disc cover template

This tutorial describes how to use Ps to create an ultra-personalized disc sports car cover to a PHP Chinese network friend. The album cover created in this tutorial is very personalized and difficult, we recommend you to the PHP Chinese web. if you like it, let's take a look at it. this tutorial shows you how to use Ps to create an ultra-personalized CD sports c

of it center and radius, expressed as real numbers in decimal nota tion, with up to digits after the decimal point. The imprecision margin is 5 x 10-13 . That's, it is guaranteed this variations of less than 5 x 10-13 on input values does not change which dis CS is visible. Coordinates of all points contained in discs is between-10 and 10.Confetti is listed in their stacking order, x1y1r1 being the Bottom one and xnynrN the top one. You is observing from the top.The end of the input is marked

Previously, I used K3b in Linux to burn a CD. Although K3b is powerful, it is for KDE. For a person who is more familiar with GTK + software, I naturally chose Brasero as an alternative. Today, Brasero developers have released a milestone important version 0.8, which has added many new features and is worth upgrading. In Brasero 0.8, apart from the previously described CD cover design feature (cover edit

The tutorial to the Friends of the triple introduction of the use of PS to make the disc on the back of the production method, thinking: The first to make the optical disc structure layer, and then use color gradient to make the color of the optical light, the process is relatively simple. The tutorial is not written in a very detailed time can be made according to their own habits! Final effect F

; i = R[i])//go right (Find a column with the fewest nodes) if(S[i] //Column I node number c =i; Remove (c); //Remove C node for(inti = d[c];i! = C;i = D[i])//find the smallest of these columns and go down.{Ans[d]=Row[i]; for(intj = R[i]; J! = I;j = R[j]) remove (col[j]);//remove the column corresponding to the row if(Dance (d+1))return true;//recursive next layer for(intj = L[i]; J! = I;j = L[j]) resume (col[j]);//Backwards Connection} resume (c); retu