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The last article we use string lookup method to achieve the ASP email email address verification, there may be more like the regular expression of friends, here also give the corresponding code.Method One
Copy Code code as follows:
Public Function Chkmail (ByVal Email)
Dim Rep,pmail:chkmail = True:set Rep = New RegExp
Rep.pattern = "([. a-za-z0
In the development of Java server-side code, we will encounter the external parameters of the validity of validation, and Hibernate-validator provides some common parameter check annotations, we can use.The hibernate-validator corresponding jar is introduced in 1.maven:2. Define the field to validate in the model (that is, the field cannot be empty and the maximum length is 14):
123456789101112
First, prefaceIn the background development process, the validation of parameters becomes an indispensable part of the development environment. For example, the parameter can not be null,email so must conform to the format of email, if manually make if judgment or write regular expression to judge the unintended development efficiency is too slow, in time, cost,
Java uses regular expressions for form validation tools class, can verify mailbox, mobile phone number, QQ number, etc.
Copy Code code as follows:
Package util;
Import Java.util.regex.Matcher;Import Java.util.regex.Pattern;
/*** Use regular expressions for form validation**/
public class Regexvalidateutil {Static Boolean flag = FALSE;static S
(String value) {Return match (V_unpositive_float,value);} /*** Verify URL* @param value to validate the string* @return If it is a string that conforms to the format, return */public static Boolean URL (String value) {Return match (V_url,value);} /*** Verify user registration. Matches a string consisting of a number, 26 letters, or underscores* @param value to validate the string* @return If it is a string that conforms to the format, return */public static Boolean UserName (String value) {Retu
The previous article simply wrote a regular expression of theoretical knowledge, this is the actual combat verificationFirst we write a URL validation class, of course, it can be another environment, here we have the Java environmentPackage Com.zyt.regex;Import Java.util.regex.Matcher;Import Java.util.regex.Pattern;URL validationpublic class Urlreg {public String str = NULL;Public String
); // associate the regular expression with the string to match the string.
2. Cut: The split method in the string class is used.
3. Replace: replaceall () in the string class ();
4. obtain:
1), first compile the regular expression into a regular object. The static method compile (RegEx) in pattern is used );
2) Get the matcher object through the pattern object.
Pattern is used to describe a regular expression and can be parsed.
The rule
Implementation ideas:
1. Use a java.net. url object to bind a webpage address on the network
2. Obtain an httpconnection object through the openconnection () method of the java.net. url object.
3. Use the getinputstream () method of the httpconnection object to obtain the input stream object inputstream of the network file.
4. read each row of data in the stream cyclically, and use the regular expression compiled by the pattern object to partition each row of characters to obtain the
Turn http://blog.csdn.net/marila4720/article/details/8728840Package URL;Import Java.util.regex.Pattern;Import Java.util.regex.Matcher;public class test1{public static void Main (String[]args) {String regex = "\ \[email protected]\\w+\\. (com\\.cn) |\\[email protected]\\w+\\. (COM|CN) ";/*\w representative [a-za-z0-9_], the reason is written \\w because \ has esca
"}; Onestring[] IDArray =NewString[18]; A intIntstrlen =idcard.length (); -String Idstr =Idcard; - intsum = 0; the - //Regular verify that the ID card format is correct -Pattern pattern =pattern.compile (regex); -Matcher Matcher =Pattern.matcher (idcard); + if(!matcher.matches ()) { - return false; + } A at //Verify that the ID number algorithm is legal - for(inti =
BufferedReader (New InputStreamReader (Conn.getinputstream ())); String Line=null; Matches the email's regular String regex= "[a-za-z0-9_-][emailprotected]\\w+\\. [A-z]+ (\\.[ a-z]+)? "; Use the compile () method of the pattern to generate the pattern object, pattern p=pattern.compile (regex); while ((Line=bufr.readline ())!=null) {Matcher
BufferedReader (New InputStreamReader (Conn.getinputstream ())); String Line=null; Matches the email's regular String regex= "[a-za-z0-9_-][emailprotected]\\w+\\. [A-z]+ (\\.[ a-z]+)? "; Use the compile () method of the pattern to generate the pattern object, pattern p=pattern.compile (regex); while ((Line=bufr.readline ())!=null) {Matcher
In the past, there was such a question in the written test. The content was similar to the question. I knew how to do it, but I couldn't write it in the White Paper. It was immediately rejected by the Technical Manager.
This is a Java class that I have time to write for simple verification of the email format. However, regular expressions are generally used for validati
Password Verification requirements:1) Password control can only enter letters, numbers, special symbols ([email protected]#$%^* () _+[]{}|\;: ' ",./2) length 6-16 digits, must include 2 kinds of letters, numbers, special symbols3) password cannot contain user name informationDetermine if the password contains a number: contains return 1, does not contain return 0int i = newpwd.matches (". *\\d+.*")? 1:0;Determine if the password contains letters: cont
successfully, returns aUserobjects →Regservlet (judging the returnedUseris empty, not emptyStartunder the Tools classSendemailthreadThread Class)→ Mail sent successfully to email click on the link →ActiveservletThe link now takes a parameterActive→Registerservice (Interface)Business Layer(Pass the activation code as a parameter to determine if the activation code exists.)→Registerserviceimp (Implementation Class)calledDAOmethod of layer interface →Re
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