asr 1006

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CRS-1006, CRS-0215 fault case

:~ /Product/10.2.0/crs_1/bin> crs_stop ora. bo2dbp. VIPAttempting to stop 'ora. bo2dbp. VIP 'on member 'bo2dbs'Stop of 'ora. bo2dbp. VIP 'on member 'bo2dbs' succeeded.Oracle @ bo2dbp :~ /Product/10.2.0/crs_1/bin> crs_start ora. bo2dbp. VIPAttempting to start 'ora. bo2dbp. VIP 'on member 'bo2dbp'Start of 'ora. bo2dbp. VIP 'on member 'bo2dbp' failed.Attempting to start 'ora. bo2dbp. VIP 'on member 'bo2dbs'Start of 'ora. bo2dbp. VIP 'on member 'bo2dbs' succeeded. I am dizzy and drift to the bo2dbs

1006-hbase operation Combat (JAVA API status)

listArticles:1. HBase Connection Pool--htablepool after being deprecatedhttp://blog.csdn.net/u010967382/article/details/380468212. HBase Java API Introductionhttp://www.cnblogs.com/NicholasLee/archive/2012/09/13/2683432.html3. HBase Java API Operation CaseHttp://www.programcreek.com/java-api-examples/index.php?api=org.apache.hadoop.hbase.HTableDescriptorhttp://hbase.apache.org/apidocs/org/apache/hadoop/hbase/client/Admin.htmlhttp://blog.csdn.net/hadoop_/article/details/11481215 Copyright notice

Lightoj 1006 Hex-a-bonacci "Water"

and 0≤n≤10000 and the each of the others would be fit into a 32-bit integer.OutputFor each case, print the output of the given code. The given code may has an integer overflow problem in the compiler and so is careful. Sample Input Output for Sample Input 50 1 2 3 4 5 203 2 1 5 0 1 94 12 9 4 5 6 159 8 7 6 5 4 33 4 3 2 54 5 4 Case 1:216,339Case 2:79Case 3:16,636Case 4:6Case 5:54 AC Code:1#include 2#include string.h>3 #defineH 100000074 intshu[1

Pat B 1006. Output integers in a different format (15)

Let us use the letter B to denote "hundred", the letter S for "Ten", "12...N" to represent the single digit n (input Format: each test input contains 1 test cases, giving a positive integer n (Output format: one row for each test case output n in the specified format.Input Sample 1:234Output Example 1:BBSSS1234Input Sample 2:23Output Example 2:SS1231#include 2 intMain ()3 {4 intn,i;5scanf"%d",N);6 if(n>= -)7 {8 for(i=1; i -; i++)9 {Tenprintf"B"); One } An=n%

ACM/ICPC Asia Regional Dalian Online 1006 Football Games

the input.The first line contains a positive integersM, which is the number of groups.TheI-th of the nextMLines begins with a positive integerBi Representing the number of teams in theI-th Group, followed by Bi nonnegative integers representing the score of each team I n this group.Number of test Cases mb[i]Score of each team OutputFor each test case, output M lines. Output ' F ' (without quotes) if the scores in the I-th group must is false, output ' T ' (without quotes) otherwise. See samp

Dalian Online race 1006 Football games

1 //Dalian Online Race 10062 //Spit Groove: Data Compare water. The following code can be AC3 //But the positive solution seems to be: after sorting, the sum of the first I items is greater than or equal to i* (i-1)4 5#include 6 using namespacestd;7 #defineLL Long Long8typedef pairint,int>PII;9 Const DoubleINF =123456789012345.0;Ten ConstLL MOD =100000000LL; One Const intN =1e4+Ten; A #defineCLC (A, B) memset (A,b,sizeof (a)) - Const DoubleEPS = 1e-7; - voidFre () {freopen ("In.txt","R", stdin);

pat-Serie B-1006 output integers in a different format

Let's use B the letter to denote "hundred", the letter S means "Ten", 12...n to represent a non-zero digit n (234 , it should be output BBSSS1234 because it has 2 "hundred", 3 "ten", and a single digit of 4. Input Format:Each test input contains 1 test cases, giving a positive integer N (output Format:The output of each test case is one line, and n is output in the specified format . Input Sample 1:234Output Example 1:BBSSS1234Input Sample 2:23Output Example 2:SS123Analysis:Three digit

PAT 1006. Output integers in a different format (15)

Let us use the letter B to denote "hundred", the letter S for "Ten", "12...N" to represent the single digit n (input Format: each test input contains 1 test cases, giving a positive integer n (Output format: one row for each test case output n in the specified format.Input Sample 1:234Output Example 1:BBSSS1234Input Sample 2:23Output Example 2:SS123Accept integers with strings, eliminating the number of digits to judge integers#include #includestring.h>intMain () {Chara[Ten]; scanf ("%s", a); in

1006 Tick and tick

1006 Questions:Problem DescriptionThe three hands of the clock is rotating every second and meeting all other many times everyday. Finally, they get bored of this and all of the them would like to stay away from the other. A Hand is happy if it's at least D degrees from any of the rest. You is to calculate what much time in a day and all the hands is happy.InputThe input contains many test cases. Each of them have a single line with a real number D be

