cable tv multiplexer

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Introduction of cable TV Cable (Cable) mode broadband access

Cable TV Cable (Cable) mode broadband access to the Internet is the standard docsis (Data over Cable Service Interface specification), Recently this standard has been upgraded to 2.0, and Imedia announced in April the DOCSIS2.0 chip IM6030 and a reference design that can be

LCD TV Plug the cable TV signal line is which interface HDMI is what interface

1, LCD TV cable Signal line interface (analog signal) is a radio frequency interface (also known as RF interface, coaxial cable interface, closed route interface), digital signal through the set-top box to convert analog signal video output to the TV, in order to watch TV pr

Cable TV Network (HFC) to establish computer network solutions

CATV Broadband Integrated Information network based on 3COM company CATV Access Network platform is a successful implementation of cable TV, data communication and network telephone "three nets in one" on the 750MHz bandwidth fiber-optic coaxial hybrid network (HFC). The open television, telephone, computer line of the public Information network, the main technical indicators to reach the world's advanced l

A dvb-based Data Broadcast System developed by the Blue topology company for cable TV networks

[Abstract]: This paper introduces the DVB-based Data Broadcast System (IP over DVB) developed by the Blue topology company for cable TV networks, which focuses on the system structure, the front-end system structure and implementation, and the design and implementation of the backend data receiving card. Key parts of the system: Front-End Server software, multi-protocol wrappers, and data receiving cards ar

Application of the access network system in cable TV network Backhaul

The access network system is widely used and has been well developed in various fields. It also plays an important role in cable TV return. After more than 20 years of development, China's cable TV network line is now more than 3 million kilometers in length, the optical fiber trunk line reaches 0.26 million kilometers

POJ 1966 Cable TV Network

POJ 1966 Cable TV Network graph connectivity, net flow minimum cutCable TV Network Cable TV networktime limit:1000ms Memory limit:30000ktotal submissions:5047 accepted:2347descriptionthe Inter Connection of the relays in a cable

Cable TV Network (CATV)

CATV Network is an efficient and inexpensive comprehensive network, it has a wide bandwidth, large capacity, multi-function, low cost, anti-interference ability, support a variety of services to connect the advantages of millions of households, its development for the development of Information superhighway laid a foundation. In recent years in China CATV Network development, the country has built more than 1500 cable

Comparison of IP transmission technology in cable TV networks

Comparison of IP transmission technology in cable TV networks Abstract: IP transmission technology in cable TV networks includes three forms: IP over ATM, IP over SDH, and IP over WDM, this article introduces and compares the three IP Address Transmission Technologies in detail. Key words: IP technology,

Cable TV Network vertex connectivity (maximum flow algorithm)

Cable TV NetworkAbstract: Give a graph with n points vertex, give M edge. Find the point of connectivity KAlgorithm: Each vertex v is split into V ' V ', and V '-->v ' has a capacity of 1. For edges in the original (u,v) edge u '--->v ' V '-->u '. P (u,v) for each pair of points, with u as source and V as meeting point.We just need to fix one vertex and enumerate the other sinks.1#include 2#include 3#inclu

win8.1 system notebook Connection use HDMI HD cable to connect the TV without sound how to solve

win8.1 system notebook connection use HDMI HD cable to connect to TV no sound how to solve? win8.1 system notebook has an HDMI interface, as long as the use of HDMI high-definition cable can be connected to the monitor, LCD TV screen display, so you can operate under the large screens. But some win8.1 system friends sa

POJ 1966 Cable TV Network (vertex connectivity for undirected graphs)

POJ 1966 Cable TV NetworkLinks: http://poj.org/problem?id=1966Test Instructions: in a cable TV network, the repeater connection is bidirectional. If there is at least one route between any two repeaters in the network, the repeater network is called connected, or the repeater network is not connected. An empty network,

POJ 1966--cable TV Network "The point connectivity of undirected graphs is constructed with maximum flow model && Dinic"

Cable TV Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 4234 Accepted: 1989 DescriptionThe interconnection of the relays in a cable TV network is bi-directional. The network is connected if there are at least one interconnection path be

