/***//**
* Fractionserial. Java
* There is a fractional sequence: 2/1, 3/2, 5/3, 8/5, 13/8, 21/13...
* Calculate the sum of the first 20 items of the series.
* @ Author Deng Chao (codingmouse)
* @ Version 0.2
* Development/test environment: jdk1.6 + eclipse SDK 3.3.2
*/
Public class fractionserial ...{
Public static void main (string [] ARGs )...{
/**//*
* Not
There is a fractional sequence of 2/1 + 3/2 + 5/3 + 8/5 + 13/8 +... Find the sum of the first 20 items of the series.Program:
# Include
Output result: 32.660261 Press any key to continue
C language: There is a score sequence: 2/1 + 3/2 + 5/3 + 8/5 + 13/8 +... Find the sum of the first 20 items in this seriesProgram:
# Include
Output result: 32.660261 Press any key to continue
Calculate the sum of the First n items of the Fibonacci fractional sequence (N is a constant, and the Fibonacci fractional sequence is 2/1, 3/2, 5/3, 8/5 ,...).
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# Include
}/* The numerator behind the score is equal to the numerator plus the denominator of the previous score, and the denominator of the subsequent score is equal to the numerator with the previous score */
There is a fractional sequence: 2/1, 3/2, 5/3, 8/5, 13/8, 21/13... find the sum of the first 20 items of this series
Tags: open window function query desc font where SRC definition nio return1. Recursively query the sub-categories under the parent classification. Table Design: Sql: --CTE Statement (for later versions of MSSQL2005)
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SELECTId,name,pid fromNaviWHEREName='Automotive'
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SELECTA.id,a.name,a.pid fromNavi aINNER JOINCt
)#generates a subset of all the rules, the rows and columns are each rules, where the values are true and false, when Rules2 is a subset of rules1, the value of Rules2 in Rules1 is trueSubset.matrix[lower.tri (subset.matrix,diag=t)]#set the element below the diagonal of the matrix to null, leaving only the upper triangleRedundant#R will treat true in the matrix as 1, counting the sum of each column (ignoring missing values), if the sum of the column is greater than or equal to 1, that is, that t
This tutorial is based on the Child Dragon Mountain Man translation cocos2d iPhone tutorial, rewrite with cocos2d-x for xNa engine, plus some of my processing and production. In the tutorial, most of the text images are from the original author and the author of the translation, Long Shan, and many others are my own understandings and processing. I would like to thank the original author for his tutorial and the translation of Zilong shangren. This tutorial is only for learning and communication
Write a program using C language to solve there is a fractional sequence: 2/1,3/2,5/3,8/5,13/8,21/13 ... find the first 20 items of this sequencevoid Test () {///idea: rule-based starting from 3/2 the denominator of the next number is the numerator of the previous number, the next number of numerator is the numerator of the previous number of the denominator and
/* For the sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222*/#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Output Result:224690Press any key to continueThis article is from the "51cto" blog, be sure to keep this source http
Program:The sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Results:224690Press any key to continueThis article is from the "Rock Owl" blog, please be sure to keep this source h
); if(n%2==1) k= (n+1)/2;/*K,summ, the purpose of this is to take a large number of N/2 when n is odd, and more accurately for subsequent results*/ Elsek=n/2; for(intI=1; ii) {scanf ("%d",W[i]); Sum+=W[i]; } f[0][0]=f[1][0]=true; if(sum%2==1) summ= (sum+1)/
Personal Items 2--ArithmeticOn the basis of generating arithmetic expression function in personal item 1, the function is expanded.1. Avoid duplication:The two numbers of the expression are computed by operation to generate a number, as follows: The previous number *10000, the next number, the resulting two numbers are added, and stored in the array, with "= =" to determine whether the resulting number is t
/* For the sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222*/#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Output Result:224690This article is from the "Rock Owl" blog, please be sure to keep this source http://10742111.blo
: This article mainly introduces Question 2: in the Fibonacci series, find out the sum of the values of less than 4 million items that are even ., If you are interested in the PHP Tutorial, refer.
Copyright Disclaimer: This article is an original article by the blogger and cannot be reproduced without the permission of the blogger. The above introduces Questi
Write an object-based program to find the volume of 3 long Fang (Bulk).Data members include length (length), Width (width), height (heigth), volume, and require design member functions to implement the following functions:(1) by the keyboard input 3 long Fang long, wide, high;(2) Calculating the volume (volume) and surface area of the long Fang (areas);(3) Output the volume and surface area of these 3 long Fang;#include using namespace Std;Class Bulk{
After a fraction of the numerator = numerator of the previous fraction + denominator, the denominator of the next fraction = the numerator of the previous fraction, the cycle is 20 times the result. Note that the numerator is a and the denominator is B, although a = a + B,But at this point A has become a+b, so to re-assign the value of the time, it is (a+b)-B to be equal to the original denominator B, so re-assignment should be written as a-aMethod OneFrom fractionsImport fractiondef Fibonacci (
Recently, I have done 2 more interesting projects, all of them are done alone, feeling quite a sense of accomplishment. I share the next. Oh.A telecom operation support systemIntroduction to this system: development environment Windows,eclipse,javaSystem Description: The system realizes the user login information collection module, the AAA server collects the user's online and offline information, and sends the complete information to the central serv
Just use a For loop to achieve the purpose #includeFind the sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222
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