bash programming language tutorial

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Wuhan University of Science and Technology acm:1003: Chinese Edition C language Programming tutorial (second Edition) example 6.6. Adaptation

Problem DescriptionWowapps most like to learn English, English class never skip class, but English has not been learned, because the class has been sleeping. Why do you sleep, because he thinks the English word is too long. Now Wowapps has a long, long, long word and wants to compress it. Can you help him?Compression: Replaces consecutive repeating letters with one, see sample for details.InputEnter an n first to indicate the number of words Wowapps give (1Next n lines, each behavior of a string

Wuhan University of Science and Technology acm:1002: Chinese Edition C language Programming tutorial (second Edition) example 6.6

Problem DescriptionTomorrow will be the English exam, Wowapps is Midnight Oil recite the words. Wowapps found the word difficult to recite, the back one forget. After careful study, Wowapps found that the reason why the word is difficult to recite is because of the appearance of a character, destroying the beauty of the whole word, resulting in poor memory. Wowapps decided to destroy these discordant characters on behalf of the Moon!! (Applause!!) But the exam has entered the countdown, and Wowa

Wuhan University of Science and Technology acm:1004: Chinese Edition C language Programming tutorial (second Edition) after class exercise 3.7

Problem DescriptionEnter an unsigned short integer k[hex.] and P[oct.], the high byte of K as the low byte of the result, and the high byte of p as the result of the high byte to form a new integer.InputK[hex.] and P[oct.]OutputThe operation gets the new integer n.Sample Input0XD9 01117Sample Output200HINTOutput is 16 binary1#include 2 intMain ()3 {4 5 intk,p;6 while(SCANF ("%x%o", k,p)! =EOF)7 {8 intNewint = (p0xff00)| (k0xff00) >>8;9printf"%x\n", newint);Ten }

Wuhan University of Science and Technology acm:1009: Chinese Edition C language Programming tutorial (second edition) Exercise 5.12

Problem Descriptionthis day the teacher as a routine to small Hao out a topic: The teacher to small Hao a string, let small Hao will the string in reverse order output. InputThe first line includes a T, which indicates how many sets of test data are:Next T line, each line includes a string (length not exceeding 65535).OutputFor each test data output it's reverse string.Sample Input1oaHoaiX EvoL ISample OutputI Love Xiaohao1#include 2#include string.h>3 intMain ()4 {5 intL,i,n;6 Chara[655

1028:c Language Programming Tutorial (third Edition) after class exercise 8.1 using functions to find the number of conventions

The title description writes two functions, each for two integers greatest common divisor and least common multiple, calls these two functions with the main function, and outputs the result two integers by the keyboard input. Input two-digit output greatest common divisor least common multiple sample input6 15Sample output3 30Hint Sourceint main(){int a,m,n,cun,bei;scanf("%d %d",m,n);a=m*n;if(mwhile(n!=0){cun=m%n;m=n;n=cun;}bei=a/m;printf("%d %d",m,bei);return 0;}1028:c

Wuhan University of Science and Technology acm:1008: Chinese Edition C language Programming tutorial (second edition) Exercise 6.14

Problem DescriptionEnter an octal string, convert it to an equivalent decimal string, and output it in the PRINGF%s format.InputFirst, a positive integer t is entered, indicating that there is a T set of test data (1Next T line, one string per line, representing an octal integer (this integer is no more than 20 bits).OutputFor each test data, output the corresponding decimal string. One line per string.Sample Input11732Sample Output986HINTNote: The given octal number may be large, with a long lo

Wuhan University of Science and Technology Acm:1005:c Language Programming Tutorial (third Edition) after class exercise 6.6

Problem DescriptionTo print out all the "daffodils", the so-called "Narcissus number" refers to a three-digit number, whose numbers are cubic and equal to that of itself. For example: 153 is a narcissus number, because 153=1^3+5^3+3^3. Output:153?????????InputNoOutputThe number of daffodils, the beginning of childhood. One per lineSample InputSample Output1#include 2 3#include 4 5 6 7 intMain ()8 9 {Ten One inti; A - for(i= -;i +; i++) - the if(I==pow (i

1032:c Language Programming Tutorial (third Edition) after class exercise 8.6

Title Description Write a function to concatenate two strings into a string sample input after two lines of string output link123abcSample output123abc1#include 2#include string.h>3 4 voidStr_cat (CharS1[],Chars2[])5 {6 intL1 =strlen (S1);7 intL2 =strlen (S2);8 inti;9 Ten for(i = L1; i ) One { AS1[i] = s2[i-L1]; - } - theS1[i] =' /'; - } - - intMainintargcChar Const*argv[]) + { - Chars1[Bayi], s2[Bayi]; + Ascanf"%s", S1); atscanf"%s", S2); - - str_cat (S1, S2

