alice in wonderland series

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PS Synthetic production of Alice in Wonderland Dream Scene effect tutorial

For professional later design, the choice of material is very important, to meet your theme, matching your shape, an element of composition to the picture size, color, and placement of the position, elements And the impact of the elements, should be matched properly. Original: Creative Ideas: The idea comes from the movie "Alice in Wonderland" with the same name. The protagonist of the story

Create a Dream "Alice in Wonderland" theme photo with PS

In this Photoshop tutorial, you'll learn how to make a picture of the "Alice in Wonderland" theme by using smart filters and mixed materials. This tutorial will show you how to mix materials, create light effects, change the atmosphere of the image, draw hair, eyes, makeup and handle the skin, and how to add depth of the scene manually. This tutorial is written by Monika Nowakowska, an artist from Poland,

Acdream 1684 Nana sleepwalking Wonderland Series--inexplicable episode (GCD)

sequence is n elements, because each operation adds a number, so the work went x-n step, Odd steps for the initiator to win.Summary, this problem needs to be required is GCD,BIG/GCD minus N, and then sentenced to parity results.  1 /*2 * This code was made by xcw07543 * problem:16844 * verdict:accepted5 * Submission date:2015-07-19 23:45:136 * time:0ms7 * MEMORY:1680KB8 */9#include Ten using namespacestd; One Const intn=1050; A intA[n]; - - intCalintN) the { -Sort (a,a+n); - inttmp=a[0];

F-Nana in Wonderland Series--multi-ethnic kingdom

F-Nana in Wonderland Series--multi-ethnic KingdomTime Limit:2000/1000ms (java/others) Memory Limit: 128000/64000kb (java/others) Submit Statusproblem DescriptionNana finally recalled that she was Nana and not what Alice, also recalled to continue to explore the world's goals, then sneak out of the palace. Nana found that there are many nationalities in this kingd

F-Nana in Wonderland Series--multi-ethnic kingdom

F - Nana in Wonderland Series--multi-ethnic Kingdom Time Limit: 2000/1000ms (java/others) Memory Limit: 128000/64000kb (java/others) Problem DescriptionNana finally recalled that she was Nana and not what Alice, also recalled to continue to explore the world's goals, then sneak out of the palace. Nana found that there are many nationalities in this kingdom, ea

D-Nana in Wonderland Series--The villagers ' quirks

D-Nana in Wonderland Series--The villagers ' quirksTime Limit:2000/1000ms (java/others) Memory Limit: 128000/64000kb (java/others) Submit Statusproblem DescriptionNana laborious Dickens finally put the candy Eat finished (agreed to eat not finish? Lie, Mouth heng ~), so, Edge Brook Line, forget road of distance. Suddenly every peach blossom forest, clip shore Hundreds of steps, no miscellaneous tree, grass

Acdream Hut Freshman Training tournament E-Nana Sleepwalking Wonderland Series--inexplicable episode number theory

Problem-solving ideas: In fact, is to find the largest collection of energy composition. Max (A[1],a[2],a[3].........a[n])/gcd (a[1],a[2],a[3],...... a[n])Problem Solving Code:1 //File name:e.cpp2 //Author:darkdream3 //Created time:2015 April 13 Monday 13:56 11 seconds4 5#include 6#include 7#include 8#include Set>9#include Ten#include One#include A#include -#include -#include the#include -#include -#include -#include +#include -#include +#include A#include at#include - #defineLL Lo

B-Nana in Wonderland Series-long jump Queen

B-Nana in Wonderland Series-long jump QueenTime Limit:2000/1000ms (java/others) Memory Limit: 128000/64000kb (java/others) Problem DescriptionNana thought the piano is very uninteresting, abandoned the piano, continue to walk, Front is a lake, Nana thought of the other side of the lake, but Nana looked for a long time did not find the small bridge and boat, Nana also found that they are not immortal, not li

A-Nana in Wonderland series-Spooky piano

A-Nana in Wonderland Series-Spooky pianoTime Limit:2000/1000ms (java/others) Memory Limit: 128000/64000kb (java/others) Submit Statusproblem DescriptionOnce upon a time, there was a Acdream kingdom, a princess lived in the kingdom, her name is Nana, Nana Princess had a very long dream one day ~ She said she had never met these wonderful things ~Now standing in front of Nana is a piano, which is a seemingly

C-Nana in Wonderland Series--Endless sweets

C - Nana in Wonderland Series--Endless sweets Time Limit: 2000/1000ms (java/others) Memory Limit: 128000/64000kb (java/others) Problem DescriptionNana finally in your help "jump" over this lake, sure enough be okay, after the war will have a reply, survived, there will be crippled! Now in front of Nana is a lot of candy and some heibuliuqiu things! But Nana's eyes only eat the candy that never ends! Nana

B-Nana in Wonderland Series-long jump Queen

B - Nana in Wonderland Series-long jump queen Time Limit: 2000/1000ms (java/others) Memory Limit: 128000/64000kb (java/others) Problem DescriptionNana thought the piano is very uninteresting, abandoned the piano, continue to walk, Front is a lake, Nana thought of the other side of the lake, but Nana looked for a long time did not find the small bridge and boat, Nana also found that they are not immortal,

Acdream Hut Freshman Training tournament F-Nana in Wonderland Series-multi-ethnic kingdoms and collection

Problem-solving ideas: And check the water problems, many years ago with violent water.Problem Solving Code:1 //File name:c.c2 //Author:darkdream3 //Created time:2013 March 01 Friday 00:37 28 seconds4 5#include 6#include string.h>7#include 8#include 9#include Ten One BOOLa[102][102] = {0}; A intf[102]; - intb[102] = {0}; - intMain () { the - //freopen ("Input.txt", "R", stdin); - //freopen ("Output.txt", "w", stdout); - intN, m, p =0; +scanf"%d%d",n,m); - for(inti =1; I ) + { A

Acdream Hut Freshman Training tournament B-Nana Sleepwalking Wonderland series-long jump Queen BFs

][j]); the printf ("******\n"); - }*/ $ while(!qu.empty ()) the { theQunode tmp =Qu.front (); the //printf ("%d\n", tmp.num); the Qu.pop (); -Mians = min (mians,yd-p[tmp.num].y); in the if(Tmp.num = = n+1) the { AboutOK =1; the returnTmp.step; the } the for(inti =0; i ) + { - if(!Vis[mp[tmp.num][i]]) the {Bayi //printf ("%d to%d\n", Tmp.num,mp[tmp.num][i]); theVis[mp[tmp.num][i]] =1; t

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