ASR now Supports NetApp Private Storage for Microsoft AzureThis week atignite in Chicago, Microsoft and NETAPP would showcase how customers can simplify disaster recovery For Hyper-V workloads without investing in a secondary datacenter. Together,we'll demohow Azure Site Recovery (ASR) can replicate and recover a san-based on-premises appl Ication to Azure Computewith NetApp Private Storage (NPS) for Micros

Cisco ASR 5000 PMIPv6 Denial of Service Vulnerability (CVE-2015-6340)Cisco ASR 5000 PMIPv6 Denial of Service Vulnerability (CVE-2015-6340)
Release date:Updated on:Affected Systems:
Cisco ASR 5000 19.0.M0.60737
Description:
CVE (CAN) ID: CVE-2015-6340The Cisco ASR 5000 series is a carrier-level platform for deploy

Release date:Updated on:
Affected Systems:Cisco ASR 9006Cisco ASR 9006Description:--------------------------------------------------------------------------------Bugtraq id: 48811Cve id: CVE-2011-2549
Cisco ASR 9000 series is an integrated service router solution that uses the Cisco ios xr Software module operating system to provide carrier-level reliability.

Cisco ASR 5000 GGSN Component Denial of Service Vulnerability (CVE-2015-4201)Cisco ASR 5000 GGSN Component Denial of Service Vulnerability (CVE-2015-4201)
Release date:Updated on:Affected Systems:
Cisco ASR 5000 18.0.L0.59219Cisco ASR 5000 17.2.0.59184
Description:
CVE (CAN) ID: CVE-2015-4201The Cisco

Cisco ASR 5000 Denial of Service Vulnerability (CVE-2015-0712)Cisco ASR 5000 Denial of Service Vulnerability (CVE-2015-0712)
Release date:Updated on:Affected Systems:
Cisco ASR 5000
Description:
Bugtraq id: 74407CVE (CAN) ID: CVE-2015-0712The Cisco ASR 5000 series is a carrier-level platform for deploying high-de

Release date:Updated on:
Affected Systems:Cisco ASR 5000Description:--------------------------------------------------------------------------------Bugtraq id: 65052CVE (CAN) ID: CVE-2014-0669
The Cisco ASR 5000 series is a carrier-level platform that can be used to deploy high-demand 3G networks and migrate to long-term evolution (LTE.
The Gateway GPRS of the Cisco

1013. Recognize triangles, 1013 recognize triangles1013. Identification triangle (Standard IO) Time Limit: 1000 MS space limit: 262144 KB Specific Limit
Enter three positive integers in the topic description to determine whether the three sides of the triangle can be formed. If not, output "NO ". If a triangle can be formed, which triangle can be determined? Output the corresponding triangle types "Equil

The title describes the value of SN=A+AA+AAA+...+AA...AAA (with n a), where a is a number. For example: 2+22+222+2222+22222 (n=5), n is entered by the keyboard. Input a output and sample input5Sample output246901#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 intN, Sn =0, num =2;6scanf"%d", n);7 8 while(N >0)9 {TenSn + =num; Onenum = num *Ten+2; AN--; - } - theprintf"%d\n", Sn); - return 0; -}1013:c Language Programming

decimal point, and its absolute value is no more than 20000.OutputWith only one row, the n-dimensional coordinates (n real numbers) of the globe are given in turn, and two real numbers are separated by a space. Each real number is exactly 3 digits after the decimal point. Data is guaranteed to be solvable. Your answer must be the same as the standard output in order to score.Sample Input20.0 0.0-1.0 1.01.0 0.0Sample Output0.500 1.500HINTData size:For 40% of data, 1For 100% of data, 1Tip: Give t

Subtract the upper and lower two equations and then Gaussian elimination
1013: [JSOI2008] spherical space generator sphere time
limit: 1 Sec
Memory Limit: 162 MB
Submit: 2901
Solved: 1517
[Submit] [Status] [Discuss]
DescriptionThere is a spherical space generator capable of producing a hard sphere in n-dimensional space. Now that you are trapped in this n-dimensional sphere, you only know the coordinates of the n+1 p

Test instructionsTells you a k+1 point on a sphere of k-dimensional spheres asking the spherical coordinates.SolAt first glance I thought it was a k-dimensional answer and judged the distance ... What a jerk. You look at the messy topics and then forget the most useful basic calculations ...We can see that, assuming the center O, according to the formula that he tells us we can get an equation of any two points and a center point, the equation has K unknowns, then we randomly construct K equatio

Algorithmic enthusiastsHDU 1013 Digital RootsDigital RootsTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 29353 Accepted Submission (s): 8974Problem DescriptionThe digital root of a positive integer is found by summing the digits of the integer. If The resulting value is a, digit then, digit is the digital root. If The resulting value contains or more digits, those digits was summed and the process i

9-degree OJ 1013, 9-degree oj1013
Question 1013: Opening and Closing
Time Limit: 1 second
Memory limit: 32 MB
Special question: No
Submit: 4352
Solution: 2202
Description:
The first person to arrive at the data center should open the door every day, and the last person to leave should close the door. There are a bunch of messy data center sign-in and sign-out records. Please fin

1013-love CalculatorYes, you're developing a ' Love Calculator '. The software would is quite complex such that nobody could crack the exact behavior of the software.So, given names your software would generate the percentage of their ' love ' according to their names. The software requires the following things:
The length of the shortest string that contains the names as subsequence.
Total number of unique shortest strings which contain

1013: [JSOI2008] spherical space generator sphere
time limit:1 Secmemory limit:162 MB submit:5995 [Submit][status][discuss]
Description
There is a spherical space generator capable of producing a hard sphere in n-dimensional space. Now that you are trapped in this n-dimensional sphere, you know only the coordinates of the n+1 points on the plane of the ball, and you need to determine the spherical coordinates of the n-dimensional

1013. Battle Over Cities (25)It is vitally important to have all the cities connected by highways in a war. if a city is occupied by the enemy, all the highways from/toward that city are closed. we must know immediately if we need to repair any other highways to keep the rest of the cities connected. given the map of cities which have all the remaining highways marked, you are supposed to tell the number of highways need to be retried red, quickly.For

Main topic:Give two number, profit and loss, the company in the annual statistics 8 times, each time the statistics 5 months, so there are overlapping parts, 8 times the result of statistics are deficit, seek profitProblem Solving Ideas:Since there is a deficit each time, so there is at least one D in 5 months, there are four cases, the number of months of profit *s-loss of the number of months *d for the requestCode:#include #includeusing namespacestd;intMain () {ints,d,sum; while(cin>>s>>d) {

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