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template. "TAT" number theory abuse me like a vegetable worm, even vegetable chicken can not forget ... AC Template ... /*/#include "map" #include "Cmath" #include "string" #include "Cstdio" #include "vector" #include "CString" #include "iostream "#include" algorithm "using namespace std;typedef long LL; ll EXGCD (ll a,ll b,ll x,ll y) {//Direct reference to save X and y in the entire process (N-M) x+ly=x-y; if (!b) {X=1;y=0;return A;} LL D=EXGCD (b,a%b,x,y); LL t=x;x=y;y= (t-a/b*y); return D;}

Title Link: http://poj.org/problem?id=1061is to find contentment (X+MT)-(Y+NT) = Lk's T and KThe upper formula can be reduced to (N-M) T + Lk = x-y, satisfying the form of ax+by=c so that we can seek t and K with the extension Euclid;Since the upper formula has a solution and only if C is gcd (A, B) = 0;#include #include#includestring.h>#includestring>#include#include#include#include#include#includeusing namespacestd;#defineMet (A, b) memset (A, B, sizeof (a))#defineN 10053#defineINF 0x3f3f3f3fC

2 have done, put 1 to fill.Test instructions gives N and K, and the number of N. is the n number to find the two number x, Y. Make x+y=k.Calculate all the possibilities. When X0+y0=k. X1+y1=k. Must have unequal. X0!=x1 or Y0!=y1.For example4 42 2 2 2The correct output should be 1.I was sort of, went heavy, and then two points. It seems that many people are using the pointers.Forget the STL's two-point return subscript function, the mood is not good, too lazy to check, hand hit two points.#includ

a time, Frog B can jump n meters at a time, and two frogs will spend the same time jumping once. Latitude line total length l m. Now you have to find out how many times they have jumped before they meet.InputThe input includes only one line of 5 integer x,y,m,n,l, where X≠y OutputOutput the number of hops required to meet, and output a line of "impossible" if it is never possible to meetSample Input1 2 3) 4 5Sample Output4#include #include#include#includeusing namespaceStd;typedefLong Longll;vo

[flag][v].ma = Tree[flag][v].ma_r = (tree[flag][v].r-tree[flag][v].l + 1) *tag;return;}Push_down (v);int mid = (tree[flag][v].l + tree[flag][v].r) >> 1;if (a if (b > Mid) update (A, B, right, flag, tag);Push_up (v);}int main (){Freopen ("In.txt", "R", stdin);int T;scanf ("%d", t);int cas = 0;while (t--){int N, Q;scanf ("%d%d", n, q);Build (1, N, 1);Char ch[10];int L, R, QT;printf ("Case%d:\n", ++cas);while (q--){scanf ("%s", ch);if (ch[0] = = ' D '){scanf ("%d", AMP;QT);if (Tree[1][1].ma {Puts (

; A=b; b=R; } returnA;}voidEXTEND_GCD (ll A, ll B, ll x, LL y) {if(b = =0) {x=1; Y=0; return ; } Else{EXTEND_GCD (b, a%b, x, y); LL tmp=x; X=y; Y= TMP-A/b *y; }}intMain () {LL x, y, D; while(~SCANF ("%i64d%i64d%i64d%i64d%i64d", x, y, m, n, L)) {LL a= N-M; LL b=L; LL C= X-Y; D=gcd (A, b); if(c% d! =0) {printf ("impossible\n"); Continue; } A/=D; b/=D; C/=D; EXTEND_GCD (A, B, X, y); LL T= c * x%b; if(T 0) T + =b; printf ("%i64d\n", T); } return 0;}View Code#include typedefLong Long

Topic Links:http://poj.org/problem?id=1061Main topic:Chinese topic, test instructions at a glance, is the data range is surprisingly large.Problem Solving Ideas:Assuming that two frogs have skipped T-times, you can list the indefinite equation: P*l + (n-m) *t = = x-Y. After the equation is listed, the solution of the indefinite equation is calculated using the extended Euclidean. In finding the smallest solution of the whole place card for a long time, long.To learn more about the use and proof

* * equation has an integer condition (y-x)%GCD (A, B). At this point the solution is extended gcd (y-x)/GCD (A, B). (Think about why?) Equivalent to both sides of the equation expand/Shrink k=(y-x)/GCD (A, B) times. but we need to ask for the smallest integer. Because the extended GCD is a set of integer solutions, this requires us to adjust the answer. The specific method isar = (ar% abs (b/g) + ABS (b/g))% abs (b/g); AR is the time to find out TYou can limit the answer to 0~abs (b/g) and wh

The processing of stones is based on the time of each location to obtain the remainder of K and judge the repetition. Others can be written at will. #include 　　 HDU 2579 dating with girls (2) BFS remainder judgment

