dateadd hour

Generally, you need to obtain the current date and calculate some other dates. For example, your program may need to determine the first or last day of a month. Most of you probably know how to divide a date (year, month, day, and so on ), then,

T-SQL time operations (dateadd, datediff, datepart, datename), datepartdatename -- 1. current System Date and Time select getdate () -- 09:27:27. 277--2. the Time Operation dateadd returns the new datetime value dateadd (datepart, number, date)

Tag:sql    database     --1. Current system date, time select GETDATE ()--2015-01-06 09:27:27.277--2. The time operation DateAdd returns a new datetime value DATEADD (datepart, on the basis of adding a period of time to a specified date)

Example of how to use DATEADD and DATEDIFF in SQL, dateadddatediff Generally, you need to obtain the current date and calculate some other dates. For example, your program may need to determine the first or last day of a month. Most of you probably

1. Cast Cast (data as data_type)   Example: declare @ data int Set @ DATA = 5 Select cast (@ data as char (2) + 'abc'   -- Result: 5 ABC   2. Convert Convert (data_type, expresses (, style) -- style is the style of the specified date

PHP implementation of DateDiff and DateAdd time function code sharing, Datediffdateadd Extended time functions in PHP DateDiff and DateAdd function DateDiff ($part, $begin, $end) {$diff = Strtotime ($end)-Strtotime ($begin), switch ($part) {case "Y"

DECLARE @ DateDATETIMESET @ DateGETDATE () -- previous DAY, previous DAY of given Date SELECTDATEADD (DAY,-1, @ Date) AS previous DAY -- next DAY, next DAY of given Date SELECTDATEADD (DAY, 1, @ Date) AS the next day GO -- the beginning of the month,

1,Datediff   Syntax description: Datediff (date-part, date-expression1, date-expression2) Function: Returns the interval between two dates. Parameter description: Date-part: Year | quarter | month | week | Day | hour | minute | second | millisecond  

No nonsense.CodeThe comment is very detailed. It is certainly okay to understand it! Declare @ date datetimeSet @ date = getdate ()-The previous day, the previous day of the given dateSelect dateadd (day,-1, @ date) as 'previous Day'-The next day,

Introduction: This is a detailed page on how to implement the date after several days of a given date (somewhat similar to dateadd in VB). It introduces the knowledge, skills, and experience related to PhP, and some PHP source code. Class =