barn vector

{intx, y;} C[n];intMain () {scanf("%d", n); for(intI=1; iscanf("%d%d", a[i],b[i]); C[i].x=a[i],c[i].y=b[i]; } sort (A +1, a+n+1), sort (b +1, b+n+1);if(n1) {inttmp=n/2+1;intTMPX=A[TMP],TMPY=B[TMP];intans=0;intflag=1; for(intI=1; iif(TMPX==C[I].XAMP;AMP;TMPY==C[I].Y) {flag=0; Break;} }if(flag) { for(intI=1; iABS(Tmpx-a[i]) +ABS(Tmpy-b[i]); }printf("%d 1\n", ans); }Else{Ans=inf;intCnt=0; for(intI=1; i4; i++) {intX=tmpx+xx[i],y=tmpy+yy[i];intret=0; for(intj=1; jABS(x-c[j].x) +ABS(Y-C[J].Y); }

USACO 1.3 Barn Repair (Greedy), USACO Barn This question is also greedy. To minimize the total length of a wooden board, the maximum length of the uncovered wooden board is required. We first use a piece of wooden board to cover the cowshed. Then, each time we select the largest gap from the covered range, divide the wooden board into two blocks Based on the gap, and repeat until it is divided into m block

Title DescriptionIn a dark night, under a stormy night, farmer John's barn roof, the door was blown away. Fortunately, many cows are on holiday, so the barn is not full. The bullpen was lined up next to the other, and the cows stayed overnight. There are some cows in the barn, some not. All the barns have the same width. After the door was lost, farmer John had t

A rectangular barn Mircea pasoi -- 2003 Ever the capitalist, Farmer John wants to extend his milking business by purchasing more cows. He needs space to build a new barn for the cows. FJ purchased a rectangular field with r (1 ≤ r ≤ 3,000) rows numbered 1 .. R and C (1 ≤ C ≤ 3,000) columns numbered 1 .. c. unfortunately, he realized too late that some 1x1 areas in the field are d

The farmer needs to cover up a bunch of barn-sized barns, but he can only make m-planks, not all barns have cows, so they don't have to cover all the barns. Ask how many sheds can be used at least in the case where all cattle barns are covered and only m planks can be customized.Greedy to find M-1 largest (connected and cattle-free barn range), the sum of these intervals is not allowed to cover the sum, and

886. [Usaco 4.2] Perfect barn ★★☆ input file:stall4.inOutput file:stall4.outSimple ComparisonTime limit: 1 s memory limit: MBUSACO/STALL4 (translated by Felicia Crazy)DescribeFarmer John had just built his new barn last week, and he used the latest milking techniques. Unfortunately, every barn is different due to engineering problems. The first week, farmer John

time limit: 1 s space limit: 128000 KB title level: Golden Gold Title Description Description In a dark night, under a stormy night, farmer John's barn roof, the door was blown away. Fortunately, many cows are on holiday, so the barn is not full. The bullpen was lined up next to the other, and the cows stayed overnight. There are some cows in the barn, some not.

is to find the minimum value, this is also difficult. because (x+y) 2>x2+y2so to some point will definitely be in the middle of the shift, the specific implementation of a queue is good. #include #includeusing namespacestd;Const intn=100005;intN,i,s,l,x,t,w,a[n],g[n];Long Longans;intMain () {scanf ("%d",N); for(i=1; i) {scanf ("%d",A[i]); A[n+i]=A[i]; } ans=0; x=1; for(i=1; i2*n-1; i++) { if(s0) s=0, x=i; S+=a[i]-1; if(s>ans) {ans=s; L=x; }} t=1; w=0; ans=0; for(i=l;i1; i++) {

First as a chainFor once, find a location.To calculate the answer for a#include #include #include #include #include #include using namespace Std;typedef long Long LL;#define N 100010int n;int cnt=1;int a[nint main (){Freopen ("A.in", "R", stdin); Freopen ("A.out", "w", stdout);scanf ("%d", n);for (int i=1;iscanf ("%d", a[i]), a[n+i]=a[i];for (int i=1;i{if (i==cnt+n)BreakS[i]=s[i-1]+a[i]-1;while (S[i]cnt++;}LL ans=0;int l=cnt+n-1,r=cnt+n-1;while (R>=CNT){while (!a[l])l--;ans+= (LL) (r-l) * (R-L);

