cisco 3524

DescriptionInput Output10 3 1 2 1 2 1 2 3 2 3 3 8 1 2 1 3 1 4 1 5 2 5 2 6 6 9 7 10Sample InputNoYes 1NoYes 1NoYes 2NoYes 3Sample Output HINTNotice: The second integer input is the range of weights in the sequence Lim, i.e. 1Still Chairman tree template, without discretization.1Source1#include 2#include 3#include 4 #defineN 100000105 using namespacestd;6 intsum[n],root[500010],ls[n],rs[n];7 intN,m,lim,sz;8 voidUpdata (intLintRintXinty,intv)9 {Teny=++sz; Onesum[y]=sum[x]+1; ALS[Y]=LS[X]; rs[y]=Rs[

Main topicGive a sequence that asks if there are more than half the numbers in the interval.IdeasUse the Chairman tree to take the interval out and find it in the weight segment tree.CODE#define _crt_secure_no_warnings#include #include #include #include #define MAX 500010#define MAXR 10000010using namespace STD;structsegtree{Segtree *son[2];intCNT;} MEMPOOL[MAXR], *c = Mempool, *root[max]; Segtree *newsegtree (Segtree *_, Segtree *__,int___) {c->son[0] = _; c->son[1] = __; c->cnt = ___;returnC +

]); } } for(k = tw[tp]; k k) {//Full Backpack if(Dp[tp][k] TV[TP]) {Dp[tp][k]= DP[TP][K-TW[TP]] +TV[TP]; POWER[TP][K]= power[tp][k-TW[TP]]; } Else if(Dp[tp][k] = = dp[tp][k-tw[tp]]+TV[TP]) power[tp][k]= Min (power[tp][k],power[tp][k-TW[TP]]); } for(k =0; K k) {//Update Answer if(Dp[tp][k] >ans) ans= Dp[tp][k],dist =Power[tp][k]; Else if(Dp[tp][k] = =ans) Dist=min (dist,power[tp][k]); } //pf ("cur%d:\n", cu

Tag: www + + scan sum put scanf int while output 3524: [poi2014]couriers time limit:20 Sec Memory limit:256 MBsubmit:1905 solved:691[Submit] [Status] [Discuss] DescriptionGive a sequence of length n. 1≤a[i]≤n.The M-group asks, each time an interval [l,r] is asked, if there is a number that appears in [L,r] greater than (r-l+1)/2. If present, output this number, otherwise output 0.InputThe first line is two numbers n,m.Second row n num

if (S > V, r, R, S-l)return Query (L-R, R-r, M + 1, R);return 0;}int main () {freopen ("test.in", "R", stdin);root[0] = pt++;int n, m;cin >> n >> m;Rep (i, N) {scanf ("%d", v);root[i + 1] = Modify (root[i], 1, n);}While (m--) {int L, R;scanf ("%d%d", l, r);v = (r-l + 1) >> 1;printf ("%d\n", Query (root[l-1], root[R], 1, N));}return 0;}---------------------------------------------------------------------------------------------- 3524: [Poi2014

Apache OpenOffice Calc Command Injection Vulnerability (CVE-2014-3524) Release date:Updated on: Affected Systems:OpenOfficeUnaffected system:OpenOffice Description:--------------------------------------------------------------------------------Bugtraq id: 69351CVE (CAN) ID: CVE-2014-3524OpenOffice was originally Sun's commercial Office software-StarOffice. After Sun's public code, it was officially named OpenOffice development plan.OpenOffice 4.1.0 an

];voidUpdateintPintq,intLintRintV) {seg[++size]=seg[p],q=size; seg[q].sum++;if(L==R)return;intMid= (l+r) >>1;if(vElseUpdate (seg[p].rson,seg[q].rson,mid+1, r,v);}intQueintLintRintLintRintK) {if(L==R)returnLintMid= (l+r) >>1;if(seg[seg[r].lson].sum-seg[seg[l].lson].sum>k) {returnQue (seg[l].lson,seg[r].lson,l,mid,k); }if(seg[seg[r].rson].sum-seg[seg[l].rson].sum>k) {returnQue (seg[l].rson,seg[r].rson,mid+1, r,k); }return 0;}intN,m;intMain () {scanf("%d%d", n,m); for(intI=1; iintXscanf("%d", x); U

Hdu 3524 Perfect Squares inverse element Perfect Squares Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission (s): 501 Accepted Submission (s): 272 Problem Description A number x is called a perfect square if there exists an integer B Satisfying x = B ^ 2. there are too beautiful theorems about perfect squares in mathematics. among which, Pythagoras Theorem is the most famous. it says that if the length of

Half a year five acquisitions Cisco intensive integration for self-redemptionWu MicroCisco, a "takeover guru", recently announced a new deal.The acquisition was Cloudlock, a cloud security company, with a total transaction price of $293 million. This is the fifth takeover deal that Cisco has launched this year.As the world's largest network equipment manufacturer, Cisco