data structures and algorithms coding interview questions

is more complex because: Need to handle different node types, very cumbersome A multiple comparison operation is required to move the node down Need to move up to split the 4-node node There are a number of scenarios for splitting 4-node nodes 2-3 Find trees are more complex to implement, and in some cases the balancing operation after insertion may result in reduced efficiency. The improved red-black tree based on the 2-3 find tree is not only more efficient, but also

algorithm is O (NLOGN).2: Worst of all, that's what I'm talking about. The maximum and minimum values are selected:Then look at the worst-case fast-track, when the sequence to be sorted is in a positive or reverse order, and each partition has only one sub-sequence that is less than the last one, noting that the other is empty. If the recursive tree is drawn, it is a diagonal tree. You need to perform a n‐1 recursive call at this time, and the first Division I need to go through the N‐i keyword

;//I fall back to the next last match firstj =0;//J fallback to the first of the substring } if(J = =searchstr.length) {returnIJ; } }}I is the subscript positioning of the main string, and J is the subscript location of the substring.When the main string string is equal, it enters the loop mode of the substring, and when the number of cycles J satisfies the substring length, the validation is exactly the same.When the main string string is not equal, it is necessary to move the

indicates that the small o is used to describe the progressive upper bound of an algorithm, both gradually approaching. large Ω indicates that the large ω is used to describe the progressive lower bound of an algorithm. small Ω indicates that the small ω is used to describe the progressive lower bound of an algorithm, which is gradually approaching. thetaθ says Thetaθ is used to describe an algorithm's true bounds, including the minimum upper bound and the maximum lower bound. thought it was

numbers, so the time complexity cannot exceed N2.The basic idea of the improved sorting algorithm is "decomposition": select an appropriate keyword and divide a sorting task into two small sorting tasks. Ideally, the keyword can always break down the original sorting task into two groups of sorting tasks with the same length. Therefore, in the next round of sorting, you only need to compare in this group (the length is 1/2 of the previous round ). This process is equivalent to a binary sorting

, while (!thestack.isempty ()) {int Currentvertex = Thestack.peek (); int v = Getadjunvisitedvertex (Currentvertex); if (v = =-1) {Thestack.pop ();} else{vertexlist[v].wasvisited = True;thestack.push (v);d Isplayvertex (Currentvertex);d Isplayvertex (v); System.out.print ("");}} Search complete, initialize, for the next search for (int i = 0; i 5. SummaryThe graph is made up of vertices connected by edges, which can represent many real world situations, including aircraft routes, electronic circ

() method in the Bubblesort.java program (listing 3.1) with the Oddevensort () method . Make sure it runs in a sort of different amount of data, and that you need to figure out the number of two scans. Parity Ordering is actually useful in multiprocessor environments where the processor can process each odd pair at the same time, and then handle even pairs at the same time. Because the odd pairs are independent of each other, each pair can be compar

their definitions into a hash list; The second part lets the user enter a word, and the program gives the definition of the word.// 字典类function Dict () { this.hashTable = new HashTable(); this.save = save; this.find = find;}function save (word, description) { this.hashTable.put(word, description);}function find (word) { return this.hashTable.get(word);}// 示例let d = new Dict();d.save('Mazey', 'a strong man.');d.save('Cherrie', 'a beautiful girl.');d.save('John', 'unknown.');consol

){ if(Array[j] key) {Array[i+ +] = Array[j];//A[i] = a[j]; i + = 1; Break; }; } for(; i ){ if(Array[i] >key) {Array[j--] =Array[i]; Break; }}} Array[i]=key; Sort (0, i); Sort (i+ 1, numsize); }} sort (0, Array.Length); returnArray;}There is also an easy-to-understand approach:Set two empty arrays left and right, traverse the entire array, and push in to leave if it encounters less critical

,elemtype e){int j,k,l;K = max_size-1;if (i{return ERROR;}j = malloc_sll (L);//Call the function written above,if (j){L[j].data = e;for (l=1;l{K = L[k].cur;}L[j].cur = L[k].cur;L[k].cur = j;return OK;}return ERROR;}Delete operation650) this.width=650; "title=" 11.jpg "src=" http://s3.51cto.com/wyfs02/M02/57/28/wKioL1STg1TTn7fqAAHvw03C2fQ503.jpg "alt=" Wkiol1stg1ttn7fqaahvw03c2fq503.jpg "/>Sample codeStatus Listinsert (staticlinklist l,int i){int j,k;K

