bubble sort python

ObjectiveInterviews often have interviewers like to ask how to do bubble sort? This question is believed to be able to overwhelm a batch of heroes, this article will explain in detail how to use Python to bubble sort.First, the basic principle1. Concept:Bubble sort (

This section briefly introduces how to use bubble, select, and insert sorting in Python. it is recommended to your partners for reference. I recently learned the basics of python and wrote about the following three sorting trainer skills: The code is as follows: '''Created on@ Author: codegeek'''// Bubble sortDef bu

):ifData[i] > Data[i+1]: Temp=Data[i] Data[i]= Data[i+1] Data[i+1] =temp R1= Maopao (data,j+1) returnR1li1= [33,2,10,1]ret=Maopao (LI1)Print(ret)Xiao Bai happily told the results to Xiao LiuXiao Liu laughed, but the former training of the small white Ah, incredibly still use the recursion, but I also have a code on this side of a shorter program Oh! Do you want to see it?Little white dot nodXiao Liu: In fact, you can use a loop again, instead of recursion, you seeLi = [11,33,56,27,756]for j i

that when the list is in the right order, it still takes a complex amount of space to sortdefBubble_sort_easy (nums:list): forIinchRange (len (nums)):#The index of the nested two-layer loop starts at 0, so the back is Len (nums)-i-1 forJinchRange (len (nums)-i-1): ifNUMS[J] > nums[j + 1]: nums[j], nums[j+ 1] = nums[j + 1], nums[j]#Exchange returnnumsnums= [1,2,5,8,4,3,6]bubble_sort_easy (nums) Output [1, 2, 3, 4, 5, 6, 8]#Improved bubbling sorting" "1. Add Time to runing 2

comparisons as shown:The first method:DefBubble_sort (alist): for J in Range (len (alist) -1,0,-1): # J indicates the number of times each traversal needs to be compared, is gradually reduced for i in Range (j): if alist[i] > Alist[i+1]: alist[i], Alist[i+1] = Alist[i+1], Alist[i]li = [54,26,93,17,77, 31,44,55, 20]bubble_sort (li) print (LI) 第二种Method:def bublle_sort (alist):"" Bubble Sort "" "n =

1. ReferenceA gitbook online book on sorting Algorithms, "Ten classic Sorting Algorithms", using JavaScript Python Go2. Bubble Sort: 22 comparison, swap positionarr = [9,8,2,23,3]#Bubble sort 22 comparison, swap position#3 5 9) 1 8#A B C D E#3 5 9) 1 8#3 5 9) 1 8#3 5 1) 9

Start learning python, format god horse is the cloud, directly on the data structure of the algorithm. After all, read the code to learn the fastest 1 Accept the input of the Py code, later the input of the algorithm import this file #!/usr/bin/env python#coding=utf-8# stdininput.pyintsortarrays=[]def stdininput (): sortArray=raw_input (" Please input num array the want

This article mainly introduces Python's implementation of bubble, insert, and simple sorting examples. It is suitable for beginners of Python to learn and use for reference. If you need it, you can refer to the Python Implementation of bubble, insert, simple sorting example is suitable for beginners of

Bubble sort (Bubble sort) is a simple sort algorithm. It repeatedly visited the sequence to sort, comparing two elements at a time, and swapping them out if they were wrong in the order. The work of the sequence of visits is repea

>>> for I in range (Len (a)-1):... for j in Range (Len (a)-i-1):... if a[j]>a[j+1]:... a[j],a[j+1]=a[j+1],a[j]...The time complexity of bubble sorting is the idea of O (n^2) bubble sort: compare two adjacent elements each time, and swap them if they're in the wrong order.For example, there are five numbers: 12, 35, 99, 18, 76, from the big to the small

Recently learned the basics of Python, write a 3 sort of practice practiced hand: Copy the Code code as follows: ''' Created on 2013-8-23 @author: Codegeek ''' Bubble sort def bubble_sort (seq): For I in range (len (seq)): For j in range (I,len (seq)): If SEQ[J] TMP = Seq[j] SEQ[J] = Seq[i] Seq[i] = tmp Select

1. After sorting n elements from large to small, select the K-Large element#!/usr/bin/env python#Coding-*-Utf:8-*-#bubble Sort Select K elementImportRandomImport TimedefSelect_k (): N= Int (Input ("The length of the array to be generated:")) Arraya= [] forIinchrange (N): x= Random.choice (Range (100)) arraya.append (x)Print("the resulting array (not sorted):"

loop)First 22 comparison 2 Pre-swap Status | 2 |4 | 1 | 5 | 6 | 9 |Post-swap Status | 2 |4 | 1 | 5 | 6 | 9 |Second 22 comparison, 4 > 1 swapPre-swap Status | 2 | 4 |1 | 5 | 6 | 9 |Post-swap Status | 2 | 1 |4 | 5 | 6 | 9 |Third 22 Comparisons, 4 Pre-swap Status | 2 | 1 | 4 |5 | 6 | 9 |Post-swap Status | 2 | 1 | 4 |5 | 6 | 9 |Fourth time 22 comparison, 5 Pre-swap Status | 2 | 1 | 4 | 5 |6 | 9 |Post-swap Status | 2 | 1 | 4 | 5 |6 | 9 |Third trip sort (o

Python code:"""Bubble Sort (4) in the unsorted number, by 22 comparison [transposition], the smallest number to the first n number of orders, you need to execute the N-1 wheel, the 1th round of N-1 times, the subsequent round than the previous round less than 1 times in this case: the 1th round will be 0 in the correct position; 2nd wheel will 1 in the correct po

,row) - forIndexinchRange (I,len (row)):#Gets the subscript for each row of elements, and each time the loop shrinks the extent of the adjustment -Temp=array[i][index]#Get -array[i][index]=Array[index][i] inarray[index][i]=Temp - forRinchArrayPrint(R) to Print("------One loop---------")3, bubble sort, the tuples in a group of lists are arranged from small to large, and each inner loop moves on

Bubble sortAs the name implies, the bubble sort intuitively means that the larger the bubble, the faster it will be, and the number that corresponds to the list is the largest one to select, then proceed sequentially.For example myList = [1,4,5,0,6], the comparison is: the adjacent two numbers first to compare, that is

Bubble Sort:The next two numbers are compared first, i.e. li[0] and li[1], and if they are not greater than the relationship, proceed to li[1] and li[2] comparison, and then each scan gets a new list as follows:###### #冒泡排序 ###### #li = [11,22,32,344,3,] for I in range (Len (LI)-1): Xin = (Li[i]) Kai = li[i+1] If Li[i] >li[i+1]: temp = li[i] li[i] = li[i+1] Li[i+1]=tempprint (LI) for i in Ran GE (Len (li)-2): Xin = (Li[i]) Kai = li[i+1] If li[i

1. Algorithm Description:(1) Total cycle n-1 times(2) in each loop, if the preceding number is greater than the following number, swap(3) Set a label, if the last time there is no exchange, it means that this is already good. 2.python Bubble Sort Code Copy Code code as follows: #!/usr/bin/python #-*-Codi