complex number calculator 1940

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How to optimize complex report computing with a set calculator (1) Data Source set

How to optimize complex report computing with a set calculator (1) Data Source setThere are many examples of how the calculator assists in report computing, but most of the computing difficulties occur before the data enters the report tool, for example, many cases of text computing and SQL assistance listed above are for report development. In addition, some

How to optimize complex report computing by the set calculator (1) Data Source set and report Optimization

How to optimize complex report computing by the set calculator (1) Data Source set and report Optimization There are many examples of how the calculator assists in report computing, but most of the computing difficulties occur before the data enters the report tool, for example, many cases of text computing and SQL assistance listed above are for report developme

Simple implementation of C + + complex calculator _c language

The example of this article for everyone to share the simple implementation of C + + complex calculator specific code, for your reference, the specific content as follows 1. Functions related to calculatorsA, to implement the subtraction, size comparison of multiple complex numbers (including real numbers),B. Implementation of decimal real-system conversion, can

Python Analog Casio Complex calculator "in construction"

1. Pre-preparation for the parentheses have such a rule:--Only ( can be more than ) the number, at this time at the end of the line complement).--Take the mold |...| cannot be nested. (There is no problem with Casio, because you will get two | Each time you press the modulo key, so you can define their size)The calculator has the following functions:--Basic subtraction: 1+2, 3/4-Power: 3^2--Take the mold: |

Using Python to implement a complex formula calculator function

forIinchLi:ifi = ='+': I=0 Nums= Nums +float (i)returnStr (nums)defSimple (x):#handle without parentheses. returnJia_jian (Cheng_chu (x))defJisuan (x):#Handle the parentheses while '(' inchX:reg= Re.compile (r'\([^\(\)]+\)') Ma=Re.search (Reg, X). Group () result= Simple (ma[1:-1]) x= X.replace (MA, result, 1) returnSimple (x)' 1-2.99 * ((60.2-30 + ( -40/5) * (9-2*5/3 + 7/3*99/4*2998 +10.5 * 568/14))-( -4*3)/(16-3*2) ) '. Replace (' ")print(' your results:') , Jisuan (ss))print('eval

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