3 3 v relay board

) and CE1/PRI (channel mode). To pay attention to the difference between E1 and CE1, CE1 is the E1 of the channel, that is, the original whole 2.048mbit/s line into a number of small transmission channels, so that can host multiple business flows at the same time. CE1/PRI interfaces are commonly used to connect telecommunications equipment.1) When working in E1 mode, the equivalent of a non-time slot, the data bandwidth of 2.048MBIT/S interface, its logical characteristics and synchronous serial

capability of a single board, it does not mean the overall forwarding capability of multiple boards in Distributed forwarding situations, nor does it include GSR consisting of expensive network processors. In addition, a higher-speed CPU is now available, but it is hard to exceed 1 mpps3 ). The high price of the network processor lies in its complexity in addition to layer-3 switching. It also has strong Q

Millet Router 3 day line position how to adjust Millet Router 3-Day Placement Tutorial: First, let's take a look at the official parameter description of Millet Router 3: Before, the Millet Router General Manager @ Tang Mu Thomas has said, these four antennas, learn the name "Franklin Whip Antenna": by the feeder PCB

following five relay systems: 1. The physical layer is often referred to as the first layer and layer L1) repeater system ).2. data link layer (Layer 2), that is, bridge or bridge ).3. Layer 3, layer L3) relay system, that is, router ).4. A mixture of bridges and routers. The bridge router has the functions of bridges

finally by the MIT Shannon issued the " Symbolic analysis of relays and switching circuits This paper proposes that this circuit is called a network. The relay that we talked about is the device that amplifies the signal can replace the switch, the advantage is that the switch is a person to drive, but the relay can be driven by other relays, relays are also called buffers, because we can buffer for a peri

A typical LAN is to connect a core switch with a layer-3 Switch to several Branch switches (not necessarily with layer-3 switching ). We assume that the core switch name is com, and the Branch switches are par1, par2, and par3 respectively, which are connected to the core switch through the light module of port 1; assume that the vlan names are counter, market, and managing ...... Work to be done: A. Set vt

and is not prone to crosstalk.③ Siganl_2 (inner_2) is adjacent to two inner electrical layers Gnd (inner_1) and power (inner_3) and can be used to transmit high-speed signals. The two inner electrical layers can effectively shield external interference on the siganl_2 (inner_2) layer and siganl_2 (inner_2) external interference. In all aspects, solution 3 is obviously the most optimal one. At the same time, solution

To clarify the advantages of MTK in the business model, as well as Android for the future of the MTK mobile phone development will have any impact, first of all to understand the mobile phone from the design, development to production of the entire process. Let's take a look at the cell phone production process first. In the manufacturing process, the difference between cottage phone and genuine mobile phone is not very big.1. Assembling the motherboardMost of the electronic equipment manufactur

A typical LAN is to connect a core switch with a layer-3 Switch to several Branch switches (not necessarily with layer-3 switching ). We assume that the core switch name is com, and the Branch switches are par1, par2, and par3 respectively, which are connected to the core switch through the light module of port 1; assume that the vlan names are counter, market, and managing ......Work to be done:A. Set vtp

the storage bit. The function functions can be directly transplanted to other programs. After the circuit is powered on, the red LED is on. When you press the button, the green LED is on. When you press "3, 1, 5, 8,", the password is correct, the red LED is off, and the green LED is on, the relay is turned on and returns to the power-on Status 10 seconds later. If the correct key value is not pressed withi

]) { return false ; } } for(intI=3* (x/3);i3* (x/3+1); i++){ for(intj=3* (y/3);j3* (y/3+1); J + +){ if(x!=iy!=jboard[x][y]==Board