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Because of the previous mention of the "qa-qd-61-151" host name problem, so the Java to get the host name of things to learn, and in the way of the Java get MAC address/IP address and so on methods.
According to the two articles in resources, the following is integrated to enable Java to obtain the
Each Ethernet device has a unique MAC address at the factory, why do I need to assign an IP address to each host? or if each host is assigned a unique IP address, why should a unique MAC
Copy Code code as follows:
The code was found on the internet, but it was modified.
The reason is that your notebook has more than one network card, will appear to get you do not network or disable the network card information, the solution: Add Restrictions:
Objobject.dnsserversearchorder!=null
With this restriction, you will be able to access the networking client's network card IP address
In network management, IP address theft often occurs, not only affecting the normal use of the network, but also because the stolen address often has high permissions, as a result, it also causes a lot of economic losses and potential security risks to users. Are there any measures to prevent such phenomena as much as possible? To prevent
C #
get local
IP
Address and
MAC
Address 1, obtain the LAN IP address through the host name; try { iphostentry iphostentry = Dns.gethostentry (Txthost.text);//pass Computer name if (ipHostEntry.Aliases.Length > 0) {
In the network management, the phenomenon of IP address embezzlement often occurs, not only affects the normal use of the network, at the same time, because the stolen address often has a higher privilege, it also causes a lot of economic losses and potential security risks to users. Are there any measures to minimize the occurrence of such phenomena? In order to
Reprinted please keep this article link: http://blog.csdn.net/sushengmiyan/article/details/8545673
{Hardware Author: sushengmiyan 2013.01.26 remarks: function: hardware information retrieval unit Units units} unit applicationhardwareinfo; interfaceuses windows, sysutils, classes, registry, nb30, Winsock; Type tcpuid = array [1 .. 4] of longint; function getcpuid: tcpuid; assembler; register; Type // cpuid Information Class tcpuidinf O = class private fcpuid: tcpuid; fcpuidstr: string; Procedure
I was so happy to receive two CDs of Ubuntu7.10, each of which is 32-bit and 64-bit, sent by the Netherlands free mail. It took more than an hour to successfully install it on the old machine. Because the school IP address is bound to the MAC address, the old machine cannot obtain the
The following actions are done in the Command Prompt window.Known IP, how to get the computer nameMethod (1):Use Ping-i IP AddressFor example, the known address is 192.168.1.168.Then use Ping-i 192.168.1.168 if you can ping the computer. You can get the name of the computerMethod (2):Use Nbtstat-a plus IP to check the
Obtain the local IP address and MAC address in AndroidUse InetAddress. getLocalHost () to obtain "127.0.0.1". To obtain a real network IP address, use the following method:First, create a project and modify the AndroidManifest. xm
The project requires the MAC address and IP address of the client, but many examples are found on the Internet. However, after testing, the server code is obtained. Later, I saw an article saying, the client's MAC address cannot b
You can use the following code to get the MAC address, depending on your actual needs./*** get MAC address * @param ipAddress127.0.0.1* @return based on IP address * @throws SocketException* @throws unknownhostexception*/publicst
Writing "using remoting technology to push messages", in which messages are pushed to the client. At this time, you must know some information about the client, such as the IP address and port. Here, we first obtain the IP address and MAC
The DNS method is simple and practical to obtain the IP address of a server, as follows:
The following is a reference clip:Private void buttonip_click (Object sender, system. eventargs E){System. net. IPaddress [] Addresslist = DNS. gethostbyname (DNS. gethostname (). Addresslist;If (Addresslist. length> 1){Textlip. Text = Addresslist [0]. tostring ();Textsip. Text = Addresslist [1]. tostring ();}Else{Text
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