bubble sort python

The process of bubbling sorting is to first compare the keywords of the first record with the keywords of the second record, and, in reverse order, Exchange two records and then compare the keywords for the second record and the third record. And so on, until the n-1 record and the nth record's keywords have been compared. The above process is called the first bubbling sort, then the second trip to the previous n-1 the same operation, ...The quick

The time complexity of bubble sorting is the idea of O (n^2) bubble sort: compare two adjacent elements each time, and swap them if they're in the wrong order.For example, there are five numbers: 12, 35, 99, 18, 76, from the big to the small sort, compare the adjacent two bits First trip: First time compar

] forIinchRange (len (data_set)):#Big Circle determines the number of rounds that we chooseMinindex =I forJinchRange (I+1,len (data_set)):#a small circle is the number of times we compare each time we choose #//If the subsequent element is smaller than the element I chose, swap the position ifDATA_SET[J] Data_set[minindex]: Minindex=J Temp=Data_set[i] Data_set[i]=Data_set[minindex] Data_set[minindex]=TempPrint(Data_set)" "The basic idea of inserting

Python to Implement Bubble, insert, select simple sort instance, python bubble The Python implementation in this article bubble, insert, and simple sorting examples are suitable for beg

Optimal time complexity: O (n) (in ascending order, sequence already in ascending state) Worst time complexity: O (n2) Stability: Stable Code:"" "Insert sort Time complexity: O (n*n) Stability: Stable" "" "" Import randomimport timedef Insert_sort (list): n = len (list) # from the second position start inserting subscript 1 for J in Range (1,n): # Start comparison from the first J element if it is less than the p

:",array)Three, direct insertion sorting algorithmdef insert1(array): ‘‘‘ 插入排序算法 :param array: :return: count: 4999 time: 3.685210704803467 ‘‘‘ count = 0 for index in range(1, len(array)): current_val = array[index] # 先记下来每次大循环走到的第几个元素的值 position = index while position > 0 and array[ position - 1] > current_val: # 当前元素的左边的紧靠的元素比它大,要把左边的元素一个一个的往右移一位,给当前这个值插入到左边挪一个位置出来 array[position] = array[position - 1] # 把左边的一个元素往右移一位

Two days ago just loaded Python 3.1.1, can't help itched write point code.1. Select sort Copy Code code as follows: >>> def selsort (L): Length=len (L) For I in Range (length-1): Minidx=i Minval=l[i] J=i+1 While JIf MINVAL>L[J]: Minidx=j MINVAL=L[J] J=j+1 L[i],l[minidx]=l[minidx],l[i] Return L 2. Bubble

1 defInsertsort (A):2' Insert sort algorithm: Pass in a list, sort the numbers in list '3 Print(' Insert sort before list element order: ', A)4Length=len (A)5For I in Range (1,length): #从第二个开始6Key=a[i]7J=i-18While J>=0 and A[j]>key:9A[J+1]=A[J]TenJ=j-1 OneA[j+1]=key A Print(' Insert sorted list element order: ', A) -#插入排序时间复杂度: n^2, Spatial complexity: 1, same el

Recommend a Visual Web site "Visual Algo": Url= ' https://visualgo.net/en/sorting 'This website gives the principles and processes of various sorting algorithms, which are visualized through dynamic forms. The related pseudo-code are also given, as well as the specific steps to execute to code."Bubble Sort"You need to repeatedly visit the sequence of columns that need to be sorted. The size of the adjacent

sort 2 4 7 9Eighth round sort 2 4 7Nineth Round sort 2 4As you can see, the order of each round, the largest number of elements participating in the comparison in this round, will float to the end. and the name of the bubble sort comes from here, too.# # Selection Sorting M

a comparison value key, which takes the first value in the list. Let the other values in the list compare them.If it is less than it is placed in the right list,If it is greater than it is placed in the left list.and then recursion. (Not very understanding of recursion.) Only know that the function itself calls itself. ）Finally, left, compare value key (need to convert to list type), right is connected together.An error has occurred:Runtimeerror:maximum recursion depth exceeded while calling a

change in range, where the length-1-long comparison is required, noting the meaning of-I (can reduce the elements that are already ordered)9 forJinchRange (0,length-1-i):Ten One #Exchange A ifMYLIST[J] > Mylist[j+1]: -TMP =Mylist[j] -Mylist[j]=mylist[j+1] theMYLIST[J+1] =tmp - - #print the list after each round of exchange - forIteminchmyList: + Print(item) - Print("============================="

, 10, 7, 4] [1, 4, 9, 13, 34, 26, 10, 7, 4] [1, 4, 4, 13, 34, 26, 10, 7, 9] [1, 4, 4, 7, 34, 26, 10, 13, 9] [1, 4, 4, 7, 9, 26, 10, 13, 34] [1, 4, 4, 7, 9, 10, 26, 13, 34] [1, 4, 4, 7, 9, 10, 13, 26, 34] [1, 4, 4, 7, 9, 10, 13, 26, 34] [1, 4, 4, 7, 9, ten,, 34]result: [1, 4, 4, 7, 9, ten,, 34]insert_sort success!!!Here's another look at bubble sort1 #==========================bubble_sort======================== 2 3 def bubble_sort (L): 4 for

#encoding:utf:8l=[5,6,9,11,34,66,6,8,7 ]deftwopointsearch (L): foriinrange (Len (l)): min_index=ifor Jinrange (I+1,len (L)): #### #循环判断得出依次次最小直的索引 ifl[min_index]>l[j]: min_index=j l[i],l[min_index]=l[min_index],l[i] ### #l [i] Minimum value aareturnla=twopointsearch (l) print (a) # # # # Bubble sort ' >>>list ' (range (10,0,-1)) [10,9,8,7,6,5,4,3, NBSP;2,NBSP;1] "DefbuBble_sort (L): foriinrange (Len (l) -1

$arr [($j + 1)]) {//Next greater than previous $temp = $arr [($j + 1)]; $arr [($j + 1)] = $arr [$j]; $arr [$j] = $temp;}}} else{//Descending for ($i = $last _key; $i >= 0; $i-) {//get sorted Key$sort_key = $last _key-$i; for ($j = $last _key; $j > $sort _key; $j-) {if ($arr [$j] > $arr [($j-1)]) {//Next greater than previous $temp = $arr [($j-1)]; $arr [($j-1)] = $arr [$j]; $arr [$j] = $temp;}}} return $arr;} $sor