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[Reprint] SQL statement exercises 50 questions, SQL statements

[Reprint] SQL statement exercises 50 questions, SQL statements Student (Sid, Sname, Sage, Ssex) Student tableCourse (Cid, Cname, Tid) curriculum SC (Sid, Cid, score) classroom table Teacher (Tid, Tname) Instructor table exercise content: 1. query the student ID of all students whose score is higher than that of the "1" course. SELECT. sid FROM (SELECT sid, score from SC where cid = 1) a, (SELECT sid, score

MySQL multi-table query case

' course name ',Ccredit tinyint (Ten) not NULL COMMENT ' credits ',PRIMARY KEY (Cno)) Engine=innodb auto_increment=1 DEFAULT charset=latin1;CREATE TABLE SC (SCid Int (a) not NULL auto_increment COMMENT ' primary key ',Cno Int (Ten) not NULL COMMENT ' course number ',Sno Int (Ten) not NULL COMMENT ' study number ',Grade tinyint (2) not NULL COMMENT ' student score ',PRIMARY KEY (SCid)) Engine=innodb DEFAULT charset=latin1;INSERT into student values (0

Database and database Learning

only consider a limited number of possibilities.(4) The optimizer includes many complex optimization technologies that can be mastered only by the best programmers. Automatic system optimization is equivalent to making everyone have these optimization technologies. RDBMS calculates the execution cost of various query execution policies based on a certain cost model, and then selects the execution scheme with the minimum cost.Centralized databaseThe execution overhead mainly includes:Number of d

12 SQL statements for shared collation together with data _mssql

SQL layer, which is not conducive to maintenance and expansion, although it does often improve the running efficiency. The specific circumstances of their own choice. The following examples are more general SQL, in fact, for a specific database, need to learn a lot, such as the Oracle DB decode function, ROWID, rownum, connect by although not universal, but very practical. Data can be downloaded here, just as an exercise, without any foreign key associations: Http://xiazai.jb51.net/database/20

Database-query optimization of the relational database system

. Generally, programmers can only consider a limited number of possibilities.(4) The optimizer includes many complex optimization technologies that can be mastered only by the best programmers. Automatic system optimization is equivalent to making everyone have these optimization technologies. RDBMS calculates the execution cost of various query execution policies based on a certain cost model, and then selects the execution scheme with the minimum cost.Centralized databaseThe execution overhead

Some common questions in SQL Server

Question 1 Problem description: Create three tables to manage job business training information: S (s #, Sn, SD, SA) s #, Sn, SD, and SA represent the student ID, Student name, organization, and student age respectively. C (C #, CN) C #, CN represents the course number and Course name respectively. SC (s #, C #, g) s #, C #, and G represent Student IDs, elective course numbers, and academic scores respectively. 1. Use standard SQL nested statements to

Custom Control compilation failures

When creating a custom class, an error is reported during compilation in vc6. Error Message Deleting intermediate files and output files for project 'test3-Win32 Uni debug '.------------------ Configuration: TEST3-Win32 Uni Debug --------------------Building resources from Test3_caption.rssPerl-S epocrc_ide6.pl-I "\ WORK \ TEST3 \ DATA"-I "\ WORK \ TEST3 \ GROUP"-I "\ WORK \ TEST3 \ INC"-I" \ WORK \ TEST3 \ GROUP "-I" \ Symbian \ 8.0a \ S60_2nd_FP2_

Basic SQL Exercises--A classic example of elective course

Tags: blog use problem div code HTML Management logTo manage the job training information, establish 3 tables:S (S#,SN,SD,SA) S#,sn,sd,sa respectively represents the student number, the student name, the unit, the Student Age C (C#,CN) C#,CN respectively represents the course number, the course name SC (s#,c#,g) S#,c#,g respectively represents the student number, the elective course number, the study result  1. Use standard SQL nested statements to qu

SQL Statement Interview Summary

) Teacher tableProblem:1, the inquiry "001" course is higher than "002" of all students of the school number;Select a.s#From (select S#,score from SC where c#= ' 001′) A,(select S#,score from SC where c#= ' 002′) bwhere A.score>b.score and a.s#=b.s#;2, the query average score is more than 60 points of the student's number and average score;Select S#,avg (Score)From SCGROUP BY s# have AVG (score) >60;3, inqu

Common Database interview test questions (SQL Server)

Problem description: Create three tables to manage job business training information:S (s #, Sn, SD, SA) s #, Sn, SD, and SA represent the student ID, Student name, organization, and student age respectively.C (C #, CN) C #, CN represents the course number and Course name respectively.SC (s #, C #, g) s #, C #, and G represent Student IDs, elective course numbers, and academic scores respectively.1. Use standard SQL nested statements to query the student ID and name of the elective course named

[Solution] the last step of MySQL installation in XP prompts the service cocould not be started. Error: 0 Error

