alice chatbot

2803 Alice Magteroydtime limit: 4 sspace limit: 8000 KBtitle level: Golden Gold SolvingView Run ResultsTitle DescriptionDescriptionIn Gensokyo, Alice Magteroyd is a magical man who lives in magical forests and specializes inSummon a puppet. One day, her "engine oil", she found her, to defend the fog rain Marisa to Bavalou DemonThe "destruction" of the law library.She has a magic value of N, each summoning a

From http://blog.csdn.net/shuangde800 Source: UV HDU Question A tree with N nodes numbered 0 ~ N-1, vertex is 0Each edge has a weight.Alice and Bob start at the vertex and go down to the leaf node.For the first time, Bob chooses the child node to go to, and for the second time, Alice takes turns...Each time you walk through an edge, you will get the corresponding weight. Bob wants the larger the total weight of the path, the better, and

Sha 1500-Alice and Bob (reasoning) Question connection: Ultraviolet A 1500-Alice and Bob In another sequence on the blackboard, you can choose one number minus one for each operation, or merge two numbers. If one number is reduced to one, it is automatically eliminated and cannot be lost by the operator. Solution: the conclusion is that the number greater than 1 can be regarded as an integer s. To eliminate

#include #includeusing namespacestd;intgcdintAintb) { returnB?GCD (b,a%b): A;}intn[ -+Ten];intMain () {intT,MAXN =0; scanf ("%d",t); for(intI=0; i) {scanf ("%d",N[i]); MAXN=Max (maxn,n[i]); } intHigh=MAXN; for(intI=0; i1; i++) { for(intj=i+1; j) { intTEM =gcd (N[i],n[j]); MAXN=gcd (Maxn,tem); } } intMovestep = HIGH/MAXN-T; if(movestep1) {printf ("alice\n"); } Else{printf ("bob\n"); } return 0;}A set of

Test instructions: To a tree of names, the output by the layer, the same layer by the name of the dictionary sequence output.Idea: First of all to index each person's name, determine which layer, according to the layer loaded into a set, and then the output of the layer automatically ordered.1#include 2 using namespacestd;3vectorSetstring> > Ord;//one set per layer, automatically sorted by dictionary order4mapstring,int> mapp;//used for hashing5 6 intMain ()7 {8 //freopen ("Input.txt", "R",

For professional later design, the choice of material is very important, to meet your theme, matching your shape, an element of composition to the picture size, color, and placement of the position, elements And the impact of the elements, should be matched properly. Original: Creative Ideas: The idea comes from the movie "Alice in Wonderland" with the same name. The protagonist of the story is an ordinary girl, from the moment she can

ACdream 1112 Alice and Bob (game prime number screening optimization) Question link: Portal Game rules: Once again, you can divide a heap into two heap x = a * B (! = 1 B! = 1) x indicates the number of original heaps, and a and B indicate the number of new heaps. You can also change the number of the original heap to the approximate number y and y of the original heap! = X. The person who made the last operation wins. Analysis: It is also a stone-r

Topic Link: PortalGame rules:No time can be divided into two piles x = A*b (a!=1b!=1) x is the number of the original heap, A, B is the number of the new heap.It is also possible to change the number of the original heap to the approximate y of the original heap. Y!=x. The person who made the last operation wins.Analysis:It's also a stone-going game, so we just need to make the whole SG value different or better.Let's consider a bunch of them first. Set the number of this heap is x;So the whole

Alice ' s mooncake shopTime Limit:20 SecMemory limit:256 MBTopic Connectionhttp://acm.hdu.edu.cn/showproblem.php?pid=4122Description the Mid-Autumn Festival, also known as the Moon Festival or Zhongqiu Festival is a popular harvest Festival CE Lebrated by Chinese people, dating back over 3,000 years to moon worship in China ' s Shang dynasty. The Zhongqiu Festival is held on the 15th day of the eighth month in the Chinese calendar, which are in Septem

Alice ' s Print ServiceTime limit:2000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 1855 Accepted Submission (s): 454Problem Descriptionalice is providing print service, while the pricing doesn ' t seem to be reasonable, so people using her Print Service found some tricks to save money.For example, the price was printing less than pages are cents per page, but when printing wasn't less than pages, You just need-p

