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. Judging R decomposition into Ρ={r1, R2, R3, R4, R5} non-destructive join decomposition? Solution: Such a problem to be solved by drawing a table, first, the original table: A B C D E AD A1 B12 B13 A4 B15 Bc B21 A2 A3 B24 B25 Be B31 A2 B33 B34 A5 Cde B41 B42

Transfer from http://blog.chinaunix.net/uid-7692530-id-2567582.htmlIn some databases there is a crosstab, but there is no such function in MySQL, but there are many friends on the Internet to find a solution, special post set the broad sense.http://topic.csdn.net/u/20090530/23/0b782674-4b0b-4cf5-bc1a-e8914aaee5ab.html?96198Now the solution is as follows:Data samples:CREATE TABLE TX (ID int PRIMARY KEY,C1 char (2),C2 char (2),C3 int);INSERT INTO TX values(1, ' A1 ', ' B1 ', 9),(2, ' A2 ', ' B1 ',

This is the world Hacker Programming competition first work (97 Mekka ' 4K intro competition), written in assembly language. The entire program is 4095 bytes long and generates a. com program with only 4 K, but it achieves the effect of 3D animation and a background music. The picture is a scene of the game spinning. Absolute cow. 1 Paste the following code into Notepad, save as a 1.txt document. 2 in the Command Line window (at the beginning → run →cmd), enter the document, enter the Debug E10

From: http://www.pconline.com.cn/pcedu/empolder/gj/other/0507/674996.html Source: China system analyst by Ding ding E100 33 F6 BF 0 20 B5 10 F3 A5 8C C8 5 0 2 50 68 13 1 CB e 1f be A1 1 BF 0 1E11b 6 57 B8 11 1 BB 21 13 89 7 4B 4B 48 79 F9 ad 86 E0 8B C8 bd ff E8 20E134 0 3D 0 1 74 1A 7f 3 aa eb F3 2D FF 0 50 E8 F 0 5A F7 D8 8B D8 26 8A 1 aaE14f 4A 75 F9 EB de CB 57 BB 21 13 8B C1 40 F7 27 F7 F5 8B FB Ba 11 1 4f 4f 4AE168 39 5 7f F9 52 8B C5 F7 25 F7 37 2B C8 95 F7 65 2 F7 37 95 2B E8 Fe e feE181

In DoS (Enter cmd in the run bar), enter the inventory letter in the document, and enter debug E100 33 F6 BF 0 20 B5 10 F3 A5 8C C8 5 0 2 50 68 13 1 CB e 1f be A1 1 BF 0 1E11b 6 57 B8 11 1 BB 21 13 89 7 4B 4B 48 79 F9 ad 86 E0 8B C8 bd ff E8 20E134 0 3D 0 1 74 1A 7f 3 aa eb F3 2D FF 0 50 E8 F 0 5A F7 D8 8B D8 26 8A 1 aaE14f 4A 75 F9 EB de CB 57 BB 21 13 8B C1 40 F7 27 F7 F5 8B FB Ba 11 1 4f 4f 4AE168 39 5 7f F9 52 8B C5 F7 25 F7 37 2B C8 95 F7 65 2 F7 37 95 2B E8 Fe e feE181 10 79 6 C6 6 Fe 1

accepted proposal, and promises not to revert to the proposal less than N; Approval phase: When a proposor receives a majority of Acceptors's response to prepare, it enters the approval phase. It sends an accept request to the acceptors that responds to the prepare request, including the number n and the value determined by P2C (if no value has been accepted based on the P2C, then it is free to determine value). Without violating its commitments to other propo

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The problem is: there are a total of 25 horses, there is a stadium, there are 5 tracks, that is to say, a maximum of 5 horses can be played together at the same time. Assuming that each horse runs very stably and does not use any other tools, only through the competition between the horse and the horse, you can know the minimum number of matches to know the fastest five horses. Note: "If every horse runs very stably" means that in the last game, A is faster than B, and A is still faster than B i