Recently, Chinese dating programs have been very popular. I also often look at Hangzhou TV, Hunan TV, and Jiangsu TV. Now I think it's hard for programmers to find a wife, including my own experiences with finding a wife is also quite frustrating. Hangzhou TV has seen many programs that match each other. In fact, many girls require boys to have a house, no matter whether handsome or competent, no house, in general, it is not easy to become or be passi

spend the same time jumping once. Latitude line total length l m. Now you have to find out how many times they have jumped before they meet.InputThe input includes only one line of 5 integer x,y,m,n,l, where X≠y OutputOutput the number of hops required to meet, and output a line of "impossible" if it is never possible to meetSample Input1 2 3) 4 5Sample Output4Analysis:when two frogs jump T-step, the coordinates of a are x+mt-p1l (P1∈z and X+mt-p1lFinishing available (x-y) + (m-n) T = (P1-P2) l

wireless network, you have to use the wireless network card. We started using our own network card, found that it is not possible, because the tablet's Android system does not support the driver download and installation features. After discussing with the classmates we contacted the teacher, received the factory sent the original network card, from then can use WiFi.V. Design experience and HarvestThrough this experiment, I first familiar with the function of the test chamber components, under

(1) Collect data: Provide text file(2) Preparing data: Parsing text files with Python(3) Analyzing data: Using Matpltlib to draw two-dimensional diffusion graphs(4) Training algorithm: This step does not apply K-nearest neighbor algorithm(5) test algorithm: Using some of the data provided by Helen as a test sample, the difference between the test sample and the non-test sample is that the test sample is the data that has been sorted, and if the forecast classification is different from the actua

Personalized dating ap Based on Rayeager PX2 Development Board for demonstration platform, rayeagerpx2Function: This is a personalized dating app. Men and women are defined by the peacock and peacock. By using this APP, users can open the APP to see all users in a certain range centered on them, the user's existing mode is the Peacock Flying. If you are interested in a peacock, you can capture it and chat w

HDU 2579 Dating with girls (2) Fail the retake exam. I hate network technology ...... Cisco Software operations. That's it !!! Computer Networks are simple. It is also a book in English "Computer Network. A school that is truly forced. The dictionary is as thick as it is. I really want to kill you! We really can afford it. 985,211 of undergraduate students are not so cool. I was shocked by a few questions. Randomly flip one page. The question is good.

Sherlock Holmes received a note with some strange strings: "Let's date!" 3485djdkxh4hhge 2984AKDFKKKKGGEDSB shgsfdk dhyscvnm ". It took him only a minute to figure out that those strange strings is actually referring to the coded time "Thursday 14:0 4 "--since the first common capital 中文版 (case sensitive) shared by the first and strings is the 4th capital Le Tter ' D ', representing the 4th day in a week; The second common character is the 5th capital letter ' E ', representing the 14th hour (he

Topic Connectionhttp://acm.hdu.edu.cn/showproblem.php?pid=2578Dating with girls (1) DescriptionEveryone in the HDU knows, the number of boys is larger than the number of girls. But now, every boy wants to date with pretty girls. The girls like to date with the boys with higher IQ. In order to test the boys ' IQ, the girls make a problem, and the boys who can solve the problemCorrectly and cost less time can date with them.The problem is that:give your n positive integers and an integer k. Need t

2984AKDFKKKKGGEDSB shgsfdk dhyscvnm ". It took him only a minute to figure out that those strange strings is actually referring to the coded time "Thursday 14:0 4 "--since the first common capital 中文版 (case sensitive) shared by the first and strings is the 4th capital Le Tter ' D ', representing the 4th day in a week; The second common character is the 5th capital letter ' E ', representing the 14th hour (hence the hours from 0 to + a D Ay is represented by the numbers from 0 to 9 and the capit

Appointment ScheduleTime limit:2000/1000 MS (java/others) Memory limit:65535/32768 K (java/others)Total submission (s): 402 Accepted Submission (s): 127Problem Description Winter vacation came, again to Xiao Ming and goddesses dating season.Although Xiao Ming for the cock, but very active, the goddess often in Xiao Ming on the internet after the big paragraph after the warm reply "hehe", so, Xiao Ming's favorite is to date with the goddess. At the sa

"Always ask for you but never say thank you ~ ~ ~", in the blog park and the above to absorb a lot of knowledge, will also grow here, here is very good, thank you blog Park and know, so today also put their own in the project during the things to share, hope to help friends ....Say less nonsense, let's go~~~~!Demand:Project needs to do a dating site, the main technology has nginx, server cluster, Redis cache, MySQL master-slave replication, amoeba rea