call of duty four

Author: Xiaolin. Peng Welcome to discussion 196568501 # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Include # Define DEVICE_NAME "pwm" # Define PWM_IOCTL_SET_FREQ 1# Define PWM_IOCTL_STOP 0 Static struct semaphore lock; /* Freq: pclk/50/16/65536 ~ Pclk/50/16* If pclk = 50 MHz, freq is 1Hz to 62500Hz* Human ear: 20Hz ~ 20000Hz*/Static void PWM_Set_Fre

:f_out=clk0;1:F_OUT=CLK1;2:F_OUT=CLK2;3:F_OUT=CLK3;4:F_OUT=CLK4;5:F_OUT=CLK5;6:f_out=clk6;7:F_OUT=CLK7;EndcaseEndmoduleThe realization of the non-fixed duty ratio (frequency adjustment, the duty ratio will follow the change)Module Pulse_gen(Input clk_in,Inputrst_n_in,Inputkey_menu,INPUTKEY_UP,Inputkey_down,Outputmenu_state,Outputregpulse_out);Debounce for Key_menuDebounce debounce_menu (. CLK (Clk_in),. Rst

Timerone Address:Https://code.google.com/archive/p/arduino-timerone/downloadsEx#include "TimerOne.h"void Setup (){Pinmode (, OUTPUT);Timer1.initialize (500000); Initialize Timer1, and set a second periodTIMER1.PWM (9, 512); Setup PWM on pin 9, 50% duty cycleTimer1.attachinterrupt (callback); Attaches callback () as a timer overflow interrupt}void Callback (){Digitalwrite (Digitalread (10) ^ 1);}void Loop (){Your program ...}*/Arduino uses Timerone lib

Definition: You should and only have one reason to change the class.Understand:If a class takes on too much responsibility, it is tantamount to coupling these responsibilities, and a change in responsibility may weaken or inhibit the ability of this class to perform other duties,This coupling can lead to fragile designs. When the change occurs, the design suffers unexpected damage.If a class A, there are two responsibilities, a, a, when responsibility a due to changes in requirements and needs t

Method One WindowProcvoid __fastcall Mywindowproc (messages::tmessage message); IncreaseClasses::twndmethod Oldwindowproc; Increasevoid __fastcall Tform1::mywindowproc (messages::tmessage message){if (message.msg = = WM_MouseWheel){:: MessageBox (NULL, "OK", "Message", 0); TestCaption = Now ();}ElseOldwindowproc (Message);}void __fastcall tform1::formcreate (tobject *sender){oldwindowproc=edit1->windowproc;edit1->windowproc=mywindowproc;}Method two Message_mapClass Tform1:public Tform{__publishe

Single responsibility principle (SRP), in the case of a class, there should be only one cause for its change.Personally think that this principle is too idealistic, only one is not absolute, reasonable is good.Much of what software is designed to do is to discover responsibilities and separate those responsibilities from "ASD"If you can think of more than one motive to change a class, then this class has more than one responsibility.MVC, it can be said that the principle of good use, but sometim

Script for automatically recording the switch-on time at work and off-duty @ ECHOOFFwww.2cto. comseta % date :~ 0, 10% setb % time :~ 0, 8% if quot; % 1 quot; s quot; gotosif quot; % 1 quot; e quot; gotoeexit: secho --------------- script for automatically recording the switch on/OFF time at work and OFF work @ echo off www.2cto.com set a = % date :~ 0, 10% set B = % time :~ % If "% 1" = "s" goto sif "% 1" = "e" goto eexit: secho ---------------

Bare shortest path...Creating a graph is still subtle... But it doesn't feel fast...Create a vertex at each time point. Then, we can build a graph in two steps:(1) I point in time connects a directed edge to the I-1 point in time(2) If there is a ox [l, r], then l-1 connects an edge to rThe last answer is dis [T].Think about it and think it's very clever... But it's slow...1 /************************************** * *********************** 2 Problem: 3389 3 User: rausen 4 Language: C

