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...). Ln2Returns the natural logarithm of 2 (LN 2 ). Ln10Returns the natural logarithm of 10 (ln 10 ). Log2eReturns the logarithm of low E (log2e ). Log10eReturns the logarithm (log10e) of E with a lower value of 10 ). PiReturns π (1415926535 ...). Sqrt1_2Returns the square root of 1/2. Sqrt2Returns the square root of 2. Method ABS (X)Returns the absolute value of X. ACOs (X)Returns the arc cosine of X (the cosine is equal to the angle of X), expressed in radians. Asin (X)Returns the arc sine o

#! /bin/bashRead-p "Pleaswe input number" nEcho $n========Read-t 3-p "Pleaswe input number" N T is the time-out===============Vim 4.sh#! /bin/bashEchoecho $EchoInput parameters of the time of the output is itself 4.shVim 5.sh#!/bin/bashn1=0While :;: denotes true meaning, or it can be 1 Doread-p "Please inpty a number:" Nm= ' echo $n |sed ' s/[0-9]//g ' m is to remove all the numbers and decide if it's empty

| D1) = 1/2 P (q| D2) = 1/2 question 3 probability smoothing avoids assigning zero probabilities to unseen words in documents. True False Question 4 Assume you are given two scoring functions: S1 (q,d) =p (q| D S2 (q,d) =logp (q| D For the same query and corpus, s1and S2will give the same ranked list of documents. True False Question 5 assume you are using linear interpolation (jelinek-mercer) smoothing to estimate the probabilities O F words in a ce

Order 3 I am not qualified to give up No matter how many times it will be reversed, I should be strong; even if it hurts to cry, I should smile and cry; because, I have no shoulders to rely on; no hands to help me. Everything must be done by yourself! Therefore, I am not qualified to give up. I have no reason, that is, "I am not qualified to give up "! First of all, I would like to thank my privileged Brother Wu houhang and his brother Zhang Yafeng

; System.out.println ("Simple interest End value is f:" +Df1.format (F)); F=0; System.out.print ("Please enter the number of compounding times:"); Doublem =scanner.nextdouble (); F=p* (Math.pow (1+r/m), nm)); System.out.println ("End value of compound interest is f:" +Df1.format (F)); } if(num==2){ DoubleH=1, P; System.out.print ("Please enter the end value of compound interest F:"); DoubleF =scanner.nextdouble (); System.out.print

One, handling stringsSpecial symbols▎ How do I use special symbols within a string?>>> text1= ' His cat's name is Tom. 'File "▎ Escape Character:\ ' Single quotation mark\ "Double quotation marks\ t tab\ n line break\ \ Inverted Slash>>> print ("\this Cat's name is \ntom.") His cat ' s name istom.Sanchong quotation marksThe starting and ending of a multiline string is 3 single or 3 double quotation marks. A

Week 3 Quizhelp Center Warning:the hard deadline has passed. You can attempt it, but and you won't be. You are are welcome to try it as a learning exercise. In accordance with the Coursera Honor Code, I certify this answers here are I own work. Question 1 Assume you are using a Unigram language model to calculate the probabilities of phrases. Then, the probabilities of generating the phrases "study text mining" and "text mining study" are not equal, i

only one element in the element list and this element is a positive integer, this defines an array containing Note: JavaScript only has a one-dimensional array! Do not use the stupid method "Array (3, 4)" to define a 4x5 Two-dimensional Array, or use the "myArray [2, 3]" method to return the elements in the "two-dimensional array. For any call in the form of "myArray [...,

the array, use: var For example, var myarray = new Array (1, 4.5, ' Hi '); Defines an array myarray, inside the element is: myarray[0] = = 1; MYARRAY[1] = = 4.5; MYARRAY[2] = = ' Hi '. However, if there is only one element in the list of elements, and the element is a positive integer, this defines an array containing the Note: JavaScript has only one-dimensional arrays! Never use the stupid method of "array (3,4)" to define a two-dimensional array of 4 x 5, or use the "myarray[2,3"

An arrayAA is stored inNN>0>0) Integer to move each integer loop to the right without allowing the use of a different arrayMM\ge 0≥0) a position that willAThe data in a is determined by (A_0 a_1 \cdots A_{n-1}A?0??A?1???A?N?1?? ) Transformation to (A_{N-M} \cdots a_{n-1} a_0 a_1 \cdots a_{n-m-1}A?N?M???A?N?1??A?0??A?1???a?Nm? 1?? ) (Last mm number of loops moved to the front m locations). If you need to consider the number of times a program moves dat