1. The last step of MySQL installation in XP prompts the service cocould not be started. Error: 0 error.Solution: Start-run, enter "services. msc" to check whether MySQL service existsIf yes and cannot be started manuallyOpen the registry and go to "HKEY_LOCAL_MACHINE \ SYSTEM \ CurrentControlSet \ Services"Delete the service corresponding to MySQL Control Panel-add and deleteProgram-Delete MySQL. Delete C: // programe files/MySQLDelete c: \ Documents ents and Settings \ All Users \ Applic

SQL Classic four-table query

Tags: group between day SQL greater than the values language full teacherTopicStudent (SID, Sname, Sage, ssex)--Student Information sheet (student number increment, student name, student birth date, gender);Teacher (TID, tname)--Teacher Information sheet (teacher number increment, teacher name)Course (CID, CNAME, TID)--Curriculum (course number increment, course name, teacher number foreign key)SC (SID, CID, score)--score table (student number, course

Sqlserv Single-Table query

Author: GW------------------------Data Query------------------------------select [all|distinct]--from --where --[group by --[group by Distinct does not show duplicate resultsASC AscendingDesc Descending--Check all student's number and name--select Sno,sname from Student--select sno,sname,sdept from Student--select * FROM Student--The following as Brithday is a name for the computed column--select Sname,2014-sage as brithday from student--select sname, ' Year of birth: ', 2014-sage,upper (sdept)

Database Experiment Instruction + Experiment Report (2015) _ Foundation/compilation/compilation/composition principle

S_c database is built. (2) using the management platform to create basic table student (Sno,sname,ssex,sage,sdept), Course (Cno,cname,ccpno,ccredit), SC (sno,cno,grade). The database in the management platform taskbar is selected as S_c. A To create a new query, type the following command under the form: CREATE TABLE Student ( Sno char (9) PRIMARY KEY, sname char UNIQUE, ssex char (2), S

SQL Job Title

Job Title:1. Check all records of elective course ' 3-105 ' and score 60 to 80. Note: Used to specify a range using between and, you can also use an and connector;Answer:Law 1:select * from SC where course number = ' 3-105 ' and score between;Law 2:select * from SC where course number = ' 3-105 ' and score > score 2. Search for records with 85, 86, or 88 results. Note: Used to make a collection use the In k

A very interesting SQL optimization experience: from 30248.271s to 0.001s

SceneI use the database is mysql5.6, the following simple introduction of the next scenarioCurriculumCREATE TABLE Course (c_id int PRIMARY key,name varchar (10))Data 100 articleStudent table:CREATE TABLE Student (ID int PRIMARY key,name varchar (10))Data 70,000 articleStudent Score Table SCCREATE table SC ( sc_id int PRIMARY KEY, s_id int, c_id int, score int)Data 70w BarPurpose of Enquiry:Find candidates with 100 points in Chinese testQue

Compile and install Ixgbe-driven tutorials in the Debian Linux system _linux

Ixgbe drive. $ wget http://sourceforge.net/projects/e1000/files/ixgbe%20stable/3.23.2/ixgbe-3.23.2.tar.gz Compile Ixgbe driver as follows. $ tar xvfvz ixgbe-3.23.2.tar.gz $ cd ixgbe-3.23.2/src $ make Step three: Check the Ixgbe drive After compiling, you will see the creation of the Ixgbe.ko in the IXGBE-3.23.2/SRC directory. This is the Ixgbe drive that will be loaded into the kernel. Check the kernel module information with the Modinfo command. Note tha

SQL Interview Topics

Label:Student (s#,sname,sage,ssex) Student tableCourse (c#,cname,t#) timetableSC (s#,c#,score) score tableTeacher (t#,tname) Teacher table Problem:1, the inquiry "001" course is higher than "002" of all students of the school number;Select a.s#From (select S#,score from SC where c#= ' 001′) A,(select S#,score from SC where c#= ' 002′) bwhere A.score>b.score and a.s#=b.s#; 2, the query average score is more

Database Query instance (contains all where condition examples)

Querying a specified column[Example 1] All students are queried for their school number and name.SELECT Sno,snameFrom Student;[Example 2] All students are queried for their name, school number and department.SELECT sname,sno,sdeptFrom Student;[Example 3] A detailed record of all students is queried.SELECT sno,sname,ssex,sage,sdeptFrom Student;OrSELECT *From Student;[Example 4] Check the names of all students and their year of birth.SELECT Sname,2004-sage/* Assumes the year is 2004 years */from S

Query optimization of database-relational database system

optimizer can consider hundreds of different execution plans, and programmers generally can only consider a limited number of possibilities.(4) The optimizer includes a number of complex optimization techniques that are often only available to the best programmers. The automatic optimization of the system is equivalent to enabling everyone to have these optimization techniques The RDBMS calculates the execution cost of various query execution strategies through a cost model, then chooses the le

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