A positive integer less than 2^32 is given. This number can be represented by a 32-bit binary number (less than 32 bits with 0 complement). We call the first 16 bits of the binary number "high" and the last 16 bits "low." We can get a new number by
Chapter 6 binary, octal, and hexadecimal
6.1 why do we need octal and hexadecimal?
6.2 decimal number conversion to decimal number
6.2.1 convert binary to decimal
6.2.2 convert octal to decimal
6.2.3 expression of the octal number
6.2.4 use of Octal
One, the conversion between decimal and binary (1) Decimal conversion to binary, divided into integers and fractional parts ① whole number of parts Methods: In addition to the 2 method, that is, each time the integer part divided by 2, the remainder
Counting bits set (naive)unsigned int v; Count the number of bits set in Vunsigned int c; C accumulates the total bits set in Vfor (c = 0; v; v >>= 1){c + = v & 1;}The naive approach requires one iteration per bit, until no more bits is set. So in a
LeetCode-Reverse Bits, 1 Bit is related to the binary state of the number, leetcodereverse
Https://leetcode.com/problems/reverse-bits/
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 0000
LeetCode-Reverse Bits, 1 Bit and number binary correlation
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00
https://leetcode.com/problems/reverse-bits/Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 ( Represented in binary as001110010111100000101001
One, the conversion between decimal and binary(1) Decimal conversion to binary, divided into integers and fractional parts① whole number of partsMethods: In addition to the 2 method, that is, each time the integer part divided by 2, the remainder is
/*The Hamming distance between and integers is the number of positions at which, the corresponding bits is different.Given integers x and y, calculate the Hamming distance.Note:0≤x, y Example:input:x = 1, y = 4Output:2Explanation:1 (0 0 0 1)4 (0 1 0
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