adtran 1544

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(Shortest way Dijkstra) HDU 1544

Shortest circuitTime limit:5000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 34764 Accepted Submission (s): 15062Problem description in the annual school game, all the students who enter the finals will get a very beautiful T-shirt. But every time our staff put demonstrating clothes from the store back to the game, it was very tiring! So now they want to find the shortest route from the store to the arena, can you help them?Input inputs include multiple set

HDU 1544 Palindromes (palindrome sub-string)

even-numbered palindrome substrings and the number of odd palindrome substrings, together with the number of characters in the string, are required.The code is as follows:#include #includestring.h>Const intMax_n = the+Ten;CharStr[max_n];intMain () { while(SCANF ("%s", str)! =EOF) { intAns =0; intLen =strlen (str); intLeft , right; for(inti =1; I 1; ++i) { left= i-1; Right= i +1; while(Left >=0 Right Str[right]) ans+ +, left--, right++; } for(inti =0; I 1; ++i) {if(Str[i] = = st

Zju 2744 echo character HDU 1544

        # Include # include using namespace STD; int main () {string s; while (CIN> S) {int I, begin, end, total = S. size (), L = S. size (); for (I = 0; I = 0 & End = 0 & End View code # Include # Include Using namespace STD;Int main (){String

Screen command basic tutorial for Linux systems

need 15 SSH sessions, 15 logons, 15 windows, and so on. With screen, each system is assigned to a separate session, and I manage the different jobs on the system through screens. To open a new window, you only need to use "ctrl-a" "C". A new window is created that displays a default command prompt. For example, I can run the top command and then open a new window to do other work. Top Keep running! You can experiment, start screen and run top. (Note: I truncated multiple screens to save space.

Vro initial default password of various models

Telnet admin Admin 3Com super stack II console N/A (none) Admin Accelerated networks dsl cpe and dslam Telnet sysadm anicust ADC kentrox pacesetter router Telnet n/a secret Adtran mx2800 Telnet N/A adtran Advanced integration pc bios console N/A advance Admin Alcatel PBX 4400 port 2533 Kermit unknown thanks to Nicolas Gregoire Alcatel PBX 4400 port 2533 dhs3mt dhs3mt unknown thanks to Nicolas Gregoire Alca

[Translated from mos] In the rac database, the HC _ & lt; SID). dat file is

'instances. example: ----------- # lsof/u0n command pid user fd type device size/off node name oracle 8167 oracle 60r VREG 388, 50 1544 48967 hc_sqa2d101.dat oracle 8167 oracle 72r VREG 388, 50 1544 78760 hc_sqa2e101.dat... oracle 8563 oracle 60r VREG 388, 50 1544 48967 hc_sqa2d101.dat oracle 8563 oracle 72r VREG 388, 50 154

The process of simulating failover of ORACLE11GR2_ADG management in the standby storehouse

this new main library into a standby librarySQL> alter database convert to physical standby;Database altered.Need to restart the standby librarySQL> shutdown immediateSQL> startup mountThe most critical step to reconfigure the DG Broker on the main library is to remove the DG broker configurationSql> alter system set Dg_broker_start = FALSE; System altered. sql>!ps-ef |grep dmon Oracle 24648 24644 0 00:13 pts/3 00:00:00/bin/bash-c ps-ef |gre P dmonoracle 24650 24648 0 00:13 pts/3 00:00:00 grep

Test the kernel-based and non-SLB protocols

-equivalent load balancing13. Flexible route controlA 00.0.0.0 -- 127.255.255.255B10128.0.0.0-191.20.255C110192.0.0.0-223.20.255Classless RoutingMaster route entry with a mask of/8/16/24Classless RoutingMetric = bandwidth + DelayBandwidth = 256*107/min bandwidthDelay= 256 * Summary delay/10Ethernet0/0 is up, line protocol is upHardware is amdp2, address is cc00.4798.0000 (BIA cc00.4798.0000)Internet address is 21.1.1.1/24MTU 1500 bytes, BW 10000 kbit, dly 1000 USEC,Serial1/0 is up, line protocol

How to make good use of VoIP: Some things implemented through VoIP

accountant's explanation, because telecom service providers often use unique market terms to describe lines and interfaces, rather than using standard terms. Table 1: What connections do I have? What is their overhead? Multiple connections When you have more voice and data transfer lines on small and medium-sized sites, telecom service providers are very smart to bind them into a multi-channel connection, includes a bound network connection, DS1 (also known as T1, with a transfer rate of 1.544

ORACLE instance sharing: DB_LINK synchronization (MaterializedView, Snapshot)

$ ORACLE_SIDBitc# --------------------- 7. modify the configuration file name[Oracle @ h1 ~] $ Cd $ ORACLE_HOME/dbs[Oracle @ h1 dbs] $ ls-alTotal 56Drwxr-xr-x. 2 oracle oinstall 4096 Nov 12.Drwxr-xr-x. 76 oracle oinstall 4096 Nov 10 ..-Rw ----. 1 oracle oinstall 1544 Nov 10 hc_DBUA0.dat-Rw ----. 1 oracle oinstall 1544 Nov 12 hc_orcl.dat-Rw ----. 1 oracle oinstall 1544

Lsof application instance sharing and Oracle Data File Deletion AND RECOVERY TEST

pts/3 grep dbw ** use lsof to list all files opened by dbwr ** [root @ temp ~] # Lsof-P 5643 command PID user FD type device size/off node nameoracle 5643 Oracle CWD dir 4096 1556206 5643/u01/APP/Oracle/product/10.2.0/db_1/dbsoracle Oracle RTD dir 8, 2 4096 2/Oracle 5643 Oracle TXT Reg 8, 2 93362427 1557452/u01/APP/Oracle/product/10.2.0/db_1/bin/oracleoracle 5643 Oracle mem Reg 8, 2 70077 1565448/u01/APP /Oracle/product/10.2.0/db_1/lib/libclsra10.sooracle 5643 Oracle mem Reg 50848 389032/lib/li