57 A9 C5 ca AA 1bE1b4 4f 52 B4 92 3f AB 6e 9e A8 1D C6 3 FC e 6a E7 AE BB 5f 7b 10 B8 B4 F7 8E1cd E2 BF 36 4E 39 9d 79 29 3f A F9 36 52 16 FB 5 E8 E5 A6 C2 E9 B0 43 D3 A3E1e6 CF D3 fd cb D1 4C 5E E0 63 58 86 BB 3E 9 C1 20 bc cc 91 A3 47 81 70 B3E1ff D6 1A 9e C2 C9 12 E7 4E ad F4 5f E3 30 E9 9 39 D7 E8 F9 F4 D2 44 E8 D7 22E218 be E2 ce 88 25 CF 30 4A A8 29 AE 3f 47 C6 2D 85 E9 73 54 13 B E6 E0 34 65E231 E2 50 8A 89 18 5f ce 70 99 3 5f 42 bf eb 7 AE D0

C2 E9 B0 43 D3 A3E1e6 CF D3 fd cb D1 4C 5E E0 63 58 86 BB 3E 9 C1 20 bc cc 91 A3 47 81 70 B3E1ff D6 1A 9e C2 C9 12 E7 4E ad F4 5f E3 30 E9 9 39 D7 E8 F9 F4 D2 44 E8 D7 22E218 be E2 ce 88 25 CF 30 4A A8 29 AE 3f 47 C6 2D 85 E9 73 54 13 B E6 E0 34 65E231 E2 50 8A 89 18 5f ce 70 99 3 5f 42 bf eb 7 AE D0 ca 5 22 8d 22 A5 B7 F0E24a 90 81 BC 7A bc dc 5 dB C0 6a 2 E5 57 38 be 60 Cb AC Ba A5 3B 9d F1 77 38E263 A6 84 D1 3C af 49 D8 6a 45 A2 76 60 21 12 C0 C2

It is said that a Chinese person participated in the competition. E100 33 F6 BF 0 20 B5 10 F3 A5 8C C8 5 0 2 50 68 13 1 CB e 1f be A1 1 BF 0 1E11b 6 57 B8 11 1 BB 21 13 89 7 4B 4B 48 79 F9 ad 86 E0 8B C8 bd ff E8 20E134 0 3D 0 1 74 1A 7f 3 aa eb F3 2D FF 0 50 E8 F 0 5A F7 D8 8B D8 26 8A 1 aaE14f 4A 75 F9 EB de CB 57 BB 21 13 8B C1 40 F7 27 F7 F5 8B FB Ba 11 1 4f 4f 4AE168 39 5 7f F9 52 8B C5 F7 25 F7 37 2B C8 95 F7 65 2 F7 37 95 2B E8 Fe e feE181 10 79 6 C6 6 Fe 10 7 46 D0 14 D1 D1 D1 E5 79 EC 5

A beautiful female DBA wants to learn SQL optimization, and is often confused with me. My favorite beauty. Today, he sent an SQL statement asking me to help you. The execution plan is as follows: Select "A1 ". "code", "A1 ". "device_id", "A1 ". "sideb_port_id", "A1 ". "version" from (select "A2 ". "Code" "code", "A2 ". "device_id" "device_id", "A2 ". "sideb_port_id" "sideb_port_id", "A3 ". "version" "version", row_number () over (partition by "A4 ". "

Tags: Code ad EF ca CF bug C 3D AE E100 33 F6 BF 0 20 B5 10 F3 A5 8C C8 5 0 2 50 68 13 1 CB e 1f be A1 1 BF 0 1E11b 6 57 B8 11 1 BB 21 13 89 7 4B 4B 48 79 F9 ad 86 E0 8B C8 bd ff E8 20E134 0 3D 0 1 74 1A 7f 3 aa eb F3 2D FF 0 50 E8 F 0 5A F7 D8 8B D8 26 8A 1 aaE14f 4A 75 F9 EB de CB 57 BB 21 13 8B C1 40 F7 27 F7 F5 8B FB Ba 11 1 4f 4f 4AE168 39 5 7f F9 52 8B C5 F7 25 F7 37 2B C8 95 F7 65 2 F7 37 95 2B E8 Fe e feE181 10 79 6 C6 6 Fe 10 7 46 D0 14 D1 D1 D1 E5 79 EC 5A B8 11 1 FF 7 4B 4B 48E19b 3B

programmers have strong or weak points. Putting aside impetuousness, it is right to sink your mind to do things. Source code of the appendix Program (I do not know it was written by the Senior Engineer ): E100 33 F6 BF 0 20 B5 10 F3 A5 8C C8 5 0 2 50 68 13 1 CB e 1f be A1 1 BF 0 1E11b 6 57 B8 11 1 BB 21 13 89 7 4B 4B 48 79 F9 ad 86 E0 8B C8 bd ff E8 20E134 0 3D 0 1 74 1A 7f 3 aa eb F3 2D FF 0 50 E8 F 0 5A F7 D8 8B D8 26 8A 1 aaE14f 4A 75 F9 EB de CB 57 BB 21 13 8B C1 40 F7 27 F7 F5 8B FB Ba 11

