calculate latitude and longitude from distance and bearing

public static double Getdistance (double long1, double lat1, double long2,Double lat2) {Double A, B, R;R = 6378137; Earth radiusLAT1 = LAT1 * math.pi/180.0;LAT2 = Lat2 * math.pi/180.0;A = LAT1-LAT2;b = (long1-long2) * math.pi/180.0;Double D;Double SA2, SB2;SA2 = Math.sin (a/2.0);SB2 = Math.sin (b/2.0);D = 2* R* Math.asin (MATH.SQRT (SA2 * SA2 + math.cos (LAT1)* MATH.COS (LAT2) * SB2 * sb2));return D;}public static double Getangle (double lat_a, double lng_a, double lat_b, double lng_b){Double d

Code Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> PublicStaticDoubleDistanceoftwopoints (DoubleLng1,DoubleLAT1,DoubleLng2,Double LAT2, gausssphere GS) {DoubleRadlat1= Rad (LAT1 );DoubleRadlat2= Rad (LAT2 );DoubleA=Radlat1- radlat2; double B = rad (lng1) - rad (lng2 ); double S = 2 * math. asin (math. SQRT (math. pow (math. sin (A / 2 ), 2 ) + Math. Cos (radlat1) *Math. Cos (radlat2)*Math. Pow (math.

) mile = 3958.758349716768 * Arccos (C) mileIn practical application, we generally use an individual zip code to find the longitude and latitude of the region center corresponding to the zip code, and then calculate the distance between each other based on these latitudes, to estimate the approximate

-type.co.uk/scripts/latlong.htmlThe section "Destination Point given distance and bearing from start point" is described here. I paste the code directly:Here Getrectrange This function is also to due north as the starting angle, clockwise direction, to obtain Maxlatitude, Minlatitude, Maxlongitude, minlongitude such an MBR. The error of 2 methods is very small. I think it's all a formula that can be used.

according to 2 a latitude and longitude point, calculate this 2 distance between a latitude and longitude pointThe formula for calculating the distance between any two points on a spher

SQL statements: Select Location.* from (select *,round (6378.138*2*asin (sqrt () (Pow () (Sin (36.668530*pi ()/180-px_lat*pi ()/180)/2), 2) +cos (36.668530*pi ()/180) *cos (Px_lat*pi ()/180) * POW (Sin ((117.020359*pi ()/180-px_lon*pi ()/180)/2), 2)) (*1000)) As distance from bsx_training where (px_state = 1) and (type_id! = ") and (((Px_lat >= 27.683290277922) and (px_l At Ignore the above SQL statement first. One by one explanationSQL statements so

triangle across latitudesFor example, AB two points of different latitude and longitude (a by B weft)The distance between the Latitude B ', which is collinear with point A, and the distance from A to B ' are calculated by using the Pythagorean theorem.Simply put, the follow

PHP calculates the Distance Based on the longitude and latitude between two points, and php calculates the longitude and latitude of two points. This is a good example. paste the code to know the latitude value and

Original http://www.cnblogs.com/softfair/p/distance_of_two_latitude_and_longitude_points.htmlCalculates the distance between the 2 latitude and longitude points based on the 2 latitude and longitude pointsThe formula for calculating the