c programming language 2nd edition

Problem DescriptionEnter n (nInputExample of multi-group test sample. The first row of each group has an integer n indicating that there are n strings. Next there are n rows, one string per line.OutputOutput a sequential string, with each line outputting a string.Sample Input3abaaabcabSample OutputAababacab1#include 2#include string.h>3 voidSortChar* str[],intsize)4 {5 inti,j;6 Char*tmp;7 for(i=0; i1; i++)8 {9 for(j=i+1; j)Ten { One if(strcmp (str[i]

Problem DescriptionEnter n, and the output corresponds to a hollow positive hexagon with a side length of N.For easy viewing, the sample midpoint '. ' Represents a space and prints a space instead of a small dot when plotting a drawing.InputEdge length N. (NOutputSide length is a positive hexagon of nSample Input5Sample Output.....*****....*.....*...*.......*.. *.........*.*...........*.. *.........*...*.......*....*.....*.....*****1#include 2#include 3 voidPrtCharCintcount)4 { 5 while(cou

Problem DescriptionEnter n strings (nInputMultiple sets of test data. The first row of each set of test data contains an integer n, representing a total of n strings. Next, each line contains a string that consists of printable characters.OutputEach set of test sample output one row. The output finds a string that satisfies the test instructions.Sample Input3djdlkfjsadfjwedlkfjdlkfjl;jf;sfjdsl;al/dljfd2dlkasfjmmlld;femflsad;fiwejdifSample OutputDlkfjdlkfjl;jf;sfjdsl;al/ld;femflsad;fiwejdif1#incl

Problem DescriptionVerify Goldbach conjecture that any even number of sufficiently large (>=4) can be represented by a sum of two primes.InputEnter an even n. (2OutputFind A, B make n=a+bWhere A and B are two primes, and aSample Input4100Sample Output2 23 971#include 2 3#include 4 5 using namespacestd;6 7 intPrimeintm)8 9 {Ten One intI,n; A - if(m==1)return 0; - theN= (int) sqrt (Double) m); - - for(i=2; i) - + if(m%i==0)return 0; - +

+ if((m%i==0) (n%i==0)) - $ { $ -printf"%d%d\n", i,m*n/i); - the Break; - Wuyi } the - } Wu - } About $ } - -}Other code:1#include 2#include 3 intgcdintAintb)4 {5 if(a%b==0)6 returnb;7 Else8 returnGCD (b,a%b);9 }Ten intLcmintAintb) One { A returna

array to find the maximum and minimum value;Fifth step: Finally, the output can be carried out according to the requirements of the topic;(2) Flowchart: 2、实验代码#include 3、本题调试过程碰到问题及解决办法 错误信息1：The problem is that I put Max and Min's initialization in the For loop, which leads to a point at the time of submission;Correction method: After this error, I was also very puzzled, because I am typing an example of what is right but I can not cross that point. After I also tried the teacher sai

Problem DescriptionThis day the teacher again to small Hao out a topic: give you three lengths, respectively, A,b,c match, let you calculate the three matches can make up of the Triangle area.InputEnter each row to include three number a,b,c.OutputThe area of the output triangle for each row (reserved three decimal places), cannot be composed of triangles told the small Hao output "no!".Sample Input1 2 33) 4 5Sample Outputno!6.000HINT1#include 2#include 3 intMain ()4 {5 Doubles,a,b,c,p;6

Problem DescriptionThe teacher gave a title to Xiao Hao: give you a value of n (within 32 bits) in seconds, let you convert to: minutes: seconds output. Now that little Howe is in a quandary, please help him solve the problem.InputEnter a positive integer of n seconds per line.Outputfor each set of test data, output a row of results: minutes: seconds. (24-hour system)Sample Input560Sample Output00:00:0500:01:00HINT#include intHh,mm,ss;voidConvertime (Longsec) {hh=sec/3600; MM= (sec-hh*3600L)/ -;

