ati 3450

Miyu original, post Please note: Reprinted from __________ White House Question address: Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 3450 Description: Counting Sequences Time Limit: 2000/1000 MS (Java/others) memory limit: 32768/65536 K (Java/Others)Total submission (s): 312 accepted submission (s): 105 Problem descriptionfor a set of sequences of integers {A1, A2, A3 ,... an}, we define a sequence {aI1, ai2, ai3... AIK} in which 1 Inpu

Let's take a look at the glxgears score. Before I installed the driver, it was about 300. After I installed the driver, it was about 5000. Many graphics cards need to be driven to enable 3D desktops. The built-in video card driver of Fedora9 has relatively poor functions and is not well developed. Coupled with AMD (ATI)'s perfunctory attitude in Developing Linux drivers, the atigraphics card driver provided by Fedora is very bad, it is easy to see pro

3450:tyvj1952 Easy Time limit:10 Sec Memory limit:128 MBsubmit:468 solved:353[Submit] [Status] [Discuss] DescriptionOne day WJMZBMR is playing osu~~~ but he is too weak to push, some places entirely by luck: (Let's simplify the rules of the game.Have n click to do, success is O, failure is x, score is calculated according to comb, continuous a comb there is a*a points, comb is a great continuous o.Like Ooxxxxooooxxx, the score is 2*2+4*4=4+16

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 3450 Counting Sequences Time Limit: 2000/1000 MS (Java/others) memory limit: 32768/65536 K (Java/Others)Total submission (s): 1815 accepted submission (s): 618 Problem descriptionfor a set of sequences of integers {A1, A2, A3 ,... an}, we define a sequence {aI1, ai2, ai3... AIK} in which 1 Inputmultiple test cases the first line will contain 2 integers n, D (2 Outputthe Number of perfect

Hdu 3450 tree array optimized dp I won't talk about the meaning of the question; hdu2227 is almost just that this question is not incremental, but the adjacent difference is not greater than d. In fact, they are the same and there are also differences; This question does not contain a range and the size relationship between trees has an impact on the results. Therefore, the original id is used in the tree array. Due to the large number of values, the

Http://poj.org/problem? Id = 3450 I did this during my vacation. At that time, I used KMP. This time I used a suffix array. Concatenate n strings and separate them with different characters that do not appear in the input string. Separate each character in The New String according to the region of the atomic string and mark it with the LOC array. The length of a binary common substring. Check whether the height values of N consecutive Suffixes in the

Hdu 3450 tree array optimized dp and hdu3450 I won't talk about the meaning of the question; hdu2227 is almost just that this question is not incremental, but the adjacent difference is not greater than d. In fact, they are the same and there are also differences; This question does not contain a range and the size relationship between trees has an impact on the results. Therefore, the original id is used in the tree array. Due to the large number of

Label: style blog Io ar OS for SP on 2014 Enumerate all substrings of a string and match other strings. # Include POJ-3450 impersonate identity

;} int Searchl (int A ) { int Left=1,Right=Tt; while (LeftRight ) { int Mid=(Left+Right)/2; if (Mark[Mid]A)Left=Mid+1; else if (Mark[Mid]==A ) return Mid; Else Right=Mid; } return Left;} int Main () { int I,J,D; while (~scanf("%d%d",N,D) { for( I=1;IN;I++) {scanf("%d",Num1[I]);Num2[I]=Num1[I]; }Sort(Num2+1,Num2+1+N);Tt=0;Num2[0]=-1; for (I=1;IN;I + +) { if( Num2[I]!=Num2[I-1]) {Tt++;Mark[Tt]=Num2[I]; } }Memset(Coun,0 ,sizeof( Coun)); int Sum=0; int X=Searchl(Num1[1])

3450:tyvj1952 Easy Time limit:10 Sec Memory limit:128 MBsubmit:431 solved:325[Submit] [Status] [Discuss] DescriptionOne day WJMZBMR is playing osu~~~ but he is too weak to push, some places entirely by luck: (Let's simplify the rules of the game.Have n click to do, success is O, failure is x, score is calculated according to comb, continuous a comb there is a*a points, comb is a great continuous o.Like Ooxxxxooooxxx, the score is 2*2+4*4=4+16

Attention to detail ah ...Same as the last.#include #include#include#include#defineMAXN 300500using namespacestd;intN;CharS[MAXN];Long DoubleDP1[MAXN],DP2[MAXN];intMain () {scanf ("%d\n%s",n,s); for(intI=1; i) { if(s[i-1]=='o') {dp1[i]=dp1[i-1]+1;DP 2[i]=dp2[i-1]+2*dp1[i-1]+1;} Else if(s[i-1]=='x') {dp1[i]=0;DP 2[i]=dp2[i-1];} Else{dp1[i]= (dp1[i-1]+1)*0.5;DP 2[i]=dp2[i-1]+(2*dp1[i-1]+1)*0.5;} } printf ("%.4lf\n", Dp2[n]); return 0;}Bzoj 3450