csr 2 mod

D. Maximum Value time limit per test 1 second memory limit/test 256 megabytes input standard input output standard out Put You are given a sequence a consisting of n integers. Find the maximum possible value of (integer remainder Ai divided by AJ), where 1≤i, J≤n and Ai≥aj. Input The contains integer n-the length of the sequence (1≤n≤2 105). The second line contains n space-separated integers ai (1≤ai≤106). Output Print the answer to the problem. Samp

2^X mod n = 1Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 13341 Accepted Submission (s): 4143Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x ex

Time Limit: 2 seconds memory limit: 65536 KB Give a number N, find the minimum X that satisfies 2 ^ x mod n = 1. Input One positive integer on each line, the value of N. Output If the minimum x exists, print a line with 2 ^ x mod n = 1. Print

2^X mod n = 1Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 14349 Accepted Submission (s): 4438Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x ex

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 13952 ^ x mod n = 1 Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 12146 accepted submission (s): 3797Problem descriptiongive a number N, find the minimum x (x> 0) that satisfies 2 ^ x mod n = 1. Inputone positive integer on each line, the value o

This question requires the smallest positive integer x, N> 0 that satisfies 2 ^ x limit 1 (mod N. First consider the Euler's Theorem 2 ^ Eular (n) limit 1 (mod N), which requires n> 1. So when n = 1, in fact, all K numbers have k limit 0 (mod N), which is a special decisio

/*2 ^ x mod n = 1Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 11800 accepted submission (s): 3673Problem descriptionGive a number N, find the minimum x (x> 0) that satisfies 2 ^ x mod n = 1. InputOne positive integer on each line, the value of N. OutputIf the min

Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 13345 Accepted Submission (s): 4146Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x exists, print a line with 2^x

2 ^ x mod n = 1 Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 11542 accepted submission (s): 3577 Problem descriptiongive a number N, find the minimum x (x> 0) that satisfies 2 ^ x mod n = 1. Inputone positive integer on each line, the value of N. Outputif the

2^X mod n = 1Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 13610 Accepted Submission (s): 4208Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x exi

Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others) Total Submission (s): 14494 Accepted Submission (s): 4484Problem descriptiongive a number n, find the minimum x (x>0) that satisfies 2^x mod n = 1.Inputone positive integer on each line, the value of N.Outputif the minimum x exists, print a line with 2^x

Question: Returns a positive integer n, and returns the smallest x so that 2 ^ x mod n = 1. Ideas: N = 1. All positive mod 1 values are 0. N is an even number, why? The above formula can be deformed as follows: 2 ^ x = k * n + 1. If n is an even number, k * n + 1 is an odd number, and

In this question, 2 ^ X is obtained cyclically and then mod n = 1, and the time exceeds. Use mathematical formula (M * n) % d = (M % d * n % d) % d to simplify the scenario. The Code is as follows: # Include

Strategy: we can see that the remainder is not equal to 1 or the number that can be divisible by 2. We only need to judge whether it is an odd number other than 1, search for 2 ^ X (mod (N) in sequence ))? = 1.Difficulty: if every time it is based on the original × 2, it will time out. At this time, we can use the same