apptio planning

I. optimization of multi-stage decision-making process -- Basic model of dynamic planning In real life, there is a kind of activity process. Due to its particularity, the process can be divided into several interrelated stages, and decision-making is required at each stage of the process, so that the entire process can achieve the best activity effect.Result. Therefore, the decision-making in each stage cannot be determined arbitrarily. It depends on

1 longest common sub-sequence lengthdef LCS (X,y,m,n): c = [[0]* (N+1)]* (m+1) print (Len (c), Len (C[0])) for I in range (m): for J in Range (N): C4/>if X[i]==y[j]: c[i+1][j+1]=c[i][j]+1 Else: C[i+1][j+1]=max (c[i+1][j],c[i][j+1]) return c[m][ N]x = [1,3,2,5,6]y = [6,3,2,4,5,7,6]m,n = 5,7print (LCS (X,y,m,n))Distortion has shortest editing distance2 Longest ascending subsequence length def lis (x,m): if m == 0: return 0 c = [1]

Cron: Automatically executes a script file on a regular basis.-u specifies a user, without adding the current user-e Make a scheduled task-L List Scheduled Tasks-R Delete Scheduled TasksEX:CRONTAB-E (writing a scheduled Task)3 echo "OK" >/root/cron.logTime-of-Day weekly command lineEvery 8 hours, is to use all hours (0-23) to remove 8When encountering multiple numbers (minutes, hours, months, weeks), you need to separate them with commasA time period, expressed in a n-m way.View Cron service sta

60 points, greedy strategy is decided to choose left or right, the first Test, and then according to left left right right side of the right four nodes to make decisions.PS2: This problem can also be used to conduct violent search DFS in DFS in the process of the problem can not use backtracking, because all solutions are feasible solutions, we are looking for the optimal solution, the optimal solution is generally thought to use branch boundary method to prune, but this problem node value is n

design, including login registration interface, product information interface, user feedback interface and so on, it takes about 30 hours of working timeGroup Chen Zhili: Background management, including the establishment and connection of the database, the update of the quantity of goods, it takes about 20 hoursGroup One: Further market research and user demand analysis, takes about 15 hours of timeCrew Zhao Yonghen: Software Testing and maintenance takes about 8 hoursV. Daily STANDING meeting

these three cases are the optimal substructure, so the solution to dp[i][j] can be solved for the length of the "current oldest string" contained in the above three cases.3: For each dp[i][j], because each dp[i][j], need to solve dp[i-1][j-1], so you can use a matrix to record the value of each dp[i][j], the matrix is a memoThe second feature of dynamic programming is that the sub-problem is repeated, which is different from the recursive algorithm such as binary tree traversal, the node that i

Logger.info (Link.text)Link.text: Need to print contentThe Print log content format is as follows and can be positioned by file name and number of lines2018-06-14 16:03:38,866-client.py[line:47]-Debug-get http://www.baidu.com5. Get the value of the CONFIG.YML configuration variable via config.pyAs below, config.yml has config URL variableCan be obtained directly from the following codeFrom Utils.config import config #导包url = Config (). Get ('url')6. Assertion class: Assertion.pyThe content is

]Using the code user to view the contents of the file, first using the root user to write some content, will make the test more intuitive"">/test[[email protected]-study ~]$ vim/test "/test [Permission Denied] // you can see at the bottom of the tip that is not allowed to access, and do not see any contentRemove ACL permissions[Email protected] ~]# setfacl-x u:code/test//cancel/test permissions on user code[[Email protected]-study ~]# setfacl-x M/test//Restore Effective P

in the same format as the system-level Task Scheduler global file/etc/crontab, except that the 6th column execution user is not specified, as described in the previous section. Enter the following and save the exit.#该例子只用开测试*/5 * * * * echo "now is: ' Date '" >>/tmp/usercron.logEach task row, you can enter multiple tasks. The content entered in this command is automatically saved to the/var/spool/cron/zeng file.[Email protected] ~]# Cat/var/spool/cron/zeng*/5 * * * * echo "now is: ' Date '" >>/

" ACL setting parameters;-K: Remove the "preset" ACL parameter, which is described in the following example for the so-called "preset" parameter;-r: Recursive settingACLs, which include the sub-directories, are set up;-D: Sets the meaning of "preset ACL parameters"! Only the directory is valid, and the new data in that directory will reference this default "How do I set special permissions for ACLs?" Special permissions are set in many ways, let's talk about the most common, is for a single user