1006 Pass the note

-intersecting lines, then it may have four cases in the previous step:The first point from the top walk, the second point also from the top, at this time of goodwill and for F[i-1][j][k-1][l] + a[i][j] + a[k][l]The first point comes from the top, the second point is left to come, at this time the goodwill and for F[I-1][J][K][L-1] + a[i][j] + a[k][l], but at this time should consider whether the point above the first point will coincide with the point to the left of the second point, if coincide

Peking University 1006

Question link: http://acm.pku.edu.cn/JudgeOnline/problem? Id = 1006 This question mainly uses the Chinese Remainder Theorem 1. remainder problem: in integer division, a number is divided by several pairs of mutual quality numbers at the same time. After an integer operator, there are remainder numbers, it is known that each divisor and its corresponding remainder are used to obtain the divisor that meets the conditions. 2. Chinese Remainder Theorem: D

CRS-1006, CRS-0215 fault cases

'ora. bo2dbp. vip 'failed on member 'bo2dbs' CRS-1006: No more members to consider CRS-0215: cocould not start resource 'ora. bo2dbp. vip '. 7. check log Oracle @ bo2dbp :~ /Product/10.2.0/crs_1/log/bo2dbp/racg> tail-50 ora. bo2dbp. vip. log 16:18:55. 942: [RACG] [4250161648] [20571] [4250161648] [ora. bo2dbp. vip]: end for resource = ora. bo2dbp. vip, action = start, status = 1, time = 6.390 s 16:19:30. 968: [RACG] [4041843184] [20878] [4041843

Poj 1006 biorhythms number theory-(Sun Tzu's theorem)

Question address: http://poj.org/problem? Id = 1006 lang = default change = true This is the question of a deformed Sun Tzu's theorem, which is used directly by formulas. CodeAs follows: # Include

1006. team rankings

distance between these two rankings is 2. the median ranking of a set of rankings is that ranking whose sum of distances to all the given rankings is minimal. (note we cocould have more than one median ranking .) the median ranking may or may not be one of the given rankings. Suppose there are 4 voters that have given the rankings: abdce, bacde, abced and acbde. consider two candidate median rankings ABCDE and cdeab. the sum of distances from the ranking ABCDE to the four voted rankings is 1 +

[Chinese Remainder Theorem] poj 1006

Simple physiological Cycle Simulation Perform the remainder operation when the value exceeds 23*28*33 (21252. #include China Remainder TheoremIf a certain number of X is D1 ,,... The remainder of the DN division is R1, R2 ,... , RN, can be expressed as the following formula:X = r1r1 + r2r2 +... + Rnrn + RdR1 is D2, D3 ,... , DN public multiple, and division by D1, the remainder is 1;R1, R2... , RN is D1, D2 ,... , The dn-1 of the public multiple, And the DN division, the remain

Analysis of Pat computer problems in Zhejiang University 1006. Sign in and sign out (25)

1006. Sign in and sign out (25) Time Limit 400 MS The memory limit is 32000 kb. Code length limit: 16000 B Criterion author Chen, Yue At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. given the records of signing in's and out's, you are supposed to findOnes who have unlocked and locked the door on that day. Input specification: Each input file contai

Bzoj 1006: [hnoi2008] the dyeing problem of the magic National string graph & the sequence of the perfect elimination of the string Graph

1006: [hnoi2008] Time Limit: 20 sec memory limit: 162 MB Submit: 1788 solved: 775 [Submit] [Status] Description K is a country keen on triangles, and even people only like the triangle principles. they believe that the triangular relationship: AB, BC, and Ca are concise and efficient. in order to consolidate the triangular relationship, K countries prohibit the existence of four-edge relations, five-edge relations, and so on. the so-called n-edge re

HDU 5358 (2015 Multi-school joint training competition 1006) First One (range merging + constant optimization), hdu training competition

HDU 5358 (2015 Multi-school joint training competition 1006) First One (range merging + constant optimization), hdu training competition HDU 5358 Question: Calculate Σ I = 1n Σ j = in (⌊ log2S (I, j) records + 1) records (I + j ). Ideas: S (I, j) It is mainly difficult to write, some details are tangled, and some ideas are clarified before writing. Ps. The unit constant is unhuman. Remember to pre-process the interval ing. Otherwise, n (logn) ^ 2 wil

HDU 3788 and 9du OJ 1006 test data are different, hduoj

HDU 3788 and 9du OJ 1006 test data are different, hduojZOJ ProblemsTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission (s): 2935 Accepted Submission (s): 889Problem Description determines whether a given string (only contains 'Z', 'O', and 'J') can be AC.The AC rules are as follows:1. zoj can communicate with each other;2. If the string format is xzojx, it can also be AC, where x can be N 'O' or is empty;3.

1006. Sign in and sign out (25)

:25cs301133 21:45:00 21:58:40Sample Output:SC3021234 CS3011331 ImportJava.util.*;2 Public classMain {3 4 Public Static voidMain (string[] args) {5Scanner in =NewScanner (system.in);6String m=in.nextline ();7String early= "24:00:00", late= "00:00:00";8String earlyperson= "", lateperson= "";9 for(intI=0;i){TenString []line=in.nextline (). Split (""); One if(Line[1].compareto (early) ){ AEarly=line[1]; -Earlyperson=line[0]; - } the if(Line[2].compa

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