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S (SNO, sname) Student Relationship. Sno is the student ID, and sname is the name C (CNO, cname, cteacher) Course relationship. CNO is the course number, cname is the course name, And cteacher is the course teacher SC (stu_no, cla_no, score) Course Selection relationship. Score Initialization table: Insert into S values ("001", "zhangsan"); insert into S values ("002", "padern"); insert into S values ("003 ", "wangwu"); insert into S values ("004", "X

-- 1. The following table shows the information of all students, sorted in ascending order of student numbers, and displayed in alphabetical order of course names for the same student number. -- Student ID Student name Course name score selectst. studno, st. studname, sum (decode (cc. coursename, JAVA, SC. grade, 0) JAVA, sum (decode (cc. c -- 1. The following table shows the information of all students, sorted in ascending order of student numbers, a

'); SELECT * from course; CREATE TABLE Teacher (t_id varchar (ten), Tname varchar (20)); INSERT into Teacher values (' 01 ', ' Zhang San '); INSERT INTO Teacher values(' 02 ', ' John Doe '); INSERT into Teacher values (' 03 ', ' Harry '); SELECT * from teacher; CREATE TABLE SC (s_id varchar), c_id varchar (ten), Score decimal (18,1)); INSERT into SC values (' 01 ', ' 01 ', 80); INSERT into

Label:SQL statement Exercises 50 questions Student (sid,sname,sage,ssex) Student table Course (cid,cname,tid) curriculum SC (Sid,cid,score) Table Teacher (tid,tname) Teachers table Practice content:1. Check the number of all students who have a "1" course with a higher grade than "a 2" course;Select A.sid from (select Sid,score from SC where cid=1) A, (select Sid,score from

Create a student tableCreate a score tableCreate a teacher tableCreate a grade Table--1, Query the sname, Ssex, and class columns of all records in the student table. SELECT S.sname, S.ssex, S.classFrom student S--2, query teachers all units that are not duplicated depart column. SELECT DISTINCT depart from teacher--3, querying all records of the student table. SELECT*From student--4, query all records in the score table with scores from 60 to 80. SELECT* FROM score

Most of the SQL statements in this statement come from "Introduction to Database System" (fourth edition) Wang Shan Shaman Xuan Munsu, is our class with the teaching materials, feel very good, summed up the third chapter of the SQL statement, more practical, I hope to help everyone. Summarized below, can be used to learn the underlying SQL statements.Set up a databaseCREATE DATABASE db_studentCreate a tableCREATE TABLE Student(Sno CHAR (9) PRIMARY KEY,--main codeSname CHAR,--Unique valueSsex CH

follows: # Modinfo/lib/modules/2.6.33-110. el6.x86 _ 64/kernel/drivers/net/igb. ko Filename: igb. koVersion: 2.1.0-k2License: GPLDescription: Intel (R) Gigabit Ethernet Network DriverAuthor: Intel Corporation Srcversion: 412D1CB4C85682CBF07976FAlias: pci: v20178086d201710d6sv * sd * bc * SC * I *Alias: pci: v20178086d201710a9sv * sd * bc * SC * I *Alias: pci: v20178086d201710a7sv * sd * bc *

required for the model card [8,086:1521 ] Support.05, check whether the target core network card driver supports the current model cardThe Modinfo command allows you to see *.ko support for which device model, the driver for the target core (2.6.33-110.el6.x86_64) can be/lib/modules/2.6.33-110.el6.x86_ The catalog of "want to find", as follows:#modinfo/lib/modules/2.6.33-110.el6.x86_64/kernel/drivers/net/igb/igb.ko Filename:igb.koVersion:2.1.0-k2License:gplDescription:intel (R) Gig

Question 1: Problem description: S (SNO, sname) Student Relationship. Sno is the student ID, and sname is the name C (CNO, cname, cteacher) Course relationship. CNO is the course number, cname is the course name, And cteacher is the course teacher SC (SNO, CNO, scgrade) Course Selection relationship. Scgrade is the score 1. (1) find out the names of all students who have taken the course taught by Mr. Li Ming. -- Implementation code: method 1 Select *

downloaded here, but it is used as an exercise without any foreign key Association: The compiled SQL statement is as follows: Student (S #, Sname, Sage, Ssex) Student table Course (C #, Cname, T #) Curriculum SC (S #, C #, score) Orders table Teacher (T #, Tname) Instructor table 1. Select the student ID that passes each course Select distinct's # 'from SC where's #' not in (select's # 'from

To manage job business training information, create three tables: S (S #, SN, SD, SA) S #, SN, SD, SA stands for student ID, Student name, organization, student age C (C #, CN) C #, CN stands for course number, course name SC (S #, C #, g) S #, C #, and G respectively represent the student ID, number of the selected course, and score 1. query using standard SQL nested statements To manage job business training information, create three tables: S (S #,

