c programming language 2nd edition

The title describes the print out of all "daffodils", the so-called "Narcissus number" refers to a three-digit number, the number of its members of the cubic and equal to that of itself. For example: 153 is a narcissus number, because 153=1^3+5^3+3^3. Output:Input no output All narcissus number, from small start. One per line1#include 2 3 intMainintargcChar Const*argv[])4 {5 inti;6 for(i = -; I +; i++)7 {8 intGE = i%Ten;9 intBai = I/ -;Ten intShi = (I/Ten) %

Title Description Enter a line of characters, respectively, the number of letters, numbers, spaces and other characters. Input line character output statistic sample inputaklsjflj123 sadf918u324 asdf91u32oasdf/. '; 123Sample output23 16 2 41#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 Chars[Bayi];6 intI, Char_count =0, Num_count =0, Space_count =0, Other_count =0;7 //scanf ("%s", s);8 gets (s);9 Ten for(i =0; S[i]! =' /'; i++) One { A if(S[i] >='A' S[i]

The title description writes a function, entering a four-digit number, which requires the output of these four numeric characters, but spaces between each of the two digits. If you enter 1990, you should output "1 9 9 0". Enter a four-digit output to increase the space output sample input1990Sample output1#include 2 3 voidFuncintN)4 {5 intGE = nTen;6 intQian = n/ +;7 intBai = (N-qian * +) / -; 8 intShi = (N-qian * +-Bai * -) /Ten; 9 Tenprintf"%d %d%d%d\n", Qian, Bai, Shi, ge); On

C ++ programming language (Special Edition). This book is detailed in more than 800 pages. Because it was written by the founder of C ++, many features of C ++ are introduced. It is worth reading. It consists of three parts: The first part is the c subset of C ++, the third part is the object-oriented programming in C

Import java.util.*;public class Exercise13_04 {public static void Main (string[] args) {Scanner input = new Scanner (system.in);System.out.println ("Enter month and Year:");Printcalendar Y = new Printcalendar (Input.nextint (), Input.nextint ());Y.printmonthtitle (); Y.printmonthbody ();}}Class Printcalendar {Calendar value;Public Printcalendar (int Month, int.) {value = new GregorianCalendar (year, Month, 1); }public void Printmonthtitle () {System.out.println ("" + Getmonthname (Value.get (cal

The title describes the sum of the diagonal elements of a 3x3 matrix. Input matrix output main diagonal sub-diagonal element and sample input1 2 31 1 13 2 1Sample output3 7Hint Source#includeint main(){int a[9];int x,y,i;for(i=0;iscanf("%d",a+i);x=a[0]+a[4]+a[8];y=a[2]+a[4]+a[6];printf("%d %d\n",x,y);} 1025:c Language Programming Tutorial (third Edition) after cl

The title describes a ball from the M-meter height of the free fall, each landing after the return of the original height of half, and then fall. How high does it bounce when it lands on nth time? How many meters are there? Leave two-bit decimal input m n output how high does it bounce when it lands on nth time? How many meters are there? Keep two decimal places separated by spaces and put in one line sample input1000 5Sample output31.25 2875.00Hint Source#includeint main(){int m,n,i;float h,l=0

The title description has a fractional sequence: 2/1 3/2 5/3 8/5 13/8 21/13 ... The sum of the first n items of this sequence is calculated, and two decimal places are reserved. Input n output series top N and sample input10Sample output16.481#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 6 intN, M =2, n =1, I;7 floats =0;8scanf"%d", N);9 for(i =0; i )Ten { One intT; As + = (float) m/N; -t =m; -m = n +m; then =T; - } - -printf"%.2f\n", s); + return 0;

The title describes the sum of the following three numbers, preserving the 1~b of the sum of the squares and 1~c of the 2-bit decimal 1~a and the input a B c output 1+2+...+a + 1^2+2^2+...+b^2 + 1/1+1/2+...+1/c Sample input100 50 10Sample output47977.931 intMainintargcChar Const*argv[])2 {3 4 intA, B, C, I;5 floatS1 =0, S2 =0, S3 =0;6 7scanf"%d%d%d", a, b, c);8 9 for(i =1; I )Ten { OneS1 + =i; A } - - for(i =1; I ) the { -S2 + = i *i; - } - + for(i =1

The title description enters two integers, asking them to divide the remainder. Use a macro with parameters to implement, program. Input a b two number output A/b remainder sample input3 2Sample output11#include 2 #defineDivide (A, b) res = a% B;3 intMainintargcChar Const*argv[])4 {5 intA, B, res;6scanf"%d%d", a, b);7 8 Divide (A, b);9 Tenprintf"%d\n", res); One return 0; A}1037:c Language Programming