bootstrap file upload form

////// 1. js obtains the attributes of the uploaded file.Var fso = new ActiveXObject ("Scripting. FileSystemObject ");Var filesize = fso. GetFile (file). size;// ActiveXObject is a feature supported by IE, which is not applicable to other browsers.// When using the service, you need to set the site as a trusted site and lower the security level.// In fact, the purpose of this operation is to enable or prompt options in ActiveX controls and plug-ins at

The article begins by telling you how to make jquery easy to implement Simple File upload form style simple tutorial. Effect Chart: Page structure: CSS file style: . uploader{position:relative; display:inline-block; overflow:hidden; cursor:default; padding:0; margin:10px 0px;- moz-box-shadow:0px

From the form to upload files, the path after the jump, and can not be forwarded back.One of my solutions is. Return a piece of HTML code, the browser after parsing back one step back to the original page and refresh.return "Page jump solution after upload from form file

Before reading this article, you can read the rfc1867 Form Based File Upload in HTML protocol. 1.I don't know why, on the LAN, some computers contain The server has used a variety of file receiving tool libraries such as Apache common file

php5.5 after PHP is officially recommended to use the Curlfile class to simulate the @+ full file path method to upload filesif (class_exists (' \curlfile ')) {can use$filedata = [' fieldname ' = new \curlfile (Realpath ($filepath), ' image/jpeg ')];} else {Do not use Curlfile, and old mode　　$filedata = [' fieldname ' = ' @ '. Realpath ($filepath)];}Reference: http://blog.csdn.net/hongtu1993/article/details

")); Ticket.Setbody(Request.GetParameter("Body")); Part Filepart = Request.GetPart("File1");if(Filepart! =NULL Filepart.GetSize() >0) {Attachment Attachment = This.processattachment(Filepart);if(Attachment! =NULL) ticket.AddAttachment(attachment); }intIdsynchronized( This) {id = This.ticket_id_sequence++; This.Ticketdatabase.put(ID, ticket); } response.Sendredirect("Tickets?action=viewticketid="+ ID); }PrivateAttachmentprocessattachment(Part Filepart)throwsIOException {//Get InputStream from the

); Clearimages ($ (FileInput)); $ (FileInput). attr ("Style", ""); }}}, Error:function (msg) {clearimages ($ (FileInput)); $ (FileInput). attr ("Style", ""); Showerrortip ("parameter exception! "); } }; Pass the options to Ajaxform $ (' form '). Ajaxsubmit (options); //} }The problem was caused by ignoring

When you encounter a form that has both a file upload and a Received field, the field wants to be request.getparameter, often null. As above, call Request.getparameter ("text") in the public void DoPost (HttpServletRequest request, httpservletresponse response) To get a null How to get it. There are two kinds of solutions 1, with two forms: (More trouble)A f

when we submit the form but do not want to refresh the page, we can consider using AJAX to implement the submission function, but there is a limitation is when the file upload is not feasible, the following with the help of jquery.form can be very convenient to meet our needs.1. Forms:2.ajax notation (with the help of Jquery.form):$ (document). Ready (function ()

Php: require_once ( #39; mysql_helper.php #39;); $ pic $ _ POST [ #39; pic #39;]; $ path #39 ;. userse-bag4Desktop ;. $ _ FILES [ #39; pic #39;] [ #39; name #39;]; if (move_uploaded_file ($ _ FILES [ #39; pic #39;] [ #39; tmp_name #39;], $ path) {$ SQL quot; ins binary php form Upload Php: require_once ('MySQL _ helper. php '); $ pic =$ _ POST ['Pic']; $ path = '. /Users/e-bag4/Desktop '. $ _