192 168 2 27

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Phpinfo () 's Little Secret (a fat man with two cigarettes in his mouth!):-) ) _php

Access by browser Http://192.168.16.1/phpinfo.php?=PHPE9568F36-D428-11d2-A769-00AA001ACF42 You will see! A fat man with two cigarettes in his mouth!:-) The secret is the image data defined in the Logos.h with an array. unsigned char php_egg_logo[] =

Phpinfo () The Little Secret (of a fat man with two cigarettes in his mouth!):-) )

Access by browser Http://192.168.16.1/phpinfo.php?=PHPE9568F36-D428-11d2-A769-00AA001ACF42 You will see! A fat man with two cigarettes in his mouth!:-) Secret in logos.h the image data defined in the array. unsigned char php_egg_logo[] = { 71, 73, 70

Subnet Mask and IP address calculation network address and broadcast address conversion

Subnet Mask and IP address calculation network address and broadcast address conversion IP Address: 202.112.14.20.Subnet Mask: Too Many Subnet MaskWhat is the network address and broadcast address of this host?Solution:Step 1: Determine the

Linux deployment project process

Linux deployment project full process remote login ssh-p5108root @ 52. **. 173.202 Theauthenticityofhost & amp; #39; [52.215.173.202]: 5108 ([52.215.173.202]: 5108) & amp; #39; can & amp; #39; tbeestablished. remote logon to ssh-p 5108 root @ 52. **.

The soul of programming: Talking to 27 programmers

The soul of programming: Talking to 27 programmers Basic Information By Federico biancuzzi Shane warden Translator: Yan huaizhi Press: Electronic Industry Press ISBN:9787121104985 Mounting time: Published on: February 1, May 2010 Start: 16

POJ3177-Redundant paths.

 Reprinted please indicate the source: Thank youHttp://blog.csdn.net/lyy289065406/article/details/6762432   General question: In order to protect the grazing environment and prevent livestock from biting the turf of the same place excessively, the

Usaco-2.1-holstein-pass

This kind of problem has never been encountered before. After nearly one day, it is easy to understand. This source program is exquisite: /*ID: qq104801LANG: C++TASK: holstein*/#include #include #include #include #include using namespace std;#define

Python list Learning

1. The corresponding value in the invocation list is 0-?>>>name = [‘IBM‘,‘BD‘,‘AL‘,‘TX‘]#取第一个值>>>>>>name[0]‘IBM#依此类推,第二个值>>>name[1]‘BD‘#取最后一个值>>>name[-1]‘TX‘#倒数类推>>>name[-2]‘AL‘2. list extension numbers, value>>> name.extend (range) >>> name[' IBM ',

IP segment table

IP segment table   Total IP addresses Subnet Mask C segment count /30 4 255.255.255.252 1/64 /29 8 255.255.255.248 1/32 /28 16 20171000000000000240 1/16 /27 32 255

2 The pattern of the positive power end number

2 positive Powers-2, 4, 8, 16, 32, 64, 128, 256, ...-at the end of the numbers follow an obvious rule: 2, 4, 8, 6, 2, 4, 8, 6, .... These 4 numbers are always going to loop. In addition to the last number there is a loop-actually the final m bit-a

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