How does PHP match the most similar strings in a string pool? This paper mainly introduces the method of PHP query the most similarity of the string, involving PHP operation string and array to implement the similarity algorithm skills, I hope to be helpful to everyone. Returns the most similar string in the array, based on the strings and arrays passed in 1. The PHP code is as follows: function Closest_word ($input, $words) { $shortest =-1; foreach ($words as $word) { $lev = Levensh

SAMOA": "AS", "NORTH CAROLINA": "NC", "HAWAII": "HI", "NEW YORK": "NY", "CALIFORNIA": "CA", "ALABAMA": "AL", "IDAHO": "ID", "FEDERATED STATES OF MICRONESIA": "FM", "Armed Forces Americas": "AA", "DELAWARE": "DE", "ALASKA": "AK", "ILLINOIS": "IL", "Armed Forces Africa": "AE", "SOUTH DAKOTA": "SD", "CONNECTICUT": "CT", "MONTANA": "MT", "MASSACHUSETTS": "MA", "PUERTO RICO": "PR", "Armed Forces Canada": "AE", "NEW HAMPSHIRE": "NH", "MARYLAND": "MD", "NEW MEXICO": "NM

',' CD ' => ' Congo ',' CF ' => ' Central Africa ',' CG ' => ' Congo ',' CH ' => ' Switzerland ',' CI ' => ' Ivory Coast ',' CK ' => ' Cook Is. ',' CL ' => ' Chile ',' CM ' => ' Cameroon ',' CN ' => ' China ',' CO ' => ' Columbia ',' CR ' => ' Costa Rica ',' CS ' => ' Ceskoslovensko ',' CU ' => ' Cuba ',' CV ' => ' Cape Verde ',' CX ' => ' Christmas Island ',' CY ' => ' Cyprus ',' CZ ' => ' Czech ',' DE ' => ' Germany ',' DJ ' => ' Djibouti ',' DK '

", "Federated S Tates of Micronesia ": FM", "Armed Forces Americas": "AA", "DELAWARE": "DE", "ALASKA": "AK", "ILLINOIS": "IL", "Armed Forces Africa": "AE", "SOUTH DAKOTA": "SD", "Connecticut": "CT", "MONTANA": "MT", "Massachusetts": "MA", "PUERTO RICO": "PR", "Armed Forces Canada": "AE", "New HAMPSHIRE": "NH", "MARYLAND": "MD", "New MEXICO": "NM", "Mississippi": "MS", "Tennessee": "TN", "PALAU": "PW", "COLORADO": "CO", "Armed Forces Middle East": "AE", "N EW JERSEY ":"

' => ' Canada ', ' CB ' => ' Cambodia ', ' CC ' => ' Coco Islands ', ' CD ' => ' Congo ', ' CF ' => ' Central Africa ', ' CG ' => ' Congo ', ' CH ' => ' Switzerland ', ' CI ' => ' Ivory Coast ', ' CK ' => ' Cook Is. ', ' CL ' => ' Chile ', ' CM ' => ' Cameroon ', ' CN ' => ' China ', ' CO ' => ' Columbia ', ' CR ' => ' Costa Rica ', ' CS ' => ' Ceskoslovensko ', ' CU ' => ' Cuba ', ' CV ' => ' Cape Verde ', ' CX ' => ' Christmas Isla

This article illustrates the method of the most similar string in PHP query. Share to everyone for your reference. Specifically as follows: Returns the most similar string in an array, based on the passed-in string and arrays 1. PHP code is as follows: function Closest_word ($input, $words) { $shortest =-1; foreach ($words as $word) { $lev = Levenshtein ($input, $word); if ($lev = = 0) { $closest = $word; $shortest = 0; break; if ($lev 2.

and environmental Engineering and Geodetic Science, U.S.A. Royal Institute of Technology, Department of Geodesy And photogrammetry, Sweden U. of Alaska, Department of Geomatics, U.S.A. U. of Calgary, Dept. of Geomatics Engineering, Can Ada U. of Cape town, School of Architecture, Planning and Geomatics, South Africa U. College London, Department of Geomati C Engineering, U.K. U estadual Paulista, Departamento de Cartografia, Brazil (in Portuguese) U. of Florida, geomatics, U. S.A. U. of Glasgow

, int value );Set the int Type HTTP header value of the specified name.27. void setStatus (int xc );Set the response status code. The new value overwrites the current value.Member (HTTP status code ):Int SC _CONTINUE = 100 int SC _SWITCHING_PROTOCOLS = 101Int SC _ OK = 200 int SC _NON_AUTHORITATIVE_INFORMATION = 203Int

InstallMySQLThe system prompts: Cannot create windows service for mysql. error: 0. The reason is that the old mysql service exists in the system. The solution is as follows: To permanently delete the old mysql service, you must run the following command on the command line with the administrative permission:C: \> SC delete mysql[SC] DeleteService SUCCESS When installing the service, if a similar situation o