dance dance revolution xbox 360 pad

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UVa 1291-dance Dance Revolution (DP)

Dance Dance RevolutionTime Limit: the MsMemory Limit: 0 Kb64bit IO Format: %lld %llu Submit Status DescriptionMr White, a fat man, and now are crazy about a game named "Dance, Dance, Revolution". But his dance skill was so poor

UVALive-2031 Dance Dance Revolution three-dimensional DP

][i-1] +1;ElseDp[seQ[i]][j][i] = Dp[seQ[i-1]][j][i-1] + strength[(SEQ[i-1]+ SEQ[i]) %2]; }if(j = = SEQ[i]|| SeQ[i-1]= = SEQ[i]) Dp[seQ[i-1]][j][i] = min (dp[seQ[i-1]][j][i],dp[seQ[i-1]][j][i-1] +1);Else{Dp[seQ[i]][seQ[i-1]][i] = min (dp[seQ[i-1]][j][i-1] + strength[(j + SEQ[i]) %2], Dp[seQ[i]][seQ[i-1]][i]); Dp[seQ[i]][j][i] = min (dp[seQ[i-1]][j][i-1] + strength[(SEQ[i-1]+ SEQ[i]) %2], Dp[seQ[i]][j][i]); } } } }intans = INF; for(inti =0; I 5; i++) ans = min (min (ans, dp[se

Recursive DP UVA 1291 Dance Dance Revolution

) ret =1; + Else { - if(Y = =0) ret =2; $ Else { $ if(ABS (x-y) = =2) { -RET =4; - } the ElseRET =3; - }Wuyi } the returnret; - } Wu - intMainvoid) {//UVA 1291 Dance Dance Revolution About intn =0; $ while(SCANF ("%d", a[++n]) = =1) { - if(a[1] ==0) Break; -

UVA 1291-dance Dance Revolution (DP)

Title: There are 4 positions, each moving from one position to another requires a specific cost, the minimum cost of a sequence of specified sequences. Only one foot at a time can move, or move and step down.Use D[i][j][u] to indicate that the first I position is complete and the minimum cost in the state (J,u), (J,u) One of which must be equal to A[i], assuming J and A[i] are equal, then either the previous state is (j,u), or the previous state is (k,u), note that the previous state cannot be (

Ultraviolet A 1291-Dance Revolution (dp)

physical strength required when the status is (j, k)It is not difficult to introduce the transfer equation: Assuming that the current step is in s, all the statuses that match this step are:F (I, 0 .. 4, s), f (I, s, 0... 4) Then we can roll out the minimum physical call fees for the next step based on the above status. Assume that the next step is next. So If f (I, j, s), (0 The next status is available.F (I + 1, j, s) = f (I, j, k) + 1; // stopF (I + 1, next, s) = min {f (I, j, s) + consume (

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