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Sixth. Referencing an array to process bulk data1. Definition of array: type-character array-name [constant-expression]1) define an array in the main function, the constant expression cannot contain the variableint a[3+5]; // Legal int N; int a[n]; // Not legal2) in the function being called, the length can be a variable or a very expressive expressionvoid int N) { int a[2// Legal, because the value of n is constant when executing a function }3) in the C
Title DescriptionFor the sum of the following three digits, the sum of 2 decimal 1~a and the reciprocal of the square and 1~c of the 1~b are reserved.InputA b COutput1+2+...+a + 1^2+2^2+...+b^2 + 1/1+1/2+...+1/cSample input100 50 10Sample output47977.93TipsNote the output format, do not output extra space!Source#includemain(){int i,a,b,c;float s=0;scanf("%d%d%d",a,b,c);for(i=1;is+=i;for(i=1;is+=i*i;for(i=1;is+=1.0/i;printf("%.2f\n",s);}1016:c Language
Problem DescriptionBeg sn=2+22+222+...+22 ... A value of 222 (with N 2). For example: 2+22+222+2222+22222 (n=5), n is entered by the keyboard.InputNOutputAndSample Input5Sample Output24690My Code:1#include 2 voidMain ()3 {4 intN,a=2, t,sum=0, I;5scanf"%d",n);6t=A;7 for(i=1; i)8 {9sum=sum+T;Tent=t*Ten+A; One } Aprintf"%d", sum); -}Other code:1#include 2 3 using namespacestd;4 5 intMain ()6 {7 Longsum=0;8 intt=2;9 intN;TenCin>>N; One for(intI=0; ii) A { -Sum + =T;
The title description has n integers, so that the previous number in the order to move backward m position, the last m number into the front number of m, see figure. Write a function: To achieve the above function, in the main function input n number and output adjusted n number. Enter the number of input data n n integer moved position m output moving N number sample input101 2 3 4 5 6 7 8 9 102Sample output1#include 2 #defineN 1003 4 //Move Once5MoveintA[],intN)6 {7 intI, temp = a[n-1];8
The title describes the value of sn=1!+2!+3!+4!+5!+...+n!, where n is a number. Input n output and sample input5Sample output1531#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 6 inti, N;7 Long Long intSn =0, factor =1;8scanf"%d", n);9 Ten for(i =1; I ) One { ASn + =factor; -Factor = factor * (i +1); - } the -printf"%lld\n", Sn); - return 0; -}1014 C Language Programming
The title describes the print out of all "daffodils", the so-called "Narcissus number" refers to a three-digit number, the number of its members of the cubic and equal to that of itself. For example: 153 is a narcissus number, because 153=1^3+5^3+3^3. Output:Input no output All narcissus number, from small start. One per line1#include 2 3 intMainintargcChar Const*argv[])4 {5 inti;6 for(i = -; I +; i++)7 {8 intGE = i%Ten;9 intBai = I/ -;Ten intShi = (I/Ten) %
Title Description Enter a line of characters, respectively, the number of letters, numbers, spaces and other characters. Input line character output statistic sample inputaklsjflj123 sadf918u324 asdf91u32oasdf/. '; 123Sample output23 16 2 41#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 Chars[Bayi];6 intI, Char_count =0, Num_count =0, Space_count =0, Other_count =0;7 //scanf ("%s", s);8 gets (s);9 Ten for(i =0; S[i]! =' /'; i++) One { A if(S[i] >='A' S[i]
The title description writes a function, entering a four-digit number, which requires the output of these four numeric characters, but spaces between each of the two digits. If you enter 1990, you should output "1 9 9 0". Enter a four-digit output to increase the space output sample input1990Sample output1#include 2 3 voidFuncintN)4 {5 intGE = nTen;6 intQian = n/ +;7 intBai = (N-qian * +) / -; 8 intShi = (N-qian * +-Bai * -) /Ten; 9 Tenprintf"%d %d%d%d\n", Qian, Bai, Shi, ge); On
(addrserver,0,sizeof(Addrserver));//Initialize Amemcpy ( (ADDRSERVER.SIN_ADDR), host->h_addr, host->h_length);//Set IP -addrserver.sin_family = af_inet;//Set the version number -Addrserver.sin_port = htons ((unsigned Short) server_port);//set the port number the - //connect .... Initiating a link to the server - if(Connect (SOCKFD,structSOCKADDR *) addrserver,sizeof(structsockaddr ))) - { +printf"Connect error!\n"); -Exit1); + } Aprintf"Connection Server succeeded Connec success...\n\n");Next
The first two chapters of this book give me the feeling that this book is not as good as everyone said. To tell the truth, it is very bad. After about 5th chapters, especially later, I think this book is really good. It provides a good analysis of some key points. However, I don't think this book is suitable for beginners. It is suitable for you to understand C ++ and check for missing information to gain a deeper understanding of some knowledge points. C ++ primer is required for getting starte
1026:c Language Programming Tutorial (third Edition) After class exercise 7.4 The topic describes an array of 9 elements that have already been sorted, and entering a number now requires that it be inserted into the array in the same order as it was originally ordered. Enter the first line, the original sequence. The second line, the number that needs to be inser
software development clearly and intuitively, clarify the specific tasks that need to be completed in each stage, and play a guiding and normative role in the development process.