In-depth analysis of the IGRP Routing Protocol

calculating the measurement value of a link, it is only used as a static value and does not need to reflect the actual Bandwidth used by the link, that is to say, bandwidth does not need to be measured dynamically. For example, the default bandwidth of a serial interface is 1544 Kbit/s, regardless of whether the link connected to the serial interface is T1 or 56K. The default bandwidth value can be changed using the bandwidth command. The update pack

An example of ORA-01031: insufficientprivileges Processing

2013 ICMVFQ04_01.dbf -Rw-r ----- 1 oracle dba 2560 Dec 14 2012 spfilezjport. ora -Rw ---- 1 oracle dba 24 May 28 2012 lkZJPORTUTF8 -Rw ---- 1 oracle dba 24 May 28 2012 lkZJPORTUT -Rw ---- 1 oracle dba 1544 May 28 2012 hc_zjportutf8.dat -Rw-r ----- 1 oracle dba 1536 Jan 5 orapwzjportutf8 -Rw-r ----- 1 oracle dba 1536 Jan 5 orapwzjport -Rw-r ----- 1 oracle dba 268443648 Aug 20 cuteinfo_data.dbf -Rw-r ----- 1 oracle dba 2560 May 27 2001 spfilezjportutf8

EIGRP Basic Experiment 1

EIGRP metric value is explored below.R2#show IP Route eigrp1.0.0.0/24 is subnetted, 1 subnetsD 1.1.1.0 [90/2297856] via 12.1.1.1, 00:15:13, serial0/03.0.0.0/24 is subnetted, 1 subnetsD 3.3.3.0 [90/2809856] via 12.1.1.1, 00:14:06, serial0/013.0.0.0/24 is subnetted, 1 subnetsD 13.1.1.0 [90/2681856] via 12.1.1.1, 00:15:13, serial0/0R2#show Interface s0/0Serial0/0 is up, line protocol are upHardware is M4TInternet address is 12.1.1.2/24MTU bytes, BW 1544

"Linux" unzip command, remember the problem encountered

Recently in the Boss System Cloud Platform deployment script, the tune-up found a problem in the shell script, the following recordsA place to indicate whether to overwrite[[email protected]test]# unzip/home/redis/test/main-d-1544-160316.zip-d/home/redis/test/staribossarchive:/home/redis/test/Main-d-1544-160316.zipreplace/home/redis/test/stariboss/dbpasswordencryption.bat? [Y]es, [N]o, [A]ll, [N]one, [r]ena

which PHP God help to write a coin conversion function

100 coppers = 1 silver 100 silver = 1 Gold Want to write a money that's based on how many coppers return the corresponding levelFor example, 102135铜币 the argument is that the return10金21银35铜For example, 1544铜币 the argument is that the return15银44铜etc... PHP Foundation is not solid don't know how to write the most streamlined Reply content: 100 coppers = 1 silver 100 silver = 1 Gold Want to write a money that's based on how many coppers return the

An example of ORA-01031: insufficient privileges Processing

Fault symptom:[Oracle @ L-DB-100-17 ~] $ Sqlplus/as sysdba SQL * Plus: Release 10.2.0.4.0-Production on Saturday January 5 14:59:15 2002 Copyright (c) 1982,200 7, Oracle. all Rights Reserved. ERROR: ORA-01031: insufficient privilegesEnter user-name: ERROR: ORA-01017: invalid username/password; logon deniedProcessing: update the password file[Oracle @ L-DB-100-17 ~] $ Cd/u01/product/10.2.0/db_1/dbs/[oracle @ L-DB-100-17 dbs] $ ls-lttotal 370172-rw-r ----- 1 oracle dba 10493952 Jan 6 2013 ICMLSNDX

How to manually create data for Oracle10g (Linux)

previous step. In the database status, enter the following command to createSpfile SQL>Create spfile from pfile; File Created. SQL>!//ExitSQL [Ora10 @ localhost DBS] $ LL Total60 -Rwxr -- r -- 1 ora10 DBA 88 07-18 chongshi. env -RW ---- 1 ora10 DBA 1544 07-17 hc_ora10.dat -RW-r -- 1 ora10 DBA 19 07-17 23:33Initchongshi. ora -RW-r ----- 1 ora10 DBA 12920 initdw. ora -RW-r ----- 1 ora10 DBA 8385 init. ora -RW ---- 1 ora10 DBA 24 06-

Linux disk cannot free space after deleting files

Pre-launch environment testers found that the disk space is covered, so use df-h and Du-sh * found large files, and delete.But did not free up space, df-h or display occupancy rate is 100%, at this time du-sh * Display occupies only 7G, and Df-h looked at the content does not match.In Linux or Unix systems, deleting files via RM or the File Manager removes the link from the file system's directory structure. However, if the file is consumed by the program, it cannot really clean up the disk spac

Analyze what drop col in Oracle does for a data storage block

8191 dba:0x00000000------------------------------------------------------------------------2c000302 c12f0353 59530749 5f555345 52312c00 0302c115 03535953 0549434f4c240206 7576Bbedgt; P *kdbr[288]ROWDATA[0]----------Ub1 Rowdata[0] @1541 0x2cBbedgt; X/RNCCRowdata[0] @1541----------FLAG@1541:0X2C (KDRHFL, Kdrhff, KDRHFH)lock@1542:0x00Cols@1543:3Col 0[3] @1544:290Col 1[3] @1548:sysCol 2[10] @1552:i_job_nextBbedgt; Set Count 32COUNT 32Bbedgt; DFile:/usr/l

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