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With the release and Implementation of the Fast Ethernet standard, cat5e twisted pair wires have been widely used in network cabling. However, due to the misleading publicity by some vendors and network companies, and the lack of necessary knowledge about related standards by some network users, it is hard to identify the true and false of the cat5e twisted pair. However, the selection of non-compliant
Cat5e and cat6 twisted pair wires have entered the stage of diversified products and diversified classification. When installing the cabling system, people may have to choose products of Category 5, Category 5, Category 5, or Category 6. For the verification test of the cabling system, the standards for on-site testing lags behind products on the market. as we all know, the testing standard is required for the twisted pair link installed and tested on
The distance from the midpoint of a §4 space to a line or plane.
1. Distance from point to plane
The normal equation for 1o plane P is:
The distance from the point m (XO, Yo, zo) to the plane P is:
The general equation for the 2o plane P is:
The distance from the point m (XO, Yo, zo) to the plane P is:
2. Distance from point to line
The symmetric equation for the line L is:
(Straight line over M1 (x1, y1, Z1) point, direction number p, Q, R)
Th
Mirror and light
Time Limit: 2000/1000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)Total submission (s): 814 accepted submission (s): 385Problem descriptionthe light travels in a straight line and always goes in the minimal path between two points, are the basic laws of optics.
Now, our problem is that, if a branch of light goes into a large and infinite mirror, of course, it will reflect, and leave away the mirror in another direction.
Question: I will give you a straight line and several circles, and find out the proportion of the length of the circle and the straight line to the whole line.
Solution: calculate the percentage of the Cross-circle between the circle and the straight line by using the method of determining the ratio of points.
Step 1: (determine whether the projection direction i
1. Let's test the "drawing" menu: Click "View"-"toolbar" on the menu, and find "drawing" as shown in the following screenshot.2. We can see a "drawing" menu in the toolbar on the word menu bar.3. If I want to draw a straight line now, click "draw", hold it down, and drag a straight line;4. In this way, the
Someone asked me on the snow watching forum. So I wrote this code by the way.
Q: I encountered this problem when writing code. Set the points A (100,100) and B (200,200) to a straight line. How can I get, b: All vertices in a straight line connected by two points. The brother can give a formula. Thank you first.A: We can use the vectors to obtain the result in collinearity. I learned this in middle school:I
1. inkcanvas class.
Inkcanvas is required to implement the canvas. Generally, noCodeYou can draw a line on it.
If you need to set the paint brush color and pen tip size, you need to set defadradrawingattributes, for example:
Drawingattributes attributes = new drawingattributes (); Attributes. Color = colors. Black; Attributes. Height = 50; Attributes. width = 50; Attributes. fittocurve = true;
2. draw a straight line on inkcanvas
Method: Mod
Determine whether two straight lines are intersecting in 3D space
Straight line r1 (S) = O1 + S * D1
Straight line R2 (t) = O2 + T * D2
R1 (S) = R2 (t)
=> O1 + S * D1 = O2 + T * D2
=> S * D1 × d2 = (o2-o1 + T * D2) × d2
T * D2 × d1 = (01-02 + S * D1) × d1
=> Because D x D = 0
=> S * (d1 × d2) = (o2-o1) × d2
T * (D2 × d1) = (o1-o2) × d1
=> S * (d1 × d2)
x1y1x2y2x3y3x4y4.Thus each of these input lines represents two lines on the plane: The line through (x1, Y1) and (X2, Y2) and the line through (X3, Y3) and (X4, y4 ). the point (x1, Y1) is always distinct from (X2, Y2 ). likewise with (X3, Y3) and (X4, Y4 ).OutputThere shoshould be n + 2 lines of output. the first line of output shocould read intersecting lines output. there will then be one line of output for each pair of planar lines represented by a line of input, describing how the lines in
1350. Crossing the Desert descriptionPrincess Zelda has been taken away again. link in order to find her need to cross the Jaolanaro desert, the bad news is that link may not have enough strength to cross the desert, the good news is that the desert is distributed with the fruit of n forces, the bad news is that our link can only go straight. In order to cross the desert, link hopes to eat as much of the fruit of the force as possible. Now ask you to
Title: "Python uses DDA algorithm and midpoint Bresenham algorithm to draw straight line"date:2018-06-11t19:28:02+08:00Tags: ["Graphic science"]Categories: ["Python"]
First onCode#!/usr/bin/env python# Coding=utf-8 fromPylabImport * fromMatplotlib.tickerImportMultiplelocatorImportMatplotlib.patches asPatches'''1. Input line ends Point x0,y0 xn,yn2. Calculate initial value delta_x, delta_y,k=delta_y/delta_x,d=0, X=x0,y=y03. Plot point x, y4. D Up
Let's take a look at the effect chart:I just do the interface need to make a point sag in the page line, and strive after half an hour of research. Sum up the rules of them! There is a good way of course to share to everyone. Hope to be helpful to everybody!Such a sunken straight line! are generally composed of up and down two lines of a single pixel line together! And then through the color difference! Poor students sag effect, it is estimated that a
It's not very clear in the textbook about this section.Part of the content is referenced from: http://www.cnblogs.com/frog112111/archive/2012/08/19/2646012.htmlExtended Euclidean algorithmBasic algorithm: For a non-negative integer A,B,GCD (A, B) that is not exactly 0, the greatest common divisor of A/b is bound to have an integer pair of x, Y, which makes gcd (A, b) =ax+by.The application of the extended Euclidean algorithm mainly has the following three aspects:(1) solving indefinite equation;
1. The idea of direct insertion sequencing:Insert a record into an ordered table that is already ordered, resulting in a new, sequential table with a 1 increase in the number of records.1 voidInsertsort (SqList *L)2 {3 intI, J;4 for(i=2; i)5 {6 if(L->r[i] 1])7 {8l->r[0] = l->R[i];9 for(j=i-1; L-GT;R[J] > l->r[0]; j--)Ten { Onel->r[j+1] = l->R[j]; A } -l->r[j+1] = l->r[0]; - } the } -}2. Direct insertion sorting complex
#first, mathematical functions are introducedImportMath#create a class of pointsclassPoint ():#the coordinates of the initialization point (x, y) def __init__(self,x=0,y=0): self.x=x self.y=y#gets the x-axis coordinates of a point defGetX (self):returnself.x#get the y-coordinate of a point defGetY (self):returnSelf.y#define a class of linesclassLine ():#two points of the initialization line def __init__(SELF,P1,P2): self.x= P1.getx ()-p2.getx () self.y= P1.gety ()-p2.gety ()#Pythagor
: \ (z\) the great ideal only \ (\langle p\rangle\).3. Straight and decomposition 3.1 straight andIn group theory, we can see that the straight integral solution is the best method to deconstruct the group, and the thought is also applied to the ring. To ring \ (r_1,r_2,\cdots,r_n\), easy proof set \ (r=\{(a_1,a_2,\cdots,a_n) \mid a_k\in r_k\}\) also forms a ring
§ 7 straight lines of a Quadratic Surface
IDefinition: A surface formed by a set of continuously changing straight lines is calledStraight SurfaceEach line is called its bus.
Note: The cylindrical surface and cone surface are both straight surface, but the elliptical surface, dual-blade dual-surface and elliptical parabolic surface are not
Geometric straight line and angle of a plane
Straight Line
(Not defined) a straight line is infinitely extending to two parties, and it has no endpoint.
Ray
The part next to a point in a straight line. Rays have only one endpoint.
Line Segment
The part between two points in a
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