//TodayDateTime.Now.Date.ToShortDateString (); //yesterday, it was today's date minus one.DateTime.Now.AddDays (-1). ToShortDateString (); //tomorrow, in the same vein, add aDateTime.Now.AddDays (1). ToShortDateString (); //This week, knowing
//TodayDateTime.Now.Date.ToShortDateString (); //yesterday, it was today's date minus one.DateTime.Now.AddDays (-1). ToShortDateString (); //tomorrow, in the same vein, add aDateTime.Now.AddDays (1). ToShortDateString (); //This week, knowing
Today
DateTime.Now.Date.ToShortDateString ();
Yesterday, it was today's date minus one.
DateTime.Now.AddDays (-1). ToShortDateString ();
Tomorrow, in the same vein, add a
DateTime.Now.AddDays (1). ToShortDateString ();
This week,
//TodayDateTime.Now.Date.ToShortDateString (); //yesterday, it was today's date minus one.DateTime.Now.AddDays (-1). ToShortDateString (); //tomorrow, in the same vein, add aDateTime.Now.AddDays (1). ToShortDateString (); //This week, knowing
http://www.cnblogs.com/dekevin/p/4551843.html//TodayDateTime.Now.Date.ToShortDateString (); //yesterday, it was today's date minus one.DateTime.Now.AddDays (-1). ToShortDateString (); //tomorrow, in the same vein, add aDateTime.Now.AddDays (1).
Add and subtract based on the date passed in, integer is addition, negative number is subtraction, but day.Num can be passed in: 1,2,3,-1,-2,-3, and so on, the default is to add a day; date can be passed in: 2017-01-01 format, the default is the day
The SQL date minus DATEDIFF () returns the number of days between two dates. The definition and usage of the DATEDIFF () function returns the number of days between two dates. The syntax DATEDIFF (date1, date2) date1 and date2 are valid date and
Date D=new date ();SimpleDateFormat df=new SimpleDateFormat ("Yyyy-mm-dd");System.out.println ("Today's Date:" +df.format (d));System.out.println ("Two days ago Date:" + Df.format (new Date (D.gettime ()-(LONG) 2 * 24 * 60 * 60 *
One.(1) How many days to add or subtract the specified date(2) cycle the date between two specified datesCases:$start _time = ' 2017-07-01 ';$end _time = ' 2017-07-10 ';Get time difference$diff = Strtotime ($end _time)-strtotime ($start _time);$num =
MySQL Date TypeMySQL Date Type: Date format, occupied storage space, date range comparison.Date type storage space Date format date range------------ --------- --------------------- -----------------------------------------DateTime 8 bytes
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