Software Development Methodology
Programming style
documentation;
Have a clear name for the identifier;
appropriate procedural notes;
The procedural writing style of Liang-ha;
The form of indentation;
A clear statement s
The title description writes two functions, each for two integers greatest common divisor and least common multiple, calls these two functions with the main function, and outputs the result two integers by the keyboard input. Input two-digit output greatest common divisor least common multiple sample input6 15Sample output3 30Hint Sourceint main(){int a,m,n,cun,bei;scanf("%d %d",m,n);a=m*n;if(mwhile(n!=0){cun=m%n;m=n;n=cun;}bei=a/m;printf("%d %d",m,bei);return 0;}1028:c
Problem DescriptionTo print out all the "daffodils", the so-called "Narcissus number" refers to a three-digit number, whose numbers are cubic and equal to that of itself. For example: 153 is a narcissus number, because 153=1^3+5^3+3^3. Output:153?????????InputNoOutputThe number of daffodils, the beginning of childhood. One per lineSample InputSample Output1#include 2 3#include 4 5 6 7 intMain ()8 9 {Ten One inti; A - for(i= -;i +; i++) - the if(I==pow (i
The title describes the value of SN=A+AA+AAA+...+AA...AAA (with n a), where a is a number. For example: 2+22+222+2222+22222 (n=5), n is entered by the keyboard. Input a output and sample input5Sample output246901#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 intN, Sn =0, num =2;6scanf"%d", n);7 8 while(N >0)9 {TenSn + =num; Onenum = num *Ten+2; AN--; - } - theprintf"%d\n", Sn); - return 0; -}1013:c Language
The title description inputs two positive integers m and N, seeking their greatest common divisor and least common multiple. Input two integer output greatest common divisor, least common multiple sample input5 7Sample output1 351#include 2 3 intMax_common_diviser (intN1,intn2)4 {5 inttemp;6 7 if(N1 n2)8 {9temp = N1; N1 = n2; N2 =temp;Ten } One A - while(n1% N2! =0) - { the intt =N2; -N2 = n1%N2; -N1 =T; - } + -
later found that it is not at all, and that the error Dup_val_on_index, his book is also wrong.Here is an anonymous blockDate.sqlDECLARE l_date date;BEGIN l_date: = SYSDATE-5; Dbms_output. Put_Line (l_date); end;/I still don't know how to call that process, although I tried it before, but I didn't remember it.I'm going to try to write a call on my own, I write a process for printing time, and then call it in an anonymous block.Get_date.sqlCREATE OR REPLACE PROCEDURE get_date (num_in in number)
2015211233090 Java programming 1st weekly learning summary and javaio stream learning Summary
1. Learning Summary
A preliminary understanding of Object-Oriented Programming
Use eclipse to associate git to manage code
Java
2. Written Assignments
P: Why can java programs run across platforms? What are the steps for executing a java program? (Please write in your ow
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