8 puzzle problem game

Title Link: http://hihocoder.com/problemset/problem/1165Surface:Puzzle game time limit:20000msSingle Point time limit:1000msMemory Limit:256MB Describe Fragrance today is in a good mood, and the flowers in the field of insects play a puzzle game.This game is like this, for an array A, fragrance Select a number

Code:# Jigsaw Puzzle fromsysimportexitfromrandomimportshuffle# game Victory def Victory (): print ("' ******666**victory* *!!!!! ****** ") # definition maindefmain (): boxs= [' ', ' 1 ', ' 2 ', ' 3 ', ' 4 ', ' 5 ', ' 6 ', ' 7 ', ' 8 ']shuffle (boxs) whiletrue:boxs_num=boxs print ("' ******%s%s%s**%s %s%s**%s%s%s****** ' %tuple (boxs_num)) ins =input (' Please

Create a custom size puzzle game using jQuery This article mainly introduces the code used by jQuery to create a puzzle game with a custom size. It is very simple and practical. Although it is only limited to digital order puzzles, it will be gradually improved in the future, but I want to share it with you. If you nee

value in the matrix to C. Knowledge Supplement: See more of one-dimensional tree arrays. Two-dimensional still see less (weak). Then the difference between two-dimensional and one-dimensional is: the general meaning of the two-dimensional to seek is the Matrix and. For C[x][y], the definition here is from the elements of the (x, y)---matrix. We can abstract each line into a single point, which in fact is an abstraction to a one-dimensional situation. In fact, one-dimensional and two-dimensional

I did nothing yesterday. I wrote a digital puzzle game in JS to entertain myself. Unfortunately, the reverse order number problem has not been solved, and sometimes it cannot be solved. Sorry. The Code is as follows: Puzzles ScriptVar currPos = 9;Function move (event ){Switch (event. keyCode ){Case 37:// Left clickIf (currPos % 3! = 0 ){Var currTd = document

Main topic:n individuals in a row, the Pai Tau fixed, the other can be changed. Each person has an integer, and a person's score is the product of the number on the left hand of all the people in front of him divided by the number on his right hand (rounded down), the minimum value of the maximum fraction in the whole column.Ideas:First of all, all sequences can be converted through the exchange of several neighboring people, and the exchange of neighboring persons will only affect the scores of

,n), the result is also 0. any singular situation (a,b,c) has a (+) b (+) c = 0. If we are faced with a non-singular situation (a,b,c), how to become a singular situation ? Suppose a -(A (+) b) (the focus of the problem ) . Example 1: (14,21,39), 14 (+) 21=27,39-27=12, so a singular situation (14,21,27) can be achieved by taking 12 objects from 39. Example 2: (55,81,121), 55 (+) 81=102,121-102=19, so take 19 items from 121 to form a singular situation

from large to small, so correct.But each time we calculate the sum of the number of factors (a[i],a[j]), we have to enumerate through the past, TLE.For example, this code:#include So I see a template: Linear handsome, and each time we can find a number of the precursor prime factor1#include 2#include 3#include 4#include string.h>5#include string>6 7 using namespacestd;8 9 #defineN 100001Ten One intP[n]; A intb[n],t=0; - - structnode the { - int

+ ''). replace (0,''). replace (/(. {5}),/g, '$1 \ r \ n '); } Document. writeln (''); Var p = 8, d = gd (), t1 = document. getElementById ("t1 "); SetTimeout ('T1. value = v () ', 10 ); Document. onkeyup = function (e ){ Var k = (e | window. event). keyCode-36, q; If (k = 1 (p % 3 Q = p + (k> 2? 1:-1) * (k % 2*2-3 ); D [p] = d [q], d [p = q] = 0; If (t1.value = v (). match (/^ 1, 2, 3 [^ \ d] * 4, 5, 6 [^ 0] * $ /)) Alert ('You WIN! '); } } Script

(inti =0; I ) to { + intL =i; - while(L Tmp[i]) the++l; *Z *= l-i +1; $i = L-1;Panax Notoginseng } - returnZ; the } + A intFactors (intN) the { + if(1= = N)return 1; - intCNT =2; $ for(intj =2; J * J ) $ { - if(N% J = =0) - { thecnt++; - if(J * J! =N)Wuyicnt++; the } - } Wu returnCNT; - } About $ intMain () { - //freopen ("Input.txt", "R", stdin); - intT; - while(cin>>t) A { +

This example describes a simple jigsaw puzzle implemented by Python plus pygame. Share to everyone for your reference. The implementation methods are as follows: ? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26-27--28 29---30 31--32 33 34 35 36 37 38-39 40 41 42 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 8

Topic Links:http://hihocoder.com/problemset/problem/1165Test instructionsSelect two numbers from N to make them the number of factors that multiply.Analysis:For a number, we decompose it into a factor of element.x= (P1^A1) * (P2^A2) *....* (Pn^an);Then the number of factors for x is (a1+1) * (a2+1) *...* (an+1);Then we can preprocess the number of factors from 1 to 100000, and thenThe input data is ordered by the number of factors, and then the first

{ + intX, last=0; theBitset5]; -scanf"%d", q); $ while(q--){ the for(intI=0; i5; i++) Ans[i].reset (); the for(intI=0; i5; i++){ thescanf"%d", x); theX ^=Last ; -Ans[i] =GetStatus (i, x); in if(i) ans[i] = ans[i-1]; the //cout the } AboutLast = ans[4].count (); theprintf"%d\n", last); the } the } + - intMain () the {Bayi //freopen ("a.in", "R", stdin); the intT; thescanf"%d", T); - while(t--){ - read (); the query (); the

// 15-puzzle problem (15 digital games) // PC/Ultraviolet IDs: 110802/10181, popularity: B, success rate: average level: 3 // verdict: accepted // submission date: 2011-06-22/Ultraviolet Run Time: 0.320 S // copyright (c) 2011, Qiu. Metaphysis # Yeah dot net // You can fool some of the people all of the time, and all of the people // some of the time, but you can not fool all of the people all of the time.

Poj3239 Solution to the n Queens Puzzle (n queen problem) Solution to NQueens Puzzle Time Limit:1000 MS Memory Limit:131072 K Total Submissions:3494 Accepted:1285 Special Judge Description The eight queens puzzle is the problem