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Analysis of why the range of char types is -128~+127

in C, the range of signed char types is -128~127, which is written in every textbook, but no book (including the teacher) will give you a -128~127, and the question seems simple and easy enough not to think about why, Is there a formula for an

Analysis of why the range of char types is: 128~+127

in C, the range of signed char types is -128~127, which is written in every textbook, but no book (including the teacher) will give you a -128~127, and the question seems simple and easy enough not to think about why, Is there a formula for an

Why is the numeric type byte value range ( -128~127)?

Before we solve this problem, we should understand a few concepts.First, the concept of the original code, the inverse code, the complement  The inverse code and the complement of positive numbers are the same as the original code;Negative inverse

The method for comparing floating-point numbers with 0 equals that of 0.

The method for comparing floating-point numbers with 0 equals that of 0. Check whether the floating point number is 0 in C #. Do not use "=" or "! = "For comparison, is there no way to do this when the value is 0? The following two judgment ideas

Why does the char number in the computer represent-128----127?

Why is the range of 8-Bit Signed numbers "-128-+ 127 "? (Reposted and supplemented) 11:22:57 | category:It | Tag:| Large font size, medium/small subscription This is a problem that has puzzled me for several years. It has left me extremely

The 8-Bit Signed value range is-128 ~ + 127

This is a problem that has puzzled me for several years. It has left me extremely dissatisfied with the current textbooks and teachers. Since I started to touch my computer N years ago, in almost every C ++ textbook, the 8-Bit Signed value range is-1

On the derivation of the range of unsigned char for -128~127

For char type data, it is generally divided into unsigned and signed two types, here to illustrate the scope of the problemThe first is the unsigned char, which is simple,0000 0000 ~ 1111 1111 range 0 ~ 255What about the signed char??First clear a

Why is the eight-bit binary number in the range (-128 ~~ + 127) Understanding,-128127

Why is the eight-bit binary number in the range (-128 ~~ + 127) Understanding,-128127 There are three methods for a computer to express the number of symbols: the original code, the reverse code, and the complement code. 8-digitOriginal and

Eight-bit binary number why is the range ( -128~~+127) understood

There are three methods for the representation of the signed number of the computer: the original code, the inverse code and the complement 8-bit original code and the inverse code can represent the number range is -127~127 8-bit complement can

On the complement 0 extension and the complement sign bit extension in Java

Today, Wei a problem, the title is as follows:Define a byte[]a={-1,-2,-3,-4} of a large head order and convert it to short[]b. Q b[0] and b[1] What are the differences?At first glance, the problem is not difficult, but the shift operation, and then

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