Optimal time complexity: O (n) (in ascending order, sequence already in ascending state) Worst time complexity: O (n2) Stability: Stable Code:"" "Insert sort Time complexity: O (n*n) Stability: Stable" "" "" Import randomimport timedef Insert_sort (list): n = len (list) # from the second position start inserting subscript 1 for J in Range (1,n): # Start comparison from the first J element if it is less than the previous element, the interchange position for

1. Select the principle of sorting2. Code implementationdefSelection_sort (alist): N=Len (alist)#requires a n-1 selection operation forIinchRange (n-1): #Record minimum positionMin_index =I#Select the minimum data from the i+1 position to the end forJinchRange (i+1, N):ifALIST[J] Alist[min_index]: Min_index=J#If the selected data is not in the correct location, swap ifMin_index! =I

Method Public BooleanDeleteLongvalue) { intj =find (value); if(j==Nelems) { return false; } Else { for(intK=j; k) {A[k]= A[k+1]; } nelems--; return true; } } //Binary Method Search Public intFindLongSearchkey) { intlowerbound = 0; intUpperbound = nElems-1; intCurin; while(true) {Curin= (lowerbound + upperbound)/2; if(a[curin]==Searchkey) { returnCurin;//found it } Else if

Simple single-linked list implementation, the data type is defined as an int, if you want to be generic, you need to change to a template class, and then slightly modified to the next.List.h#include Main.cpp#include "List.h" #include Output:There are some features not implemented, such as the insertion of elements in the specified location, linked list search, etc., because there is no iterator, with index do not be too good, simply do not write forge

. listsize; return This. listsize; }; This. Find =function(ele) { for(vari=0; i This. listsize; i++){ if( This. datastore[i] = = =ele) { returni; } } return-1; }; This. add=function(ele) { This. datastore[ This. listsize++] =Ele; }; This. Insert =function(Ele, Afterele) {varindex = This. Find (Afterele); if(Index >-1){ This. Datastore.splice (Index, 0, ele); This. listsize++; return true; }Else{ return false; } };

top element and adjust r[1..i-1] to new heap int temp = r[1];//Exchange heap top and base element r[1] = R[i];r[i] = Temp;heapadjust (r, 1, i-1);//Adjustment}}//has Know R[low. High] except R[low], the rest of the elements satisfy the definition of the heap private void Heapadjust (int[] r, int low, int.) {int temp = r[low];for (int j = 2 * low; J 　　C: algorithm ExampleHeapsort.javaPackage Com.test.sort.selection;public class Heapsort {/** * @param args */public static void main (string[] args)

the character before and after the pointer.while (p>s) { *p=*p^*s; *s=*p^*S; *p=*p^*S; p--; s++;} Question 3: How to find the first occurrence of a character in a stringMethod 1: Use the hash table to record the number of occurrences of each character, with the character as the array subscript, and the array size to 256. The first time the scan element will be character statistics, the second pass through to find the first count of 1 characters.Task 4: All subsets of a stringRef

, intersection, and difference operations. So, if you want to perform some normal collection operations on the keys of the collection, you can use the key view objects directly without first converting them to a set.The dictionary's items () method returns an element view object that contains (key, value) pairs. This object also supports collection operations and can be used to find out which two dictionaries have the same key-value pairs.Although the values () method of the dictionary is simila

Tag:prethread Array readinggen thought namelog time Using system;using system.collections.generic;using system.linq;using system.text;using System.Threading.Tasks; Namespace Insert Sort {class Program {static void Main (string[] args) {int[] Arry = {10,3,4,6,7 , 9,8,2,1,0}; Insertsortpro (Arry, 10); for (int i=0;i"Normal insert Sort" is slower than selecting sort, but optimized insert ordering is faster than selecting sort. Insert sort has a feature when the ar

the left to find an element that is larger than the base element, stop, the two elements are exchanged until two pointers meet, the end of the cycle * pointer point to the The position is where the datum element should be located in the collection * eg * {8,-2, 3, 9, 0, 1, 7, 6} * Benchmark * First bm=8 * end = Lengt h-1 = 7 * start=0 * End--, We found 6:8 small, end pointer stopped, current index is j=7 * start++, until element 9 stops, current index i=3 * Exchange the elements corresp