cable tv headend

The main topic: to a N-point, M-edge of the graph, the minimum point cut set of the cardinality.Problem Analysis: The base of the minimum point cut set of the graph can be changed to the minimum cut. Considering the graph of single source s single-sink T, if a minimum point set is required, so that the graph is no longer connected after the point set is removed (the number of connected components is increased), simply split each point into two (in and out points), and with a capacity of 1 arc, t

].clear (); memset (LT,0,sizeof(LT)); for(intI=0; i1; for(intI=0; i) Addedge (i,i+n,1); while(m--) { intu,v; scanf ("(%d,%d)",u,v); Addedge (U+n,v,inf); Addedge (V+n,u,inf); lt[u][v]=lt[v][u]=1;//U and v are directly connected } intans=INF; for(intIi=n; ii2*n; ii++) { for(intI=0; i) {s=ii,t=i; if(!lt[s-n][t])//consider whether the two points in the original image are directly connected { for(int

Topic descriptionA pay cable TV network plans to relay an important football match. Their broadcast network and user terminal constitute a tree structure, the root node of the tree is located at the scene of the football match, the leaves for each user terminal, and other transit points for the tree's internal nodes.Signal transmission costs from the retransmission station to the retransmission station and

The top ten lucrative industries are energy, pharmaceuticals and medical care, primary and secondary education, funeral and teaching materials publishing, cosmetic surgery, highways, cable TV, real estate, online games. The top ten lucrative industries are energy, pharmaceuticals and medical care, primary and secondary education, funeral and teaching materials publishing, cosmetic surgery, highways,

A pay cable TV network plans to relay an important football match. Their broadcast network and user terminal constitute a tree structure, the root node of the tree is located at the scene of the football match, the leaves for each user terminal, and other transit points for the tree's internal nodes.Signal transmission costs from the retransmission station to the retransmission station and from the retransm

Cable TV set-top box cracking tutorialAfter cracking, you can watch the paid channel.Every file in it should be carefully read. negligence may cause failure.Steps for writing a set-top box ProgramIn this step, the serial port of the set-top box is upgraded. A serial port is used to connect the PC to the set-top box.Cable TV set-top box cracking steps:Step 1: Open

http://poj.org/problem?id=1966Title Description:In cable TV networks, repeaters are connected in two directions. If there is at least one route between any two repeaters in the network, the repeater network is called connected, or the repeater network is not connected. An empty network, and a network with only one repeater, are considered to be connected. The safety factor F of a network with n repeaters is

The tree backpack as a group backpack, the return of the temporary negative is also possible, and the value of the income is also very large, so no longer let the income of the current subscript, put into the array to save, set F[x][t] for the X-root of the sub-tree select T to watch the program, The biggest benefit of the TV station (let you ask what is not necessarily exist in the array inside, it may be set to subscript and then judge the feasibili

]]; $ if(!a[e.to] e.cap >e.flow) { -P[e.to] =G[x][i]; -A[e.to] = min (a[x], E.cap-e.flow); the Q.push (e.to); - }Wuyi } the if(A[t]) Break; - } Wu if(!a[t]) Break; - for(intu = t; U! = S; U = edges[p[u]]. from) { AboutEdges[p[u]].flow + =A[t]; $Edges[p[u] ^1].flow-=A[t]; - } -Flow + =A[t]; - } A returnflow; + } the }; - $ Edmondskarp G; theVectorBak; the

win8.1 System HDMI HD cable connected to the TV after no sound what to do 1, open the Control Panel, into the "hardware and sound" 2, click the Sound of "management audio equipment" 3. Right-click "Speaker/handset" In Sound equipment, select "Set as Default Device", click OK 4, the reason is because the HDMI line has the sound synchronous transmission function, by default will make

- inthead[n],cur; - ints,t; -queueint>Q; + intCap[n],fr[n]; - + voidAdd_edge (intLintRintf) A { ated[cur]=(Edge) {head[l],r,f}; -head[l]=cur++; -Ed[cur]= (Edge) {head[r],l,0}; -head[r]=cur++; - } - in intn,m; - int Get; to BOOLek () + { -memset (Cap,0,sizeof(CAP)); thecap[s]=INF; * while(!q.empty ()) Q.pop (); $ Q.push (s);Panax Notoginseng while(!q.empty ()) - { the intu=Q.front (); Q.pop (); + for(inti=head[u];i!=-1; i=ed[i].nxt) A if(!cap[ed[i].t

value between a and all other points of the G is k, there is a tree of k without a common edge in G that has a root;2. Set G is a direction graph, 0#include #includeSet>#include#include#include#include#include#include#include#include#includestring>#include#include#include#include#include#include#defineLL Long Long#definePI 3.1415926535897932626using namespacestd;intgcdintAintb) {returnA% b = =0? B:GCD (b, a%b);}#defineMAXN 110Const intINF =0x3f3f3f3f;intP[MAXN];intCAP[MAXN][MAXN],FLOW[MAXN][MAX

the capacity of the arc U "v" on the rail is ∞;(3) A "is the source vertex, B ' is the sink vertex2. Specify a source point a ", enumerate the meeting point, and ask for a" to B "maximum flow F3. To find out all the enumerated source points and the minimum values in the meeting point, all the V vertices corresponding to the arc (V ', V ') with Flow 1 are composed of a fmin set, and the G graph becomes disconnected when the vertices are removed from the G graph.4. The result if Fmin >= n means t