1013:c Language Programming Tutorial (third Edition) after class exercise 6.3

The title describes the value of SN=A+AA+AAA+...+AA...AAA (with n a), where a is a number. For example: 2+22+222+2222+22222 (n=5), n is entered by the keyboard. Input a output and sample input5Sample output246901#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 intN, Sn =0, num =2;6scanf"%d", n);7 8 while(N >0)9 {TenSn + =num; Onenum = num *Ten+2; AN--; - } - theprintf"%d\n", Sn); - return 0; -}1013:c Language

C Language Programming Tutorial (third Edition) after class exercise 6.1

The title description inputs two positive integers m and N, seeking their greatest common divisor and least common multiple. Input two integer output greatest common divisor, least common multiple sample input5 7Sample output1 351#include 2 3 intMax_common_diviser (intN1,intn2)4 {5 inttemp;6 7 if(N1 n2)8 {9temp = N1; N1 = n2; N2 =temp;Ten } One A - while(n1% N2! =0) - { the intt =N2; -N2 = n1%N2; -N1 =T; - } + -

Bash basic programming Summary

Bash should be the most popular shell script interpreter in Linux. (another shell is called Dash. I hate it too much .), As long as you work on Linux and want to enjoy yourself, you should be familiar with the most basic bash programming, because it will bring enough happiness to your work. This article will summarize some basic

Bash Programming Summary

Bash should be the most popular shell scripting interpreter on Linux today (and a shell called dash, I hate this stuff too much.) As long as you work on Linux and want to work more happily, you should be familiar with the most basic bash programming, because it will give you enough happiness to work. This article will summarize some of my own usual

2017-11-27linux basic Knowledge (+) A preliminary script programming for Bash features

character in the shell, the shell will be from the $path from left to right to find the command, if found to stop finding, can not find the shell will also prompt the corresponding result, hash command is the $ The command found in the path variable is cached and the result of the command is placed in memory so that the cached command does not have to be found in the $path variable. Its storage format is: Key-value.Key: Search Key value: ValueThe options for the hash command are:Hash: to list;

Advanced Bash Scripting Programming Guide

http://tldp.org/LDP/abs/html/Advanced Bash Scripting Programming GuideAn in-depth exploration of scripting language artThis tutorial does not assume previous scripting or programming knowledge, but progresses quickly toward an intermediate/advanced level of instruction ... h

Is it a waste of time to learn bash in a scripting language?

modern language. I am using Python now, and then I need to execute the bash command to call the OS. Basically, all bash commands can be run in the OS. system ("") mode. So far, the only thing I have found is that I cannot use the OS. system is running cd. in Python, OS. chdir ("") to implement bash cd. today, my shell

Introduction to bash shell programming

Like other shells in Linux, Bourne Again shell is not only an excellent command-line SHell, but also a scripting language. Shell scripting allows you to take full advantage of shell functions and automate multiple tasks that require many commands. There are many shell programs on your Linux machine. If you are interested in learning how they work, or modifying them, the basic element is that you must understand ba

Bash Shell Script Programming Learning Summary

Shell script Programmingcompiler-------Interpreter static language: compiled language, strongly typed (variable), converted into executable format beforehand. c/c++/java/c# Dynamic Language: Interpreted language, weak type. The side explanation changes the execution. Php,shell,python,perl oriented process: shell,c;

Detailed Anatomy of bash script programming

Detailed Anatomy of bash script programmingbackground: bash scripting is a crucial part of Linux learning, and it may be easy to complete a script, but it's not easy to make your own script write. Bash is almost always available for all Linux distributions, so let's take a bash script as an example to discuss how

Detailed Anatomy of bash script programming

Detailed Anatomy of bash script programmingbackground: bash scripting is a crucial part of Linux learning, and it may be easy to complete a script, but it's not easy to make your own script write. Bash is almost always available for all Linux distributions, so let's take a bash script as an example to discuss how

A scripting language, learning Bash is a waste of time?

to improve production efficiency Ah! There's a lot of stuff like the py shell and the ruby shell, and so on. On the other hand, the shell script gives you the ability to have system utility, and all the installed programs are cleaned up and lined up for you to flirt. SED, awk, kill, Cat, PS, mkdir, RM, rsync, ..... The number of people who can not count the good beautiful girl, but *nix with innate characteristics (redirection, pipe ...) It also allows them to work together well (so do one thin

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