bulls and cows game

Total accepted:19397 Total submissions:67937 difficulty:easy You is playing the following Bulls and cows game with your friend:you write down a number and ask your friend to guess W Hat the number is. Each time your friend makes a guess, you provide a hint the indicates how many digits in said guess match your secret num ber exactly in both digit and position (c

shoshould return "1A1B". You may assume that the secret number and your friend's guess only contain digits, and their lengths are always equal. Credits:Special thanks to @ jeantimexico for adding this problem and creating all test cases. Subscribeto see which companies asked this question // You and your friends are playing the following guess number game (BullsandCows): you write the next 4-digit mysterious number and ask your friends to guess it. /

You is playing the following Bulls and cows game with your friend:you write down a number and ask your friend to guess W Hat the number is. Each time your friend makes a guess, you provide a hint the indicates how many digits in said guess match your secret num ber exactly in both digit and position (called "bulls") an

You is playing the following Bulls and cows game with your friend:you write down a number and ask your friend to guess W Hat the number is. Each time your friend makes a guess, you provide a hint the indicates how many digits in said guess match your secret num ber exactly in both digit and position (called "bulls") an

https://leetcode.com/problems/bulls-and-cows/Examples:secret:1807 secret:1123guess:7810 ====> "0a3b" guess:0111 ====> "1a1b"secret:1122 secret:121guess:1222 ====> "3a0b" guess:222 ====> "1a0b"So getting the bull number was easy by just counting the number of matched pairs. The problem is to count the number of cows (mismatches).1) mismatched element from guess st

/** 299. Bulls and Cows * 2016-7-2 by Mingyang * code is ugly, but this topic is too simple, not details * Special case 1122-"1222 * guess the first 2 in the show will let me in the CO W plus 1 * So I'm going to go through the equal so it won't be wrong, but the code can be modified to a lot of optimizations, there's time to write slowly*/ Public Staticstring Gethint (String secret, String guess) {intBu

Secret and guess are read in bits, and if equal bull is added 1, the inequality is in the array of each number of different numbers in which they are counted, plus 1 (s_map[i] refers to the number of numbers I appear in secret). The last S_map and G_map are the number of occurrences of each value in the respective string, cow equals the smallest of the same position in two arrays.1 classSolution {2 Public:3 stringGethint (stringSecretstringguess) {4 ints_map[Ten] = {0}, g_map[Ten] =

A is the number of the same character of the statistical guess pairs B is the statistical statistics of the number of different bits of the same characterVery simple question.1 classSolution {2 Public:3 stringGethint (stringSecretstringguess) {4 intCntA =0, CNTB =0;5 intsn[Ten] = {0}, gn[Ten] = {0};6 for(string:: Size_type i =0; I i) {7 if(Secret[i] = = Guess[i]) cnta++;8sn[secret[i]-'0']++;9gn[guess[i]-'0']++;Ten } One for(inti =0; iTen

This problem seems to is easy at the first glance, especially the problem gives a too much simpler example. Make sure your understand the problem by making more examples or refering to some other material, like the Wikipedia articl E.Stefan shares a very simple and elegant solution, which are rewritten below using multiset in C + +.1 classSolution {2 Public:3 stringGethint (stringSecretstringguess) {4 intBull =0, both =0, n =secret.length ();5 for(inti =0; I )6Bull + = (sec