android get file path from content uri

Privatestring Getrealpath (Uri fileUrl) {string FileName=NULL; Uri Filepathuri=FileUrl; if(FileUrl! =NULL ) { if(Fileurl.getscheme (). toString (). CompareTo ("content") = = 0)//content://URI starting with{cursor cursor= This. Getcontentresolver (). Query (FILEURL

/** * Get file path by Uri * * @param imageuri * @return Path * * Private String GetPath (Uri Imageuri) { if (Imageuri = = null) return null; if (Android.os.Build.VERSION.SDK_INT >= Android.os.Build.VERSION_CODES.

/** * Gets the absolute path of the picture according to the URI * * @param Context Context Object * @param URI of the image of the URL * @return if the URI corresponding to the picture exists, then return The absolute path of the picture, otherwise returns NULL */public sta

The URI address of an Android file is generally as follows:content://media/external/images/media/62026This is the URI of a picture, so how do we get its path in the file system based on

This article is an example of the Android implementation of the URI to get the real path into file method. Share to everyone for your reference. The implementation methods are as follows: Uri

Protected string Getabsoluteimagepath (Uri uri) { //can post image String [] proj={ MediaStore.Images.Media.DATA}; cursor cursor = managedquery (URI, proj, //which columns to return NULL, //WHERE clause; which rows to r Eturn (all rows) null,

First of all, the files in the Webroot directory are all available through the browser input path, directly read to theFor example, this:The webroot below Web-inf cannot be read directly by the browser input path.Because it's protected.If the JSP reads a picture.JSP under the webroot/jspPicture under the Webroot/imagThen we have to. /imag/xx.jpg gets the relative path.Because the servlet program is unable to read an absolute

Sometimes the path will be obtained from other file browsers. When the path is used to retrieve files from the database, it will be unsuccessful because there are too many file browsers in Android and the paths returned are inconsistent, the

Ext.: http://blog.csdn.net/q445697127/article/details/40537945 /*** Get image absolute path according to URI, resolve Android4.4 above version URI conversion *@paramactivity *@paramImageuri *@authoryaoxing * @date 2014-10-12*/@TargetApi (19) Public StaticString Getimageabsolutepath (Activity context,

The content resource ID is the unified identifier of the data in the provided device. Content resource identifiers include the complete provider's name (its permissions) and the name (a path) pointing to the table or file ). The optional ID part points to an independent row in the table. Each data access method of the

and later get the path based on the Uri: Public class GetPathFromUri4kitkat {/*** it is designed for Android4.4 to obtain the absolute path of the file from the Uri. The previous method is hard to make */@ SuppressLint ("NewApi

://com.android.providers.media.documents/document/image%2706I printed it out and I blew it. Looking at the P6 system, sure enough, 4.4 of the.This is to say, and then turned over the API, found that 4.4 after the URI is not unique, not a unified format, so it's a common approach.4.4 Get path by URI before:Data is

HTTP scheme. Code Method 1: // Gets the uri of the subscribed XAML file of the specified XAML content to be rendered. VaR strfullurl = Application. Current. Host. Source. absoluteuri; If (Strfullurl. indexof ( " Clientbin " ) > 0 ){VaR uristr = Strfullurl. substring ( 0 , Strfullurl. indexof ( " Clientbin "

: // media/external/images/media /"33 + index );34 Log. d (TAG, "uri_temp is" + uri_temp );35 if (uri_temp! = Null ){36 uri = uri_temp;37}38}39}40}41 // TYLT: add by duanyf 20121027 end 3. Directly delete the image using the delete () method of ContentProvider Based on the path. The two lines of code are done with the highest efficiency. 1 String params [] = new String [] {filepath };2 ctx. getContentResolv

* "File name:" + f.getname ()* "File is present:" + f.exists ()* "Relative path of File:" + F.getpath ()* "Absolute path of File:" + F.getabsolutepath ()* "file can read:" + f.canread (

stringbufferstring Requesturl = Request.getrequesturl (). toString ();//full path What is the kind of string FullPath = Requesturl + "?" + queryString; SYSTEM.OUT.PRINTLN ("parameter section:" + queryString); System.out.println ("Request URI:" + requesturi); SYSTEM.OUT.PRINTLN ("Request URL:" + requesturl); SYSTEM.OUT.PRINTLN ("Full path:" + FullPath);} @Overrid

There are various ways to get path or Uri,url in a Web application, assuming a Web page access address:Http://localhost:8080/tradeload/TestServletWeb Application Context:/tradeloadEach path is identified as follows:Java code Request.getcontextpath () =/tradeload Request.getscheme () + "://" + request.getservernam

There are various ways to get path or Uri,url in a Web application, assuming a Web page access address:Http://localhost:8080/tradeload/TestServletWeb Application Context:/tradeloadEach path is identified as follows:Request.getcontextpath () =/tradeloadRequest.getscheme () + "://" + request.getservername () + ":" + requ

Today, when writing code, you encounter a problem: How do I get "/images/job_logo.gif" from the string "Http://job.cnblogs.com/images/job_logo.gif"? The solution to this problem requires: 1. Only the APIs in the. NET class library can be invoked; 2. In the simplest way to achieve. At first I thought of System.IO.Path, and the code was as follows: Path.getdirectoryname (URL) + "\" + path.getfilename (URL);