elasticsearch query all

How can I query all tables and sort them by the published time? For example, I made a forum where posts for each topic were placed in a separate table. I posted posts for the hardware, software, and programming sections respectively. now I am in my personal center, how can I display all my posts and sort them by release time? Ask for advice! How can I

I believe many of my friends have the need to use SQL statements to find all the tables in the specified database. For example, this requirement is even more common for database-related tools and projects, this chapter summarizes several methods to query all tables in a database using SQL statements. 1. Use the sysobjects system table to create a corresponding r

sameYou can also see the direct difference between the two methodsThe first one is perfectThe second one is a little awkward becauseSelect@sql="'Select@sql=@sql+','+[name] fromcan be used@s=IsNull(@s+',',"') instead'Select'+Stuff(@sql,1,1,"') thanQuoteName(Name) facilitates directBut the second one is the blogger's writing style, so the blogger has a personal feeling. See the first code like a turtle and a goddessToday once again feel the beauty of programming, code of the beauty of the heart o

S (Sno,sname,sdd,sage)Sno,sname,sdd,sageEach representative of the school number, learningMember's name, affiliation, student's ageC (Cno,cname)Cno,cnameRepresent the course number, the course name, respectivelySC (Sno,cno,score)Sno,cno,scoreRepresenting the school number,of the ElectiveCourse number, learning scoreThe data for the three tables are as follows:Problem:Use standard SQL nested statements to query the name and affiliation of the student t

Tags: mysql sql writeYou need to query three fields for information about the existence of the tables in all the libraries under an instance, and the end of the surface does not include the _ number information.SELECT Table_schema,table_name,sum (case "column_name in" (' User ', ' host ', ' password ') then 1 else 0 end) flag from infor Mation_schema. ' COLUMNS ' aWHERE table_schema= ' MySQL 'GROUP BY Table

Recently, a very strange MySQL problem occurs. Using different select statements to query all datasets produces different records. Select * gets four records, and select field gets three records.For details, refer to the following query results:[SQL]Mysql> select * from table_myisam;+ ---------- + ------- + ----------- + ------ +| Datetime | uid | content | type

Recently, a very strange MySQL problem, using different SELECT statements to query all datasets actually get different number of records. SELECT * Gets 4 records, and the Select field gets 3 records. specific questions can look at the following query results: [SQL] mysqlgt; SELECT * from Table_myisam; +----------+-------+-----------+------+ | datetime | UID

When you are doing something recently, use a database query. Group records by a field, taking all records of the maximum value of a field in each group. For chestnuts, for example.The known fractional table "Score" contains the field "id", "name", "Course", "score". Contains the record as shown in.　　Now, ask for the record of the course with the highest score for everyone. The following result is obtained:　

above is an application that removes an application for SBWXJH2The following is the relevant SQL for the domain query:SELECT * from Maxattribute where objectname= ' Sbreworker ' and attributename= ' REMARK ';SELECT * from Maxdomain where domainid= ' reworkertitle ';SELECT * from Alndomain where domainid= ' reworkertitle ';View sequence:SELECT * from SYSCAT. Sequences where seqname like ' sb% ';Set Default values:ALTER TABLE Sbrepairplan ALTER COLUMN HASLD set with default 0UPDATE Sbrepairplan S

Tags: on as SQL type Oracle table text class ROMQuery all columns and their properties for a table:Select From User_tab_columns t,user_col_comments Cwhere t.table_name = c.table_name and T.column_name = c.column_name and t.table_name = women;To find the primary key for a table:Find the foreign key of the table (including the name, the table name of the reference table, and the corresponding key name, which are divided into multi-step queries):SELEC

Tags: SQL organizational structureHow to design a table to store all employee information of a company, employee information when there is a subordinate relationship, how can quickly find a staff management of all personnel?TreeCEO 1|--manage1 11|-------Leader1 111| |-------employee1 1111| |-------employee2 1112||-------Leader2 112|-------employee3 1121|-------employee4 1122...Table_employeesID Name parent

Query statements for all table structures in the PostgreSQL Column SELECT tablename FROM pg_tablesWHERE tablename not like 'pg %'AND tablename not like 'SQL _ %'Order by tablename; Query the field information of the t_appointment_apply table.SELECT a. attnum, a. attname AS field, t. typname AS type, a. attlen AS length,. Atttypmod AS lengthvar,. attnotnull AS n

-- View All sequences of current users Select SEQUENCE_OWNER, SEQUENCE_NAME from dba_sequences where sequence_owner = 'username '; Note: 1. You must log on as an administrator; 2. sequence_owner must be in upper case, regardless of whether your user name is in upper case. Only uppercase letters can be recognized. Take the query of a BOOK table as an example: Create table BOOK(Booknumber char (3) not null,BO

Solution to database query time out of minutes and seconds The source of the problem: a company uses dynamic SQL to query the Oracle database in a project. When the Data Type field is displayed, only the date type field is displayed, and there is no time, minute, and second. Analysis: 1. As we all know, there are many oralce date types, such as

Oracle uses a cursor to query a string that combines the names of all fields in a specified data table. Application Scenario: refer to the Code for querying all field names of a data table on the Internet, and use a cursor to generate a list of field names separated by select commas (,) consisting of all field names an

If your experience in SQL is not rich enough and you have not solved many problems in SQL, read this chapter carefully, it helps you avoid a mistake that is likely to be made frequently! Create a test table first. Create Table # Table1 (ID int identity (1, 1) primary key, col1 int not null, col2 decimal (18, 1 )) Insert data Insert into # Table1 (col1, col2) Select 0, 0.1 Union all select 1, 1.1 Union all