Copy the following code and save it as a text document. Name it 1. Use DEBUG Generate an executable program. It's a 3D Game rotation interface, and there's a wonderful piece of music !!!Go and have a look E100 33 F6 BF 0 20 B5 10 F3 A5 8C C8 5 0 2 50 68 13 1 CB e 1f be A1 1 BF 0 1E11b 6 57 B8 11 1 BB 21 13 89 7 4B 4B 48 79 F9 ad 86 E0 8B C8 bd ff E8 20E134 0 3D 0 1 74 1A 7f 3 aa eb F3 2D FF 0 50 E8 F 0 5A F7 D8 8B D8 26 8A 1 aaE14f 4A 75 F9 EB de CB 57 BB 21 13 8B C1 40 F7 27 F7 F5 8B FB Ba 11

= []; //using the above an array to weigh the thought for(vark = 0, L = a1.length; K ){ if(!Obj[a1[k]]) {Obj[a1[k]]= 1; }Else{Obj[a1[k]]+ = 1; }; } varnum = 0, Word = ""; for(varIteminchobj) { if(Obj[item] >num) {num=Obj[item]; Word=item; } } returnWord; } varW =maxnum (str); Console.log (w); //gThird, sorting algorithm (too many kinds of sorting algorithm)1. Bubble sortvar a3 = [1,4,2,9

The solution is as follows: Data sample: Create table tx (Id int primary key,C1 char (2 ),C2 char (2 ),C3 int); Insert into tx values(1, 'a1', 'b1 ', 9 ),(2, 'a2 ', 'b1', 7 ),(3, 'a3 ', 'b1', 4 ),(4, 'a4 ', 'b1', 2 ),(5, 'a1', 'b2', 2 ),(6, 'a2 ', 'b2', 9 ),(7, 'a3 ', 'b2', 8 ),(8, 'a4 ', 'b2', 5 ),(9, 'a1', 'b3', 1 ),(10, 'a2 ', 'b3', 8 ),(11, 'a3 ', 'b3', 8 ),(

In some databases, there are cross tables, but this function is not available in MySQL. However, many friends on the Internet want to find a solution.Http://topic.csdn.net/u/20090530/23/0b782674-4b0b-4cf5-bc1a-e8914aaee5ab.html? 96198The solution is as follows: Data sample: Create Table TX (Id int primary key,C1 char (2 ),C2 char (2 ),C3 int); Insert into TX values(1, 'a1', 'b1 ', 9 ),(2, 'a2 ', 'b1', 7 ),(3, 'a3 ', 'b1', 4 ),(4, 'a4 ', 'b1', 2 ),(5,

Tags: haproxy load balancer MySQL dual masterHaproxy load balancer MySQL dual master 650) this.width=650; "height=" 356 "src=" http://a3.qpic.cn/psb?/594581eb-e62e-4426-a878-953c87dd5729/ qve5nzzvbuqffqo9g6peti58q4ijtp*tc3tbzfscke0!/b/dgybaaaaaaaaek=1kp=1pt=0bo=kgjlaqaaaaadagk! su=0194203249tm=1481871600sce=0-12-12rf=2-9 "width=" 553 "style=" margin:0px;padding:0px; border-width:0px;border-style:none;vertical-align:top; "Alt=" dgybaaaaaaaaek=1kp=1pt=0

Label:Ext.: http://blog.chinaunix.net/uid-7692530-id-2567582.html In some databases there is a crosstab, but there is no such function in MySQL, but there are many friends on the Internet to find a solution, special post set the broad sense.http://topic.csdn.net/u/20090530/23/0b782674-4b0b-4cf5-bc1a-e8914aaee5ab.html?96198Now the solution is as follows: Data samples: CREATE TABLE TX (ID int PRIMARY KEY,C1 char (2),C2 char (2),C3 int); INSERT INTO TX values(1, ' A1 ', ' B1 ', 9),(2, ' A2 ', ' B1