cat5 straight through

Someone asked me on the snow watching forum. So I wrote this code by the way. Q: I encountered this problem when writing code. Set the points A (100,100) and B (200,200) to a straight line. How can I get, b: All vertices in a straight line connected by two points. The brother can give a formula. Thank you first.A: We can use the vectors to obtain the result in collinearity. I learned this in middle school:I

Question: I will give you a straight line and several circles, and find out the proportion of the length of the circle and the straight line to the whole line. Solution: calculate the percentage of the Cross-circle between the circle and the straight line by using the method of determining the ratio of points. Step 1: (determine whether the projection direction i

1. inkcanvas class. Inkcanvas is required to implement the canvas. Generally, noCodeYou can draw a line on it. If you need to set the paint brush color and pen tip size, you need to set defadradrawingattributes, for example: Drawingattributes attributes = new drawingattributes (); Attributes. Color = colors. Black; Attributes. Height = 50; Attributes. width = 50; Attributes. fittocurve = true; 2. draw a straight line on inkcanvas Method: Mod

Determine whether two straight lines are intersecting in 3D space Straight line r1 (S) = O1 + S * D1 Straight line R2 (t) = O2 + T * D2 R1 (S) = R2 (t) => O1 + S * D1 = O2 + T * D2 => S * D1 × d2 = (o2-o1 + T * D2) × d2 T * D2 × d1 = (01-02 + S * D1) × d1 => Because D x D = 0 => S * (d1 × d2) = (o2-o1) × d2 T * (D2 × d1) = (o1-o2) × d1 => S * (d1 × d2)

x1y1x2y2x3y3x4y4.Thus each of these input lines represents two lines on the plane: The line through (x1, Y1) and (X2, Y2) and the line through (X3, Y3) and (X4, y4 ). the point (x1, Y1) is always distinct from (X2, Y2 ). likewise with (X3, Y3) and (X4, Y4 ).OutputThere shoshould be n + 2 lines of output. the first line of output shocould read intersecting lines output. there will then be one line of output for each pair of planar lines represented by a line of input, describing how the lines in

1350. Crossing the Desert descriptionPrincess Zelda has been taken away again. link in order to find her need to cross the Jaolanaro desert, the bad news is that link may not have enough strength to cross the desert, the good news is that the desert is distributed with the fruit of n forces, the bad news is that our link can only go straight. In order to cross the desert, link hopes to eat as much of the fruit of the force as possible. Now ask you to

Title: "Python uses DDA algorithm and midpoint Bresenham algorithm to draw straight line"date:2018-06-11t19:28:02+08:00Tags: ["Graphic science"]Categories: ["Python"] First onCode#!/usr/bin/env python# Coding=utf-8 fromPylabImport * fromMatplotlib.tickerImportMultiplelocatorImportMatplotlib.patches asPatches'''1. Input line ends Point x0,y0 xn,yn2. Calculate initial value delta_x, delta_y,k=delta_y/delta_x,d=0, X=x0,y=y03. Plot point x, y4. D Up

Let's take a look at the effect chart:I just do the interface need to make a point sag in the page line, and strive after half an hour of research. Sum up the rules of them! There is a good way of course to share to everyone. Hope to be helpful to everybody!Such a sunken straight line! are generally composed of up and down two lines of a single pixel line together! And then through the color difference! Poor students sag effect, it is estimated that a

It's not very clear in the textbook about this section.Part of the content is referenced from: http://www.cnblogs.com/frog112111/archive/2012/08/19/2646012.htmlExtended Euclidean algorithmBasic algorithm: For a non-negative integer A,B,GCD (A, B) that is not exactly 0, the greatest common divisor of A/b is bound to have an integer pair of x, Y, which makes gcd (A, b) =ax+by.The application of the extended Euclidean algorithm mainly has the following three aspects:(1) solving indefinite equation;

1. The idea of direct insertion sequencing:Insert a record into an ordered table that is already ordered, resulting in a new, sequential table with a 1 increase in the number of records.1 voidInsertsort (SqList *L)2 {3 intI, J;4 for(i=2; i)5 {6 if(L->r[i] 1])7 {8l->r[0] = l->R[i];9 for(j=i-1; L-GT;R[J] > l->r[0]; j--)Ten { Onel->r[j+1] = l->R[j]; A } -l->r[j+1] = l->r[0]; - } the } -}2. Direct insertion sorting complex

#first, mathematical functions are introducedImportMath#create a class of pointsclassPoint ():#the coordinates of the initialization point (x, y) def __init__(self,x=0,y=0): self.x=x self.y=y#gets the x-axis coordinates of a point defGetX (self):returnself.x#get the y-coordinate of a point defGetY (self):returnSelf.y#define a class of linesclassLine ():#two points of the initialization line def __init__(SELF,P1,P2): self.x= P1.getx ()-p2.getx () self.y= P1.gety ()-p2.gety ()#Pythagor

: \ (z\) the great ideal only \ (\langle p\rangle\).3. Straight and decomposition 3.1 straight andIn group theory, we can see that the straight integral solution is the best method to deconstruct the group, and the thought is also applied to the ring. To ring \ (r_1,r_2,\cdots,r_n\), easy proof set \ (r=\{(a_1,a_2,\cdots,a_n) \mid a_k\in r_k\}\) also forms a ring

Geometric straight line and angle of a plane Straight Line (Not defined) a straight line is infinitely extending to two parties, and it has no endpoint. Ray The part next to a point in a straight line. Rays have only one endpoint. Line Segment The part between two points in a

Opengl basic learning topic (2) vertices, straight lines, and polygon Digress As learning grows, I feel more and more confused. In the previous blog, we recommend that you use a simplec framework based on VS2015 to learn opengl. Some problems. 1. The Release version is not considered in the VS Debug mode. 2. In this version, some Macros in the basic header files of chead and c are poorly designed, such // 4.0 print the error message on the console #

Link: http://poj.org/problem? Id = 1039 http://acm.hust.edu.cn/vjudge/contest/view.action? Cid = 22013 # Problem/bpipe Time limit:1000 ms Memory limit:10000 K Total submissions:8350 Accepted:2501 DescriptionThe GX light pipeline company started to prepare bent pipes for the new transgalactic light pipeline. during the design phase of the new pipe shape the company ran into the problem of determining how far the light can reach inside each component of the pi

VC Image ProcessingProgramLine Detection is often used, and the commonly used line detection method is the Hough transformation. As one of the basic methods for recognizing geometric shapes in image processing. The basic principle of Hough transformation is to convert the given curve of the original image space into a point in the parameter space through curve expression by using the parity between the point and the line. In this way, the detection problem of the given curve in the original im