Title: LeetcodeJump Game IIGiven an array of non-negative integers, you is initially positioned at the first index of the array.Each element of the array represents your maximum jump length is at that position.Your goal is to reach the last index in the minimum number of jumps.For example:Given array A =[2,3,1,1,4]The minimum number of jumps to reach the last index is 2 . (Jump 1 Step from index 0 to 1 and then steps to the last 3 index.)Analysis:Should consider unable to reach the end of the si

cronCron service every minute not only to read all the files within/var/spool/cron, but also to read a/etc/crontab, so we configure this file can also use the Cron service to do something. The crontab configuration is for a user, while the edit/etc/crontab is a task for the system. The file format for this file is:Shell=/bin/bashPath=/sbin:/bin:/usr/sbin:/usr/binMailto=root//If an error occurs, or if there is data output, the data is sent to this account as an emailhome=///user-run path, here i

#include#include#include#includeSet>#include#includeusing namespaceStd;typedefLong Longll;Const intMAXN =3010; ll DP[MAXN][MAXN];intA[MAXN][MAXN];intMain () {//freopen ("In.txt", "R", stdin); intT; scanf ("%d", T); while(t--) { intN, M, K; scanf ("%d%d%d", n, m, k); for(inti =1; I ) for(intj =1; J ) scanf ("%d", A[i][j]); ll ans=0; for(inti =1; I ) for(intj =1; J ) { if(A[i][j] k) Dp[i][j]=0; Else {

, focusing on communication, management and planning. Of course, some companies also require the project experience to participate in the bidding negotiations, which requires the project manager to have a certain degree of business negotiation ability. Technical managers may sometimes call system analysts, and some small companies may have a technical manager across the department. The role of technical manager is mainly system analysis, structure bu

2018-09-01 23:02:46Problem solving:Problem solving:At the beginning, a glance at the past is a DP, save each number end of the length and, finally, the sum is good, as for the length of how to ask, the subject needs to use sliding window to maintain.After writing the code, it is not necessary to actually apply for a 1000-length array to save each number, and simply sum it up. public int Numsubarrayproductlessthank (int[] nums, int k) { int res = 0; int begin = 0; int cur

In the previous article, we introduced the "Building Dubbo distributed platform-platform function map", starting from today, we are for each individual system to do a detailed construction, by the way, the entire construction process is recorded, to facilitate more developers.Remind:Before building a Dubbo distributed platform, you must have a good grasp of MAVEN's skills, and the entire build process is using MAVEN technology. The time to resolve MAVEN issues in the build process is often more

1. Currently engaged in the work and position of the Java back-end engineer2. Personal work experience position more inclined to Javaweb engineer3. Basic Book Program: in-depth understanding of computer systems, data structures and algorithmic analysis Java language Description, Java core technology, Java Concurrency Programming combat, in-depth understanding of Java virtual machines3.1 English Chinese learning, Advanced mathematics, calculus4. Common development tools, JDK, IntelliJ idea, maven

In the previous article, we introduced the "Building Dubbo distributed platform-platform function map", starting from today, we are for each individual system to do a detailed construction, by the way, the entire construction process is recorded, to facilitate more developers.Remind:Before building a Dubbo distributed platform, you must have a good grasp of MAVEN's skills, and the entire build process is using MAVEN technology. The time to resolve MAVEN issues in the build process is often more

); } } } } returndis[t]inf;}intMainintargcChar*argv[]) {scanf ("%d",N); S=0; T=n*n*2+1; for(intI=1; ii) for(intj=1; jj) scanf ("%d",A[i][j]); Ins (S,1, inf,a[1][1]); INS (n*n,t,inf,0); for(intI=1; ii) { for(intj=1; jj) {ins ((I-1) *n+j, (I-1) *n+j+n*n,1,0); for(intk=0; k4; ++k) {intti=i+fx[k],tj=j+Fy[k]; if(ti1|| ti>n| | tj1|| Tj>n)Continue; Ins ((I-1) *n+j+n*n, (ti-1) *N+TJ,1, A[TI][TJ]); } } } intans=0; while(SPFA ()) {intt=Came[t]; for(intl=1; I!=s; i

I node, then the left edge is moved to the I node.2. When I node is negative, (thinking mined area!!) when you move to the right? Of course, the sub-array and the larger, then moved (the child and the larger, the sub-array expanded)int//Dynamic programming methodGet_max_sub (int a[], int len, int {int max_sum, cur_sum;int i;Max_sum = Cur_sum = A[0];lt = rt = 0;i = 0;while (++i if (Cur_sum > 0) {Cur_sum + = A[i];} else {Cur_sum = A[i];lt = i;}if (Cur_sum > Max_sum) {Max_sum = Cur_sum;RT = i;}}re