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Reverse basic OS-specpacific (1)

warning: if you have two DLL, the first of which calls the second DLL function, they are compiled by different compilers using the fastcall call method, there will be unpredictable consequences. Both MSVC and GCC compilers pass the first and second parameters through ECX and EDX, and pass other parameters through the stack. The stack pointer must be restored to the initial state by the caller (similar to stdcall ). Listing 64.4: fastcall push arg3mov

Reverse Question of the greatest challenge of geeks in the fifth quarter (2)

Obtain the dialog box data and determine the length: 004011b5 |. 6a 14 push 0x14;/COUNT = 14 (20 .) 004011b7 |. 51 push ECx; | buffer = 0018f8b8004011b8 |. 66: 894424 2D mov word PTR [esp + 0x2d], ax; | 004011bd |. 68 e8030000 push 0x3e8; | controlid = 3e8 (1000 .) 004011c2 |. 52 push edX; | hwnd004011c3 |. c64424 20 00 mov byte PTR [esp + 0x20], 0x0; | 004011c8 |. 884424 37 mov byte PTR [esp + 0x37], Al; | 004011cc |. 33ed xor ebp, EBP; | 004011ce |.

Amazon Kindle (Windows) cannot be started again after a malformed azw is opened

): Access violation - code c0000005 (!!! second chance !!!)*** ERROR: Symbol file could not be found. Defaulted to export symbols for F:\Program Files (x86)\Amazon\Kindle\Kindle.exe - eax=000000dd ebx=000004e4 ecx=00000000 edx=0022ed44 esi=0022ed68 edi=000000ddeip=0197383f esp=0022ed14 ebp=05920448 iopl=0 nv up ei pl nz na po nccs=0023 ss=002b ds=002b es=002b fs=0053 gs=002b efl=00210202Kindle!std::_Init_locks::operator=+0x13

[Reveal the Intel module of vc crt library]-strlen

that in the previous comment, Ms engineers wrote a "comment version" strlen, which is exactly the same as the strlen you previously implemented. However, it is an annotated version and will not be compiled into the program. The following Assembly implementation code is as follows: CODESEG public strlenstrlen proc \ buf:ptr byte OPTION PROLOGUE:NONE, EPILOGUE:NONE .FPO ( 0, 1, 0, 0, 0, 0 ) string equ [esp + 4] mov ecx,string

Ms SQL Server ODBC driver SQL Server listing Stack Overflow Vulnerability

loc_74cb72a1:. Text: 74cb72a1 mov edX, [EBP + var_4]. Text: 74cb72a4 mov eax, [EBP + var_104c] Number of existing loops in the ebp-0x104c. Text: 74cb72aa CMP eax, [edX + 8] edX + 8 storage Total number of packages received. Text: 74cb72ad jge loc_74cb70f2. Text: 74cb72b3 mov ECx, [EBP + var_1044]. Text: 74cb72b9 mov edX

Efficiency of Delphi-Copy Functions

the experiment data:1 uses 2642 used 169Of course, this is only shown after 9999900 times of running. If we assign s to a long string, let's take a look.When the string s contains 100 characters, Copy 100 characters:1 uses 2662 used 181When S is followed by 200 characters and Copy is 200 characters1 2442 186It can be seen that in the case of short strings, MoveMemory must be faster, and the subsequent string growth Copy efficiency has not declined,However, SetLength + MoveMemory is reduced.Fina

Want to be a programmer? 28 Online Learning Websites let you become a secret!

can make friends at home and abroad while learning, to add some fun to learning. CodeYear is also under Codecademy. Khan Academy Another "school" is Khan Emy. If you want to become a Renaissance female or a Renaissance male, Khan Academy provides many programming courses, of course, if you only want to learn programming, it does. Mozilla Developer Network Mozilla integrates network resources to create a free learning center for Webpage Design and website creation. General Assembly General As

[Share] itpub zookeeper resource Summary

: upgrading and new featuresLink: http://pan.baidu.com/s/1jGJZJi2Password: ibs1Title: livelessons-Intro to Android Application DevelopmentLink: http://pan.baidu.com/s/1pJK54j5Password: pew3Title: pluralsight-functional programming with JavaLink: http://pan.baidu.com/s/1dD3oUXFPassword: yz6gTitle: Lynda-Maya 2015 essential trainingLink: http://pan.baidu.com/s/1i3uZqPvPassword: 52pgTitle: pluralsight-Introduction to openstackLink: http://pan.baidu.com/s/1ntv7cpFPassword: i4ohTitle: tutsplus-ASP. N

Fast 16-Color Conversion Algorithm

analysis, we can find that the " 0x000f000f" operation is not required:X = DWORD () 0x11111111; // 000g 000 h 000e 000f 000c 000d 000a 000bX = bswap (x); // 000a 000b 000c 000d 000e 000f 000g 000 hX = (X | (x> 3) 0x03030303; // 0000 00ab 0000 00cd 0000 00ef 0000 00ghX = (X | (x> 6); // 0000 00ab 0000 ABCD 0000 00ef 0000 efghX = (byte) (X | (x> 12); // 0000 00ab 0000 ABCD 00ab 00ef ABCD efgh The corresponding assembly code is:; X = DWORD (); // 000g 000 h 000e 000f 000c 000d 000a 000b; MoV eax

