computational geometry book

Source=%e8%ae%a1%e7%ae%97%e5%87%a0%e4%bd%95%e5%9f%ba%e7%a1%80 "style=" text-decoration:none; Color:rgb (55,119,188) "> Computational Geometry Fundamentals uploaded by Zhang Yunzun When you start to do this problem, you always draw on the draft paper. Infer how many cases, just think that the situation is more, may not consider the overall, beginn

On the net to find a three-dimensional computational geometry template, perfect a bit, so that it can use ...#include Three-dimensional computational geometry template

Test instructions: Xiao Ming to buy three houses, the three houses constitute a triangle, known as the coordinates of the house N, any three houses are not in a straight line, but also known as the coordinates of the M treasure, asked the house composed of triangles within the triangle has an odd number of the triangle there are many. Data range: N (3~100), M (1~1000)Analysis:Simple computational geometry.

This article is a turn, the original http://blianchen.blog.163.com/blog/static/13105629920103614613291/Before continuing with the following NAV mesh generation algorithm, let's introduce the computational geometry involved. Here are only a list of the conclusions, to learn more about the reference related books. Vector Plus subtraction:To set the two-dimensional vector p = (x1, y1), Q = (x2, y2), the ve

First, DirectoryThe basic concepts of computational geometry and common algorithms in this paper include the following:1. The concept of vectors2. Vector addition and subtraction3. Vector Cross Product4. The turn judgment of the broken line5. Determine if the point is on a line segment6. Determine if two segments intersect7. Determine if line segments and lines intersect8. Determine if the rectangle contain

Doublea0,b0,c0,a1,b1,c1,d; ata0=t0.y-t1.y; -b0=t1.x-t0.x; -c0=t0.x*t1.y-t1.x*t0.y; -a1=k0.y-k1.y; -b1=k1.x-k0.x; -c1=k0.x*k1.y-k1.x*k0.y; inD=a0*b1-a1*B0; -o.x= (B0*C1-B1*C0)/D; too.y= (A1*C0-A0*C1)/D; + returno; - } the DoubleINS (point A,point B)//the modulus of finding vectors * { $ returnsqrt ((a.x-b.x) * (a.x-b.x) + (A.Y-B.Y) * (a.y-b.y));Panax Notoginseng } - DoubleDot (point a,point o,point B)//multiply two vector coordinates the { + return(o.x-a.x) * (o.x-b.x) + (O.Y-A.Y

Calculate the geometric headache place generally lies in the code quantity and the accuracy question, the code quantity question as long as usual attention accumulates the template general to be not the problem. Accuracy problem is not good to say, sometimes a precision problem may become a bottleneck, simply "finishing touch." These years of the topic is basically toward more and more the direction of the accuracy of the development, but there are some%^% problems #$%$^, in addition to some com

the height of the juice, can you find the volume of the remaining juice in the glass? " Then the programmer kissed he wife and said, "You is the best problem setter in the world!"Now he sets the same problem for you. The radius of the upper part R1 and lower part R2 is given. If height of the glass is H and height of the juice are p What are the volume of the juice in the glass?InputInput starts with an integer T (≤100), denoting the number of test cases.Each case starts with a line containing

(Cross (U,V))/len (v);};structcircle{point P;DoubleR Circle (Point _p,Double_r): P (_p), R (_r) {} point point (Doublerad) {returnPoint (p.x+r*Cos(RAD), p.y+r*Sin(RAD)); }}; vectorLine_cross_circle (line l,circle c)//intersection of lines and circles{Line Dia (C.p,normal (L.V)); Point Inter=line_cross (dia,l);DoubleD=dis_point_line (Inter,dia);if(c.r-d0)return vector();Doublelen=sqrt(Sqr (C.R)-sqr (d)); vectorV V.push_back (Inter-unit (L.V) *len); V.push_back (Inter+unit (L.V) *len);}intConv

This article will introduce a basic and important tool in computational geometry-the cross product.Before we do that, we need to solve some basic problems first.Code representation of points and segmentsThe knowledge of a struct or class is well understood here, but how it is written in the specific coding process, based on the individual's great flexibility.For example, for points, it can be expressed in t

style= "Display:inline-block; width:0px; Height:2.616em; " > Code ：/**2016-08-04 Morning Author:itakmotto: Today I want to go beyond yesterday's me, tomorrow I want to surpass today's me, to create better code as the goal, constantly surpass oneself. **/#include #include #include #include #include #include #include #include #include using namespace STD;typedef Long LongLL;typedef unsigned Long LongULL;Const intINF =1e9+5;Const intMAXN =1e6+5;Const intMOD =1e9+7;Con

than 180, enumerate each point, and find its next target point (with the angle greater than 180 degrees) calculated.1#include 2 #definell Long Long3 #defineN 15054 using namespacestd;5 intn,tp;ll s1,s2;6 structp{7 intx, y;Doubleang;8Poperator- (ConstP b)Const{returnP {x-b.x,y-b.y};}9 BOOL operatorConstP b)Const{returnangB.ang;}Ten }a[n],q[n]; Onell CRS (P a,p b) {return(LL) a.x*b.y-(LL) a.y*b.x;} All solve (intx) { -tp=0; -ll all=1ll* (n1) * (n2) * (n3)/6; the for(intI=1; i){ -

Round and rectangular area intersectionor triangulation to do it.Code:#include ZOJ 2675 Little Mammoth (computational geometry)