POJ 1966 Cable TV Network

Cable TV Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 4690 Accepted: 2170 DescriptionThe interconnection of the relays in a cable TV network is bi-directional. The network is connected if there are at least one interconnection path be

Rokua P1273 Cable TV network

2016-05-31 13:25:45Topic Link: Rokua P1273 cable TV networkMain topic:Take as many leaf nodes as possible on a given tree of weights, making sigma (val[selected leaf node])-sigma (cost[)) >=0Solution:Tree-like DP backpack DPDP[I][J] represents the maximum profit obtained by selecting J leaf nodes for the subtree of the root of the I node.Transfer equationDp[i][j]=max (Dp[i][j],dp[i][j-k]+dp[son][k]-cost[son

POJ 1966 Cable TV Network

(inti = head[x]; I i =Edge[i].next) { intv =edge[i].to; if(EDGE[I].W dep[v] = = Dep[x] +1) {k=Dinic (V,min (rest, EDGE[I].W)); if(!k) Dep[v] =0; EDGE[I].W-=K; Edge[i^1].W + =K; Rest-=K; } } returnFlow-rest;}BOOLBFs () {memset (DEP,0,sizeof(DEP)); Queueint>Q; Q.push (s); Dep[s]=1; while(!Q.empty ()) { intx =Q.front (); Q.pop (); for(inti = head[x]; I i =Edge[i].next) { intv =edge[i].to; if(EDGE[I].W !)Dep[v]) {Q.push (v); DEP[V]= Dep[x] +1; if(v =

Poj--1966--cable TV Network "undirected graph vertex Connectivity"

Links:http://poj.org/problem?id=1966Test Instructions: an undirected graph, n points, M edges, to find the vertex connectivity of this graph.idea: vertex connectivity, that is, the number of cut points in the minimum cut point set, the general method of finding the vertex connectivity of undirected graphs is to transform to the minimum cut of the network flow.Build diagram:(1) The original image of each point I split, split for I ' and I ', I ' to I ', an arc capacity of 1.(2) for edges present

UVA 1660 Cable TV Network [min Cut] [connectivity of graph] [Split Point]

Cable TV NetworkTime limit:3000ms 64bit IO Format:%lld %llu The point connectivity of undirected graphs is obtained, that is to say, to find the minimum cut of any two points.But considering s set and T set, the middle is connected by several edges, these edges are the smallest cuts of s to T, assuming that this is the answer, then finding that there is no need to enumerate all the points, but to fix a poin

POJ 1966 Cable TV Network

while(Tell ()) { the for(intI=1; i) -cr[i]=H[i]; Wu while(t=Zeng (S,inf)) -r+=T; About } $ returnR; - } - intMain () { - while(SCANF ("%d%d", n,m)! =EOF) { Amemset (H,0,sizeof(h)); +memset (NXT,0,sizeof(NXT)); thetot=1; -ans=INF; $ for(intI=1; i) theAdd (I,i+n,1); the for(intI=1; i){ thescanf"(%d,%d)",aa,BB); theAdd (aa+n+1, bb+1, INF); -Add (bb+n+1, aa+1, INF); in } the for(intI=1; i) the for(intj=1; j){ About

POJ 1966 Cable TV Network vertex connectivity

+ =tmp; the if(Cost = =limit) the Break; +}Else { -DIS[V] =-1; the }Bayi } the } the returnCost ; - } - intDinic () { the intAns =0; the while(BFS ()) { theAns + =DFS (s, INF); the } - returnans; the } the intMain () the {94 intN, m, x, y; the while(~SCANF ("%d%d", n, m)) { the for(inti =0; i) { thescanf"(%d,%d)", edge[i][0], edge[i][1]);98 } Abouts =N; - intAns =inf;101

UVA-1660 Cable TV Network (min cut)

The main topic: to a N-point, M-edge of the graph, the minimum point cut set of the cardinality.Problem Analysis: The base of the minimum point cut set of the graph can be changed to the minimum cut. Considering the graph of single source s single-sink T, if a minimum point set is required, so that the graph is no longer connected after the point set is removed (the number of connected components is increased), simply split each point into two (in and out points), and with a capacity of 1 arc, t

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