draw binary tree online

Public class treenode {public int data; Public treenode left; Public treenode right; Public treenode (INT data) {This. data = data; left = NULL; Right = NULL;} public class tree {public treenode root; // Insert the public void add (INT data) node in the sorting Binary Tree) {treenode node = new treenode (data); If (root = NULL) root = node; else {treenode current

Return any binary tree that matches the given preorder and postorder traversals. Values in the traversalspreAndpostAre distinct positive integers. Example 1: Input: pre = [1,2,4,5,3,6,7], post = [4,5,2,6,7,3,1]Output: [1,2,3,4,5,6,7] Note: 1 pre[]Andpost[]Are both permutations1, 2, ..., pre.length. It is guaranteed an answer exists. If there exists multiple answers, you can return any of them. Runti

Topic: Given a tree, ask for the maximum value of the mean of the edge in the path of the length within the [L,u] range01 Score planning, first think of the two-point answerSince it's a statistical pathway, it's definitely a point division.We're looking for a path with no greater than 0 per statistic.So for each depth of a subtrees tree I record a path weight and a maximum valueThen the depth range of all s

https://leetcode.com/problems/recover-binary-search-tree/description/ Hard problem, but it's not difficult to get over it. First draw a picture, think of the next, think of if it is from left to right in the middle sequence traversal, get is a non-descending sequence, if it is from right to left (first right subtree again Zuozi) is a non-ascending sub-sequence, a

/** 331. Verify preorder serialization of a Binary Tree * 2016-7-9 by Mingyang * This topic my absolutely original idea is to put number# #变为 #, so constantly the Russian block type of reduction * There is only one # left in the end, so do it yourself, then use the StringBuffer replace function * But found a case to pass, that is, "9,#,92,#,#" why? Just because I take the number of individual digit

Reprint please indicate the source, thank you http://blog.csdn.net/ACM_cxlove? Viewmode = ContentsBy --- cxlove A sequence a with the length of N is set to B after the sorting order. The number of digits is defined as B [n/2], where A and B start from 0, division is rounded down.Here is a sequence of s whose length is N.Q: The left endpoint of S is between [a, B], and the right endpoint is in the subsequence between [c, d], with the maximum median.A The position also starts from 0. Http://ww

is created, the node is automatically moved to the listnode corresponding to the root node. Therefore, after the left subtree is created, the root node is established, the current node is moved back, and the entire right subtree is recursively created. Use linked list = 1-> 2-> 3-> 4-> 5 to draw a picture: The Code is as follows: 1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6

new node to the right. So ans and R both add 1,r to the same ANS and l both add 1.This is probably the case, or draw a picture to look good, attached to my slag code/************************************************author:d evil*********************************************** * */#include#include#include#include#include#include#includeSet>#include#include#includestring>#include#include#defineINF 0x3f3f3f3f#defineLL Long Long#defineRep (i,a,b) for (int

Find the nearest common parent node of any two nodes on the binary tree. It is required that the nearest common parent node (LCA, lowest common ancestor) of the two nodes can be traversed in descending order of the tree. If the two nodes are not on the same line, they must be on the left and right trees of node A respectively, node A is required to traverse to

Find the shortest path from the root node to the leaf node.IdeasBegan to think back the shortest depth of the left and right subtree, the test found that for a root node with a child node, the shortest path is 2, not the minimum depth of 1, this particular case is listed separately."My Code"intMindepth (TreeNode *root) { if(root==NULL)return 0; intDepthl=mindepth (root->Left ); intDepthr=mindepth (root->Right ); if(depthl!=0depthr!=0) returnMin (DEPTHL, depthr) +1; Else

The question is to be charged. can only see the topic online, I wait for the cock Silk also can't oj test. After looking at the Internet, it is not original, other parties have similar problems. Here, for example, on the CareercupThe idea of recursion was first used,TreeNode *ans; TreeNode*helper156 (TreeNode *root) { if(!root, left !rootRight ) {ans= root;returnRoot; } TreeNode*parent = Upsidedown (rootLeft ); Parent-left = rootRight ; Parentr

Pre-sequence traversal: root-left-right In-sequence traversal: left-root-right Subsequent traversal: Left-right-root Summary: The root as the center, before the first order on the root, in the order of the root, followed by the root. Pre-order expression: corresponding to the forward traversal Middle-order expressions: corresponding to the sequence traversal Sequence of expressions: corresponding to the subsequent traversal Example: A = B/(c+d) * e-f Convert the