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problem:https://leetcode.com/problems/gas-station/There was N gas stations along a circular route, where the amount of gas at Station I was gas[i] .You had a car with an unlimited gas tank and it costs of gas to travel from station cost[i] I to its next station (i+ 1). You begin the journey with a empty tank at one of the gas stations.Return The starting gas station's index If you can travel around the circuit once, otherwise return-1.Note:The solution is guaranteed to be unique.Code C + +:class

There was N gas stations along a circular route, where the amount of gas at Station I was gas[i] .You had a car with an unlimited gas tank and it costs of gas to travel from station cost[i] I to its next station (i+ 1). You begin the journey with a empty tank at one of the gas stations.Return The starting gas station's index If you can travel around the circuit once, otherwise return-1.Note:The solution is guaranteed to be unique.Ideas:1. Can I travel around? = as long as gas[] plus total and-co

fulfilled, and the traversal is started directly from j+1 as a new node.When I to n satisfies the condition, it is necessary to determine whether the remaining oil amount of I to J is sufficient for 0 to i-1 distance.The code is as follows: Public intCancompletecircuit (int[] Gas,int[] cost) { intleft = 0;//Petrol remaining quantityintPass = 0;//gasoline shortage from 0->i-1intStart = 0; for(inti=0; i) { left= Gas[i]-Cost[i] +Left ; if(Left ) {Pass= left +Pass; Start= i + 1; Left= 0; }

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accepted:39396 Total submissions:153479There was N gas stations along a circular route, where the amount of gas at station I was gas[i].You had a car with an unlimited gas tank and it costs cost[i] of the gas-to-travel from station I to its next station (I+1). You begin the journey with a empty tank at one of the gas stations.Return The starting gas station's index If you can travel around the circuit once, otherwise return-1.Note:The solution is guaranteed to be unique.Problem Solving Ideas:Bec

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