Hdu_3660 First, if the path cannot be set to within L or R after the next step reaches a node, then this step cannot be taken. As for how to find these nodes that cannot be taken, you can start from the leaf node. If the path is not within L or R, mark the leaf as-1, it indicates that the node cannot come. For other nodes, if all their children are marked as-1, it should also be marked as-1. In this way, we only need to go along the non-1 point. How can we calculate the maximum possible valu

| | tmpans) theAns =tmp; the } the } - } the the if(ans = =-1) the returnINF;94 returnans; the } the } the 98 classInputreader { About PublicBufferedReader Reader; - PublicStringTokenizer Tokenizer;101 102 PublicInputreader (InputStream stream) {103Reader =NewBufferedReader (NewInputStreamReader (stream), 32768);104Tokenizer =NULL; the }106 107 PublicString Next () {108 while(to

Topic Link: PortalGame rules:No time can be divided into two piles x = A*b (a!=1b!=1) x is the number of the original heap, A, B is the number of the new heap.You can also change the number of the original heap to the approximate y,y!=x of the original heap. The person who made the last operation wins.Analysis:It's also a stone-going game, so we just need to make the SG value of all the cases different or better.Let's consider a bunch of them first. Set the number of this heap is x;So all the th

Idea: Game The latter will try to select a small part after cutting, so the first hand must try to take the middle to cut. [Cpp]Int main (){Int T, c = 0, n, I;_ Int64 a, B, x, y;Scanf ("% d", T );While (T --){Scanf ("% d", n );A = B = 0;For (I = 0; I {Scanf ("% I64d % I64d", x, y );While (x> 1 y> 1){X = x> 1;Y = y> 1;}If (x = 1) B + = Y-1;If (y = 1) a + = X-1;}Printf ("Case % d:", ++ c );Printf (a> B? "Alice \ n": "Bob \ n ");}Return 0;}

Question connection: Ultraviolet A 1500-Alice and Bob In another sequence on the blackboard, you can choose one number minus one for each operation, or merge two numbers. If one number is reduced to one, it is automatically eliminated and cannot be lost by the operator. Solution: the conclusion is that the number greater than 1 can be regarded as an integer S. To eliminate their total number of operation steps, including reducing 1 and merging, C is t

Question: In a directed acyclic graph, there are several toys, each of which can only move one step at a time. The toys are moved to the destination N and cannot be moved any more. Combined game SG Function Application #include Zoj 3666 Alice and Bob, SG Function

Alice's mooncake shop Time Limit: 2000/1000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)Total submission (s): 2859 accepted submission (s): 723 Problem descriptionthe Mid-Autumn Festival, also known as the Moon Festival or Zhongqiu Festival is a popular harvest festival celebrated by Chinese people, dating back over 3,000 years to moon worship in China's Shang Dynasty. the Zhongqiu Festival is held on the 15th day of the eighth month in the Chinese calendar, which is in September

The Harbin field competition was not completed... My code and ideas refer to this blog: Http://www.cppblog.com/Yuan/archive/2010/10/03/128074.html? Opt = Admin In my opinion, this is greedy and violent .. I just started to use vector, one by one clear (), timeout. Then memset it, MLE. Google knows that the objects in C ++ STL cannot be memset. After all, there are various member variables and functions that we cannot see, which can easily cause memory leakage. Then we use the pointer to do it. W

In this Photoshop tutorial, you'll learn how to make a picture of the "Alice in Wonderland" theme by using smart filters and mixed materials. This tutorial will show you how to mix materials, create light effects, change the atmosphere of the image, draw hair, eyes, makeup and handle the skin, and how to add depth of the scene manually. This tutorial is written by Monika Nowakowska, an artist from Poland, dedicated to PSD Valut. The following is a p

Provides various official and user-released code examples. For code reference, you are welcome to exchange and learn the Hahahaha and xiaohuang interface. You can enjoy yourself... The php code is as follows: $ Msg = $ _ GET ['text'];// URL