best cri bulbs

answer must be to replace all, because if the current bulb price is 1, the price to be replaced is 2, that would be 1 dollars cheaper, and can save a replacement bulb power money.So Dp[i]=min (DP[I],DP[J-1]+TMP*LIGHT[I].C+LIGHT[I].K) Where Light[i] is the type I lamp, TMP indicates the number of bulbs calculated from the back of I, plus used to be replaced by the first bulb. So the equation means that the optimal value of the dp[i] is equal to the b

QBC (query by criteria) mainly consists of criteria, criterion, Oder, restrictions classSession = This. getsession ();Criteria CRI = session. createcriteria (jditemserialnumber. Class );Criterion cron = restrictions. Like ("customer", name );CRI. Add (cron );List = CRI. List ();====================================Comparison OperatorsHql operator QBC operator mean

First, the query code String hql = "Select soft. softid, soft. softname, soft. ID from so. supercargo. Soft as soft Where soft. State in (1, 2 )"; Ilist list = session. Find (hql ); Second, the query codeIcriteria CRI = session. createcriteria (typeof (so. supercargo. Soft )); Int [] arrval = {1, 2 }; Icriterion cri2 = expression. In ("State", arrval ); CRI. Add (cri2 ); Ilist list =

For example, some paging data should be frequently used in nhib.pdf: CRI. setfirstresult ( 20 );CRI. setmaxresults ( 10 );Ilist list = CRI. List (); The list variable will get the data of a certain page. The above is the data of 20th pages (from 0. I read the SQL statement it executes. Nhib.pdf: Select top 30 this. ID as id0 _, this. title as title0 _, t

There seems to be no full-text retrieval statement for nhib.pdf. I usually use two methods. 1. icriteria, using expression. SQL Icriteria CRI = This. session. dbsession. createcriteria (typeof (MAG. Article. lightnews ));CRI. Add (expression. eq ("deleted", isdelete ));CRI. Add (expression. SQL (string. Format ("contains (title, '{0}')", key ))); 2. isqlquery

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consider encapsulating it as a class to use #! /usr/bin/env python #coding =gbk import Logging,os class Logger:def __init__ (self, path,clevel = logging. Debug,flevel = logging. DEBUG): Self.logger = Logging.getlogger (path) self.logger.setLevel (logging. DEBUG) FMT = logging. Formatter (' [% (asctime) s] [% (levelname) s]% (message) s ', '%y-%m-%d%h:%m:%s ') #设置CMD日志 sh = logging. Streamhandler () sh.setformatter (FMT) sh.setlevel (clevel) #设置文件日志 fh = logging. Filehandler (Path) fh.set

Bulb switcherThere is n bulbs that is initially off. You first turn the bulbs. Then, you turn off every second bulb. On the third round, you toggle every third bulb (turning on if it's off or turning off if it's on). For the n-th round, you are only toggle the last bulb. Find How many bulbs is on after N rounds.Example:NSo you should return 1, because there are o

Problem Description:If it s off or turning off if it's on). For the nth round, you are toggle the last bulb. Find How many bulbs is on after n rounds.Problem Analysis:/*** * There is n bulbs that is initially off. * You first turn the bulbs. * Then, you turn off every second bulb. * On the third round, you toggle every third bulb (turning on if it ' s off or t

Topic:There is n bulbs that is initially off. You first turn the bulbs. Then, you turn off every second bulb. On the third round, you toggle every third bulb (turning on if it's off or turning off if it's on). For then-th round, you are only toggle the last bulb. Find How many bulbs is on afterN rounds.Example:N [Off, off, off] [on, on, on] [on, Off, on] [on, off

The difficulty of this question seems to be that some bulbs can be replaced with bulbs with higher voltage to save money on power supply, so we have to explore the optimal solution. A good solution is to sort the voltage from small to large, so we can only replace the previous one with the following one.Change some bulbs to