Test instructionsGive a tree with a root at point 1th, and ask how many points in the subtree of each point have a point less than or equal to L .nExercisesThis question is more interesting;The first consideration is the tree DP, but the DP is completely unable to transfer;Consider the answer to a knot, which is the number of points (nonsense) in the subtree that is less than or equal to the node distance.What about the answer of his father in this subtree?The distance of each point in the subtr

USACO 1.3 Barn Repair (Greedy) This question is also greedy. To minimize the total length of a wooden board, the maximum length of the uncovered wooden board is required. We first use a piece of wooden board to cover the cowshed. Then, each time we select the largest gap from the covered range, divide the wooden board into two blocks Based on the gap, and repeat until it is divided into m blocks or there is no gap. /* ID: twd30651 PROG: barn1 LANG: C

", Query (_l[i], _r[i], H._hash (L + seq[_l[i] )));}int main () {init ();Work ();return 0;}------------------------------------------------------------------- 3011: [Usaco2012 dec]running away from the Barn time limit: ten Sec Memory Limit: MB Submit: 136 Solved: 74 [Submit] [Status] [Discuss] DescriptionIt ' s milking time at Farmer John's farm, but the cows has all run away! Farmer John needs to round them all up,

3409: [Usaco2009 Oct]barn Echoes bullpen echo time limit:3 Sec Memory limit:128 MBsubmit:57 solved:47[Submit] [Status] [Discuss] DescriptionThe cows often enjoy the moo in the barn because they can hear the echoes of their moo. Although sometimes it is not possible to fully hear the full echo. Bessie used to be an excellent secretary, so she accurately recorded all the screams and their echoes. She

3405: [Usaco2009 open]grazing2 Mobile Barn Time Limit:3 Sec Memory limit:128 MBSubmit:55 solved:32[Submit] [Status] [Discuss] Description John had N (2≤n≤1500) head cows, S (n≤s≤1,000,000) A word-lined barn. The distance between the adjacent barns is exactly 1. The cows are back in the shed, and the first cow is now in the Barn Pi. If two cows get too close, they

Title Link: POJ 3168 Barn ExpansionTest instructions: Abstract is to give the coordinates of the n rectangle (the lower left and right corner of the coordinates, the edge of the rectangle is parallel to the X, Y axis), asked a few rectangles and other rectangles have no contact (there is only side contact or point contact, there is no public area).Idea: Divide the sides into two categories, parallel x-axis and the y-axis. Sort the edges, and then for

★★☆ input file: lights.in output file: lights.out Simple comparisonTime limit: 1 s memory limit: MB"Problem description"Beth and her girlfriends were playing games in their bullpen. But the days do not from people, suddenly, the power of the barn trip, all the lights are closed. Beth is a very timid girl, in the endless darkness that reaches out her thumb, she feels frightened, miserable and desperate. She wants you to help her, to turn all the light

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Greedy, remove the largest min (m,c)-1 intervals/******************************************* task:barn1 lang:c++ Created TIME:2016/9/9 14:36:17 * * * * * /#include 　　"Usaco 1.3" Barn Repair

} - } - intMergeintXinty) { - if(!x| |! YreturnX+y;if(v[x]V[y]) swap (x, y); Pushdown (x); -ch[x][1]=merge (ch[x][1],y); Swap (ch[x][0],ch[x][1]);returnx; - } in intPopintx) { -Pushdown (x);returnMerge (ch[x][0],ch[x][1]); to } + voidDfsintXintFA) { - for(intI=G[X];I;I=ES[I].N)if(es[i].t!=FA) { theDFS (ES[I].T,X); TG[RT[ES[I].T]]+=ES[I].W; v[rt[es[i].t]]+=ES[I].W; *Rt[x]=merge (rt[x],rt[es[i].t]); ans[x]+=ans[es[i].t]; $ }Panax Notoginseng while(v[rt[x]]>l) Rt[x]=pop (Rt[x

Vectors are vector types that can hold many types of data, such as several integers, so they are called containers. Vector is an important member of the C + + STL, and you need to include the header file when you use it: Copy Code code as follows: #include Vector initialization: There are five ways to do this, examples are as follows: (1)