. NET shell software clisecure debugging notes (ii)

process, if not, naturally do not need to decrypt. 012b2a4c |.  8b45 0C mov eax,dword ptr ss:[ebp+c] 012b2a4f |.  8B48 mov ecx,dword ptr ds:[eax+4] 012b2a52 |.  8B51 mov edx,dword ptr ds:[ecx+4] 012b2a55 |.  8b45 0C mov eax,dword ptr ss:[ebp+c] 012b2a58 |.  8B48 mov ecx,dword ptr ds:[eax+4] 012b2a5b |.  8B41 mov eax,dword ptr ds:[ecx+4] 012b2a5e |.  8b4d 0C mov ecx,dword ptr ss:[ebp+c] 012b2a61 |.  8d4401 Lea Eax,dword ptr ds:[ecx+eax+> 01

Java tutorial-deal with Java's 10 methods in a few weeks, java weeks

and has appropriate exercises. The requirement cannot be higher.   Learn Java by yourself The author of this website is the same person as the author of the previous book. The inspiration for this book comes from this website. At the beginning, we will find many problems that can be solved without a large number of programming skills. However, as the study goes deeper, the problem will become more and more difficult. I have always believed that the best way to learn something is to do it first,

10 ways to fix Java in a few weeks

version).Readers can read the first 16 chapters online for free and link here. I think a lot of people will like this book, the organization of the book is very reasonable, there are appropriate exercises. Can't ask for higher.Learn Java by yourselfThe author of the site is the same person as the author of the previous book, and that book is inspired by the site. At first you will find many problems that do not require a lot of programming skills, but as you learn, the problem becomes more and

Controlling user creation of course permissions

CauseBy default, a registered user of studio can create a course that does not appear to be the usual usage scenario, and the platform owner prefers a review to allow the user to publish the courseIdeasRead the wiki!!For the novice who is tossing edx, I think the first job is two points:1. Let the platform run up2. Read through the wiki (configuration wiki and edx-platform wiki)If you read through the wiki,

Use the underlying keyboard hook to change the keyboard layout

From http://zerray.com/ Looking at the hooks in Win32 compilation, I was wondering how to write a whole-person program that changed the keyboard layout. Check the information and find that the underlying keyboard hook (wh_keyboard_ll) can be implemented. First, install and uninstall the HOOK: Installhook proc hins: DWORDInvoke setwindowshookex, wh_keyboard_ll, ADDR keyproc, hins, nullMoV hhook, eaxRETInstallhook endp Uninstallhook procInvoke unhookwindowshookex, hhookRETUninstallhook endp Like

Make MASM support the _ fastcall call Method

will only press the parameter stack and then call it, but this is not the form of _ fastcall. it is also because it does not support _ fastcall, which makes assembly and other languages (such as C) mixed programming difficult once _ fastcall is involved. We all want to adopt some strategies to make MASM support the _ fastcall call method. In other words, it enables MASM to define and call functions of the _ fastcall type. To achieve this goal, we must first understand the characteristics of t

I think the Implementation of Virtual inheritance in vc6

:{0040c230 push EBP0040c231 mov EBP, ESP0040c233 sub ESP, 60 h0040c236 push EBX0040c237 push ESI0040c238 push EDI0040c239 Lea EDI, [ebp-60h]0040c23c mov ECx, 18 h0040c241 mov eax, 0 cccccccch0040c246 rep STOs dword ptr [EDI]31: mostbase1 * pbase1 = pderived;0040c248 cmp dword ptr [EBP + 8], 0 [1]0040c24c jne f + 27 h (0040c257)0040c24e mov dword ptr [ebp-18h], 0 [2]0040c255 jmp f + 35 h (0040c265)0040c257 mov eax, dword ptr [EBP + 8]0040c25a mov ECx, dword ptr [eax] [3]0040c25c mov

[Excerpt] OllyICE instructions and Examples

again!" In this error dialog box today !" . Start OllyDBG, select the menu File> open the CrackMe3.exe file, and we will stop here: In the Disassembly window, right-click a menu and choose search> all reference text strings and click: Of course, it is more convenient to use the above super string reference + plug-in. However, our goal is to be familiar with some OllyDBG operations. I will try to use the built-in functions of OllyDBG with less plug-ins. Now, in another dialog box, right-click

Ollydbg entry series (2)-string reference

choose search> all reference text strings and click: Of course, it is more convenient to use the above super string reference + plug-in. However, our goal is to be familiar with some ollydbg operations. I will try to use the built-in functions of ollydbg with less plug-ins. Now, in another dialog box, right-click it, select the "Search Text" menu item, and enter "Wrong serial, try again !" The start WORD "wrong" (note that the search content is case-sensitive) to find one: Right-click

Kryton 0.2-& amp; gt; Yado/Lockless shell (Code fixes IAT)

I read an article on IAT encryption processing. I learned how to fix IAT after arriving at OEP. If there is any error, please advise.Copyright: evilangel Test shell is The original program kryton The Krypter [v.0.2] I. Shell check: PEiD shell check:Kryton 0.2-> Yado/Lockless 2. Arrive at OEP First, load the OD, ignore all exceptions, and stop 00434000> 8B0C24 mov ecx, [esp]; Kernel32.7C81702700434003 E9 0A7C0100 jmp 0044BC1200434008 AD lods dword ptr [esi]00434009 42 inc edx0043400A 40 inc eax00

Intel processor identification and cpuid command (2) cpuid command

, the application should assign the eax register a value of H and execute the cpuid command: MOV EAX, 80000000HCPUID After the execution is complete, the results will be saved in the eax register. To return valid CPU extension information, the eax register should always pass a value greater than or equal to H and less than or equal to the value of the result. In any case, if the value passed to eax is greater than the maximum value it can accept, or the function that returns the extended informa

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