+ +) (P+i)->sum= (p+i)->sum+ (p+i),Score[j]; }}voidSortstructStudent *p,intN) { inti,j,m; structStudent temp; for(i=0; i1; i++) {m=i; for(j=i;j) { if((p+m)->sum) sum)) {m=J; } } if(m!=i) {temp=* (p+i); * (p+i) =* (p+m); * (p+m) =temp; } }}3. Problems encountered during commissioning and solutions:Problems encountered: The array score is written as a single array when calculating fractionsCorrection method: Should be changed to SCORE[J].Learning Summary an

Problem DescriptionWowapps most like to learn English, English class never skip class, but English has not been learned, because the class has been sleeping. Why do you sleep, because he thinks the English word is too long. Now Wowapps has a long, long, long word and wants to compress it. Can you help him?Compression: Replaces consecutive repeating letters with one, see sample for details.InputEnter an n first to indicate the number of words Wowapps give (1Next n lines, each behavior of a string

Problem DescriptionTomorrow will be the English exam, Wowapps is Midnight Oil recite the words. Wowapps found the word difficult to recite, the back one forget. After careful study, Wowapps found that the reason why the word is difficult to recite is because of the appearance of a character, destroying the beauty of the whole word, resulting in poor memory. Wowapps decided to destroy these discordant characters on behalf of the Moon!! (Applause!!) But the exam has entered the countdown, and Wowa

Problem DescriptionEnter an unsigned short integer k[hex.] and P[oct.], the high byte of K as the low byte of the result, and the high byte of p as the result of the high byte to form a new integer.InputK[hex.] and P[oct.]OutputThe operation gets the new integer n.Sample Input0XD9 01117Sample Output200HINTOutput is 16 binary1#include 2 intMain ()3 {4 5 intk,p;6 while(SCANF ("%x%o", k,p)! =EOF)7 {8 intNewint = (p0xff00)| (k0xff00) >>8;9printf"%x\n", newint);Ten }

Problem Descriptionthis day the teacher as a routine to small Hao out a topic: The teacher to small Hao a string, let small Hao will the string in reverse order output. InputThe first line includes a T, which indicates how many sets of test data are:Next T line, each line includes a string (length not exceeding 65535).OutputFor each test data output it's reverse string.Sample Input1oaHoaiX EvoL ISample OutputI Love Xiaohao1#include 2#include string.h>3 intMain ()4 {5 intL,i,n;6 Chara[655

Problem DescriptionEnter an octal string, convert it to an equivalent decimal string, and output it in the PRINGF%s format.InputFirst, a positive integer t is entered, indicating that there is a T set of test data (1Next T line, one string per line, representing an octal integer (this integer is no more than 20 bits).OutputFor each test data, output the corresponding decimal string. One line per string.Sample Input11732Sample Output986HINTNote: The given octal number may be large, with a long lo

(addrserver,0,sizeof(Addrserver));//Initialize Amemcpy ( (ADDRSERVER.SIN_ADDR), host->h_addr, host->h_length);//Set IP -addrserver.sin_family = af_inet;//Set the version number -Addrserver.sin_port = htons ((unsigned Short) server_port);//set the port number the - //connect .... Initiating a link to the server - if(Connect (SOCKFD,structSOCKADDR *) addrserver,sizeof(structsockaddr ))) - { +printf"Connect error!\n"); -Exit1); + } Aprintf"Connection Server succeeded Connec success...\n\n");Next

C + + programming language (Fourth edition) "PDF" Download Link:https://u253469.pipipan.com/fs/253469-230382177Content IntroductionThis book is a classic reference in the field of C + +, and introduces the new features and functions of c++11. The main contents include: C + + Type, object, scope, storage, computing basis and modularization knowledge, namespaces, s

Tidy up the notes you put on Hi.baidu years ago!Perl concise Programming, "Perl Language Primer (Fifth Edition)" Reading notes 20110316!The book was bought very early, simply turned over and dropped!Recently bought an ipad, a good reading experience, used to read books, feel the book can look in!You can't look it over and tidy up your reading notes!Perl's program

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