asr 1013

1013. Recognize triangles, 1013 recognize triangles1013. Identification triangle (Standard IO) Time Limit: 1000 MS space limit: 262144 KB Specific Limit Enter three positive integers in the topic description to determine whether the three sides of the triangle can be formed. If not, output "NO ". If a triangle can be formed, which triangle can be determined? Output the corresponding triangle types "Equil

++,col++) - { +Max_r=K; A for(i=k+1; i) at if(Fabs (A[i][col]) >fabs (A[max_r][col]) max_r=i; - if(Fabs (A[max_r][col]) return 0; - if(k!=max_r) - { - for(j=col;jvar; j + +) Swap (a[k][j],a[max_r][j]); - swap (X[k],x[max_r]); in } -X[k]/=A[k][col]; to for(j=col+1;jvar; j + +) a[k][j]/=A[k][col]; +a[k][col]=1; - for(i=0; i) the if(i!=k) * { $x[i]-=x[k]*A[i][k];Panax Notoginseng

The title describes the value of SN=A+AA+AAA+...+AA...AAA (with n a), where a is a number. For example: 2+22+222+2222+22222 (n=5), n is entered by the keyboard. Input a output and sample input5Sample output246901#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 intN, Sn =0, num =2;6scanf"%d", n);7 8 while(N >0)9 {TenSn + =num; Onenum = num *Ten+2; AN--; - } - theprintf"%d\n", Sn); - return 0; -}1013:c Language Programming

decimal point, and its absolute value is no more than 20000.OutputWith only one row, the n-dimensional coordinates (n real numbers) of the globe are given in turn, and two real numbers are separated by a space. Each real number is exactly 3 digits after the decimal point. Data is guaranteed to be solvable. Your answer must be the same as the standard output in order to score.Sample Input20.0 0.0-1.0 1.01.0 0.0Sample Output0.500 1.500HINTData size:For 40% of data, 1For 100% of data, 1Tip: Give t

Subtract the upper and lower two equations and then Gaussian elimination 1013: [JSOI2008] spherical space generator sphere time limit: 1 Sec Memory Limit: 162 MB Submit: 2901 Solved: 1517 [Submit] [Status] [Discuss] DescriptionThere is a spherical space generator capable of producing a hard sphere in n-dimensional space. Now that you are trapped in this n-dimensional sphere, you only know the coordinates of the n+1 p

Test instructionsTells you a k+1 point on a sphere of k-dimensional spheres asking the spherical coordinates.SolAt first glance I thought it was a k-dimensional answer and judged the distance ... What a jerk. You look at the messy topics and then forget the most useful basic calculations ...We can see that, assuming the center O, according to the formula that he tells us we can get an equation of any two points and a center point, the equation has K unknowns, then we randomly construct K equatio

Algorithmic enthusiastsHDU 1013 Digital RootsDigital RootsTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 29353 Accepted Submission (s): 8974Problem DescriptionThe digital root of a positive integer is found by summing the digits of the integer. If The resulting value is a, digit then, digit is the digital root. If The resulting value contains or more digits, those digits was summed and the process i

9-degree OJ 1013, 9-degree oj1013 Question 1013: Opening and Closing Time Limit: 1 second Memory limit: 32 MB Special question: No Submit: 4352 Solution: 2202 Description: The first person to arrive at the data center should open the door every day, and the last person to leave should close the door. There are a bunch of messy data center sign-in and sign-out records. Please fin

1013-love CalculatorYes, you're developing a ' Love Calculator '. The software would is quite complex such that nobody could crack the exact behavior of the software.So, given names your software would generate the percentage of their ' love ' according to their names. The software requires the following things: The length of the shortest string that contains the names as subsequence. Total number of unique shortest strings which contain

1013: [JSOI2008] spherical space generator sphere time limit:1 Secmemory limit:162 MB submit:5995 [Submit][status][discuss] Description There is a spherical space generator capable of producing a hard sphere in n-dimensional space. Now that you are trapped in this n-dimensional sphere, you know only the coordinates of the n+1 points on the plane of the ball, and you need to determine the spherical coordinates of the n-dimensional

1#include 2#include 3#include 4 #defineEPS 1e-65 #defineM 156 using namespacestd;7 DoubleA[m],b[m][m];8 intN;9 intMain ()Ten { Onescanf"%d",n); A for(intI=1; i) -scanf"%LF",a[i]); - for(intI=1; i) the for(intj=1; j) - { - DoubleT; -scanf"%LF",t); +b[i][j]=2* (ta[j]); -b[i][n+1]+=t*t-a[j]*A[j]; + } A for(intI=1; i) at { - intto ; - for(to=i;to) - if(b[to][i]!=0) - Break; - if(i!=to ) in

1013. Battle Over Cities (25)It is vitally important to have all the cities connected by highways in a war. if a city is occupied by the enemy, all the highways from/toward that city are closed. we must know immediately if we need to repair any other highways to keep the rest of the cities connected. given the map of cities which have all the remaining highways marked, you are supposed to tell the number of highways need to be retried red, quickly.For

Main topic:Give two number, profit and loss, the company in the annual statistics 8 times, each time the statistics 5 months, so there are overlapping parts, 8 times the result of statistics are deficit, seek profitProblem Solving Ideas:Since there is a deficit each time, so there is at least one D in 5 months, there are four cases, the number of months of profit *s-loss of the number of months *d for the requestCode:#include #includeusing namespacestd;intMain () {ints,d,sum; while(cin>>s>>d) {

- { - Doublegg=ga[j][i-1]/ga[i-1][i-1]; in for(intk=i;k1; k++)//several unknown items of the equation -ga[j][k]=gg*ga[i-1][k]-Ga[j][k]; to } + Solve (); - } the * intMain () $ {Panax Notoginsengscanf"%d",n); - for(intI=1; i1; i++) the for(intj=1; j) +scanf"%LF",f[i][j]); A for(intI=1; i) the for(intj=1; j) +Ga[i][j]= (f[i+1][J]-F[I][J]) *2, ga[i][n+1]+=f[i+1][j]*f[i+1][j]-f[i][j]*F[i][j]; - Guass (); $ for(intI=1; i) $pr