Single principle of responsibility, in the case of a class, there should be only one cause for it to change.If a class takes on too much responsibility, it is tantamount to coupling these responsibilities, and a change in responsibility may weaken or inhibit the ability of the class to perform other duties, which can lead to a fragile design that will suffer unexpected damage when the changes occur.The real thing about software design is the discovery of responsibilities and the separation of th

Defined:There should be and only one cause for class changes.There should never is more than one reason for a class-to-change.Advantages:1, the complexity of the class is reduced, the realization of what responsibilities are clearly defined;2. Readability is improved, complexity is reduced, readability of course is improved;3, maintainability, improve readability, maintainability of course, improve;4, the change caused by the risk of reduction, change is essential, if the interface of a single r

operator should generally be defined as a const member. 1. Use class type conversion As long as there is a conversion, the compiler will automatically call it where built-in conversion can be used. In the expression: Smallint Si; Double dval; SI> = dval // Si converted to int and then convert to bool In the condition: If (SI) // Si convert to int and then convert to bool Pass real parameters to the function or return values from the function: Int cal

Duty cycle is the ratio of the on time to the periodThe effect is basically the same when the impulse is equal and the narrow pulse with different shape is added to the link with inertia.Duty cycle: is the output of the PWM, the high-level hold time and the PWM clock cycle time ratio, such as a PWM frequency is 1000Hz, then its clock period is 1ms, is 1000us, if the high-level occurrence of the time is 200US, Then the low-level time must be 800us, the

Some time ago, I went to Singapore to travel and spent two or three days shopping at the Singapore Changi Airport Duty Free shop. The duty-free shop stuff is really cheap, like my chop-hand party is absolutely irresistible temptation ... A lot of skincare products have been stocked at Changi Airport's online duty-free shopping site before departure. Its online

the suffix function from the prefix function.4. Define suffix OperatorsTo be consistent with the built-in operator, the suffix operator should return the old value (that is, the value that has not been auto-incrementing or auto-subtracted), and should be returned as a value, rather than a reference. CheckedArr operator ++ (int){CheckedArr ret (* this );++ (* This );Return ret;}CheckedArr operator -- (int){CheckedArr ret (* this );-- (* This );Return ret;}Because these operators are implemented

functions?Answer: 1 if the value assignment function returns void, we know that the only thing we need to note is that it does not support chained value assignment, that is, a = B = C is not allowed!2. There is a fundamental difference between the returned class object itself and the reference of Class Object!First, if it returns the class object itself.A operator = (A ){If (name! = NULL)Delete name;This-> _ id = A. _ id;Int Len = strlen (A. Name );Name = new char [Len + 1];Strcpy (name, A. Nam

C ++ learning heavy-duty operator 1, heavy operator In addition to overload functions, C ++ Allows defining existing operators so that they can be used like processing data through Operator overloading. Code first1 # include An error will be prompted during compilation: ------------------ Configuration: demo1-Win32 Debug --------------------Compiling...Demo. cppE: \ CCDEMO \ demo1 \ demo. cpp (19): error C2676: binary '++ ': 'class num' does not defin

The so-called overload is to give a new meaning. Function Overloading is to assign a new meaning to an existing function to implement new functions.Operators can also be overloaded.Operator Overloading is to give multiple meanings to existing operators.NecessityIn C ++, the pre-defined operator can only operate on basic data types, but does not apply to user-defined types (such as classes)(1) c ++ does not allow users to define new operators themselves. It can only overload existing C ++ operato

, const String s2 ); }; Step 2: Dilemma As mentioned above, the built-in operator + returns the right value, which is of the same type as the operand. However, the efficiency of returning an object in the caller stack is very low, especially when processing large objects. Can we return a pointer or reference? The answer is no. Because the return pointer breaks the rule that the parameter type and return value type should be the same. Even worse, linking multiple expressions will become impossib

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Rewriting The "number of parameters during rewriting" mentioned above has already implemented a subclass to rewrite the constructor of the parent class, but this is not a good write method. If you observe it carefully, you will find that the previous class Student overwrites the Person constructor of the parent class. In fact, it adds an additional parameter to the constructor of the parent class, however, we write the original parameters of the parent class again. Because the constructor of th